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Use a proof by contraposition to show that if \(x+y \geq 2\) where \(x\) and \(y\) are real numbers, then \(x \geq 1\) or \(y \geq 1\)

Short Answer

Expert verified
Contrapositive proven: If \(x + y \geq 2\), then \(x \geq 1\) or \(y \geq 1\).

Step by step solution

01

Understand the Contrapositive

The contrapositive of the statement 'If P, then Q' is 'If not Q, then not P.' In this exercise, the original statement is 'If \(x + y \geq 2\), then \(x \geq 1\) or \(y \geq 1\).' So, the contrapositive would be 'If \(x < 1\) and \(y < 1\), then \(x + y < 2\).' Proving the contrapositive will also prove the original statement.
02

Assume the Negation

Assume \(x < 1\) and \(y < 1\). This is the negation of the conclusion (\(x \geq 1\) or \(y \geq 1\)).
03

Add the Assumptions

Combine the assumptions to form a new inequality: \(x + y < 1 + 1\). Simplifying this, we get \(x + y < 2\).
04

Conclude the Proof

Since we have shown that 'If \(x < 1\) and \(y < 1\), then \(x + y < 2\),' this is the contrapositive of the original statement. Therefore, the original statement 'If \(x + y \geq 2\), then \(x \geq 1\) or \(y \geq 1\)' is true.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Understanding Contrapositive Proofs
A proof by contraposition is a clever way to show that a statement is true. Rather than proving the actual statement directly, we prove its contrapositive. The contrapositive of a statement 'If P, then Q' is 'If not Q, then not P.'
In our exercise, the statement is 'If \(x + y \geq 2\), then \(x \geq 1\) or \(y \geq 1\).' The contrapositive changes this statement to 'If \(x < 1\) and \(y < 1\), then \(x + y < 2\).' By proving this altered statement, we indirectly prove the original statement.
This proof technique can be particularly useful when the contrapositive form is easier to handle. It transforms a problem into a potentially simpler one while maintaining logical equivalence.
Exploring Inequalities
Inequalities are mathematical expressions that show the relationship between two values where they are not necessarily equal. Inequalities use symbols like \(<\), \(>\), \(\leq\), and \(\geq\).
In our exercise, the key inequality is \(x + y \geq 2\). This means the sum of \(x\) and \(y\) is at least 2. Instead of working directly with this, we look at its contrapositive, which involves the inequality \(x + y < 2\), suggesting that the sum of \(x\) and \(y\) is less than 2 if both \(x\) and \(y\) are less than 1.
By manipulating inequalities in this way, we can turn complex logical statements into simpler forms to prove.
Logical Negation Basics
Logical negation is about reversing the truth value of a statement. If a statement is true, its negation is false, and vice versa. This concept is crucial in forming contrapositives.
Negating 'If \(x \geq 1\) or \(y \geq 1\)' gives us 'If \(x < 1\) and \(y < 1\),' which is the starting point for our contraposition proof.
Understanding how to properly negate statements helps in transforming the original problem into its contrapositive, making the proof process feasible.
Real Numbers in Proofs
Real numbers form the basis of many mathematical proofs and problems. Real numbers include all the numbers on the number line, encompassing both rational and irrational numbers.
In this exercise, both \(x\) and \(y\) are specified as real numbers. This means they can take any value within the infinite set of real numbers. The flexibility of real numbers allows us to assume \(x < 1\) and \(y < 1\) as part of our contraposition approach.
Working with real numbers ensures that our proof remains valid over a vast range of possible values, rather than just specific cases.

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