Chapter 3: Problem 14
Prove that there are no integer solutions to the equation \(x^{2}=4 y+3\).
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Chapter 3: Problem 14
Prove that there are no integer solutions to the equation \(x^{2}=4 y+3\).
These are the key concepts you need to understand to accurately answer the question.
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Prove: \(x=y\) if and only if \(x y=\frac{(x+y)^{2}}{4}\). Note, you will need to prove two "directions" here: the "if" and the "only if" part.
Suppose you have a collection of 5 -cent stamps and 8 -cent stamps. We saw earlier that it is possible to make any amount of postage greater than 27 cents using combinations of both these types of stamps. But, let's ask some other questions: (a) Prove that if you only use an even number of both types of stamps, the amount of postage you make must be even. (b) Suppose you made an even amount of postage. Prove that you used an even number of at least one of the types of stamps. (c) Suppose you made exactly 72 cents of postage. Prove that you used at least 6 of one type of stamp.
Consider the statement "for all integers \(a\) and \(b\), if \(a+b\) is even, then \(a\) and \(b\) are even" (a) Write the contrapositive of the statement. (b) Write the converse of the statement. (c) Write the negation of the statement. (d) Is the original statement true or false? Prove your answer. (e) Is the contrapositive of the original statement true or false? Prove your answer. (f) Is the converse of the original statement true or false? Prove your answer. (g) Is the negation of the original statement true or false? Prove your answer.
Consider the statement: for all integers \(n,\) if \(n\) is odd, then \(7 n\) is odd. (a) Prove the statement. What sort of proof are you using? (b) Prove the converse. What sort of proof are you using?
Suppose \(P_{1}, P_{2}, \ldots, P_{n}\) and \(Q\) are (possibly molecular) propositional statements. Suppose further that $$\begin{array}{cl} & P_{1} \\\& P_{2} \\\& \vdots \\\& P_{n} \\\\\hline \therefore & Q\end{array}$$ is a valid deduction rule. Prove that the statement $$\left(P_{1} \wedge P_{2} \wedge \cdots \wedge P_{n}\right) \rightarrow Q$$ is a tautology.
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