/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 1 Consider the sequence \(5,9,13,1... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

Consider the sequence \(5,9,13,17,21, \ldots\) with \(a_{1}=5\) (a) Give a recursive definition for the sequence. (b) Give a closed formula for the \(n\) th term of the sequence. (c) Is 2013 a term in the sequence? Explain. (d) How many terms does the sequence \(5,9,13,17,21, \ldots, 533\) have? (e) Find the sum: \(5+9+13+17+21+\cdots+533\). Show your work. (f) Use what you found above to find \(b_{n},\) the \(n^{t h}\) term of \(1,6,15,28,45, \ldots,\) where \(b_{0}=1\)

Short Answer

Expert verified
a) Recursive definition: \(a_n = a_{n-1} + 4\), with \(a_1 = 5\). b) Closed formula: \(a_n = 4n + 1\). c) Yes, 2013 is a term. d) The sequence has 133 terms. e) The sum is \(S_{133} = 35,881\). f) The nth term for the second sequence is \(b_n = 5n - 3\).

Step by step solution

01

Determine the Common Difference

Identify the common difference by subtracting any term in the sequence from the term that follows it. For instance, the difference between the second term (9) and the first term (5) is 4.
02

Formulate the Recursive Definition

Given that the first term is 5 and the common difference is 4, the recursive definition is given by: For n > 1, the nth term is the (n-1)th term plus 4, symbolically, \(a_n = a_{n-1} + 4\), with \(a_1 = 5\).
03

Develop the Closed Formula

The closed formula of an arithmetic sequence is given by \(a_n = a_1 + (n - 1)d\), where \(d\) is the common difference. Substituting the values, we have \(a_n = 5 + (n - 1) \times 4 = 4n + 1\).
04

Check if 2013 is a Term in the Sequence

Plug the value 2013 into the formula to solve for n: \(2013 = 4n + 1\). Subtract 1 from both sides to get \(2012 = 4n\), and then divide by 4 to find \(n\). If \(n\) is a positive integer, 2013 is a term in the sequence.
05

Determine the Number of Terms up to 533

Using the closed formula, solve for n when \(a_n = 533\). From the equation \(533 = 4n + 1\), solving for n gives \(n = 133\). This means there are 133 terms in the sequence.
06

Calculate the Sum of the Sequence

To find the sum of the arithmetic sequence, use the formula \(S_n = \frac{n}{2} (a_1 + a_n)\) where \(n\) is the number of terms. Here, \(S_{133} = \frac{133}{2} (5 + 533)\). Calculate the sum using these values.
07

Relate the Sequences to Find the nth Term of the Second

Observe that the second sequence is related to the square of the term number, i.e., \(b_n = n^2 + 1\). Since the nth term of the original sequence is \(4n + 1\), we need to find a correlation between the two sequences. Notice that \(b_n = a_{n-1} + n = 4(n - 1) + 1 + n = 5n - 3\) where \(b_0 = a_{-1} + 1 = 1\).

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Recursive Definition
Understanding a sequence's pattern is crucial in mathematics, and a recursive definition simplifies this by expressing each term using its predecessor(s). For example, in the given sequence (5, 9, 13, 17, 21, …), we determine that each term increases by 4, a consistent step known as the common difference. To formulate this into a recursive definition, we use the formula \( a_n = a_{n-1} + 4 \) for all \( n > 1 \), where \( a_1 = 5 \). This approach spells out the rule for obtaining any term directly from the one before it, offering a straightforward method for advancing through the sequence.
As a content creator aimed at clarity, think of the recursive definition as a clear set of instructions for building a chain, where every link connects to the last, following a simple and repeatable pattern.
Closed Formula
While recursive definitions are great step-by-step guides, a closed formula lets you jump straight to any term in the sequence without computing all the preceding terms. To determine the closed formula for our example, you begin with the first term, \( a_1 = 5 \), add the product of the common difference, 4, and \( n - 1 \), the number of steps from the first term. This gives us the magic key, the formula \( a_n = 4n + 1 \), allowing direct calculation of any term's value with just its position in the sequence. From a learning standpoint, grasping the concept of the closed formula is an intellectual shortcut, enabling quick access to information and simplifying problem-solving tasks.
Sequence Sum
The sum of an arithmetic sequence, also known as a sequence sum, is the total value obtained when all terms in the sequence are added together. For sequences with a clear starting and ending point, we have a neat formula to calculate this sum without laboriously adding each term individually. Given our sequence starting at 5 and ending at 533 with 133 terms, we apply the series sum formula \( S_n = \frac{n}{2} (a_1 + a_n) \) to find \( S_{133} = \frac{133}{2} (5 + 533) \), streamlining the summing process. This concept is a cornerstone in understanding arithmetic progressions, as it reflects the cumulative impact of the sequence's pattern.
Arithmetic Series
An arithmetic series is the summing-up of terms in an arithmetic sequence. It is the practical application of the sequence sum concept to real-life problems. For example, if you wanted to know how many handshakes would occur in a room where each person shook hands once with every other person, you could find the answer by summing an arithmetic sequence. Learning to compute an arithmetic series is akin to learning to quickly tabulate the grand total of equally spaced items—a powerful tool in both academic and daily problem-solving scenarios. To bring it into a real-world context, imagine calculating the total cost of items on sale where the discount increases with each additional item; an arithmetic series simplifies this potentially complex calculation.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

Suppose \(f_{1}, f_{2}, \ldots, f_{n}\) are differentiable functions. Use mathematical induction to prove the generalized product rule: $$ \left(f_{1} f_{2} f_{3} \cdots f_{n}\right)^{\prime}=f_{1}^{\prime} f_{2} f_{3} \cdots f_{n}+f_{1} f_{2}^{\prime} f_{3} \cdots f_{n}+f_{1} f_{2} f_{3}^{\prime} \cdots f_{n}+\cdots+f_{1} f_{2} f_{3} \cdots f_{n}^{\prime} $$ You may assume the product rule for two functions is true.

Suppose the closed formula for a particular sequence is a degree 3 polynomial. What can you say about the closed formula for: (a) The sequence of partial sums. (b) The sequence of second differences.

Zombie Euler and Zombie Cauchy, two famous zombie mathematicians, have just signed up for Twitter accounts. After one day, Zombie Cauchy has more followers than Zombie Euler. Each day after that, the number of new followers of Zombie Cauchy is exactly the same as the number of new followers of Zombie Euler (and neither lose any followers). Explain how a proof by mathematical induction can show that on every day after the first day, Zombie Cauchy will have more followers than Zombie Euler. That is, explain what the base case and inductive case are, and why they together prove that Zombie Cauchy will have more followers on the 4 th day.

Show that \(a_{n}=3 \cdot 2^{n}+7 \cdot 5^{n}\) is a solution to the recurrence relation \(a_{n}=7 a_{n-1}-10 a_{n-2} .\) What would the initial conditions need to be for this to be the closed formula for the sequence?

Prove that \(7^{n}-1\) is a multiple of 6 for all \(n \in \mathbb{N}\).

See all solutions

Recommended explanations on Math Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.