/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 9 Solve the three counting problem... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

Solve the three counting problems below. Then say why it makes sense that they all have the same answer. That is, say how you can interpret them as each other. (a) How many ways are there to distribute 8 cookies to 3 kids? (b) How many solutions in non-negative integers are there to \(x+\) \(y+z=8 ?\) (c) How many different packs of 8 crayons can you make using crayons that come in red, blue and yellow?

Short Answer

Expert verified
All three problems result in 45 ways/solutions/packs because they all involve distributing 8 identical items into 3 distinct categories, hence using the combination with repetition formula, we get \(C(10, 2) = 45\).

Step by step solution

01

Solving Problem (a)

In problem (a), we assume the cookies are indistinguishable and the kids are distinguishable. This is a problem of distributing 'n' indistinguishable items to 'r' distinguishable boxes, which can be calculated by the formula \(C(n + r - 1, r - 1)\), where \(n\) is the number of items and \(r\) is the number of boxes. We substitute \(n=8\) and \(r=3\) to get \(C(8 + 3 - 1, 3 - 1) = C(10, 2)\).
02

Solving Problem (b)

For problem (b) the equation can be seen as distributing 8 units to 3 variables \(x, y\), and \(z\), where each variable represents one type of crayon and the units are the crayons. This is also a problem of combination with repetition, and can be solved using the same formula \(C(n + r - 1, r - 1)\). Here, \(n=8\) which is equivalent to the number of crayons (units) and \(r=3\) which is equivalent to the number of variables (categories of crayons). Therefore, we have \(C(8 + 3 - 1, 3 - 1) = C(10, 2)\) as well.
03

Solving Problem (c)

In problem (c), we want to create packs of 8 crayons from 3 colors. This is like having 8 positions in a pack and choosing what color goes into each, with repetition allowed. This is another example of combination with repetition and is solved similarly using the formula \(C(n + r - 1, r - 1)\), where \(n=8\) and \(r=3\). So, the solution will again be \(C(10, 2)\).
04

Calculate the Combinations

To calculate \(C(10, 2)\) we use the combination formula \(C(n, k) = \frac{n!}{k!(n-k)!}\) where \(n!\) represents the factorial of \(n\), \(k!\) the factorial of \(k\), and \(n-k\) the factorial of \(n-k\). Substituting \(n=10\) and \(k=2\), we calculate \(C(10, 2) = \frac{10!}{2!*(10-2)!} = \frac{10*9}{2*1} = 45\).
05

Explain Why the Answers are the Same

The numbers are the same for all three problems because each problem can be interpreted as distributing 8 identical items among 3 categories. In (a), the categories are the kids; in (b), they're the places for units in the equation; and in (c), they are the colors of crayons.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Distribution of Indistinguishable Objects
When faced with the task of distributing indistinguishable objects among distinct groups, we delve into a classic combinatorial concept. Imagine having a set of identical cookies that need to be shared among different children. The question of interest is: in how many different ways can this distribution be carried out?

In mathematical terms, this scenario is an application of combinations with repetition. The crux of this concept is that the order in which the cookies are given out doesn't matter since they are all alike. Therefore, if three kids receive 2, 3, and 3 cookies respectively, it's considered the same distribution as another where the allocation of cookies is 3, 2, and 3.

To calculate the number of ways to distribute 'n' indistinguishable objects to 'r' distinguishable recipients, combinatorics offers a straightforward formula: \(C(n + r - 1, r - 1)\). It encapsulates the idea that we are selecting 'r - 1' dividers from a total of 'n + r - 1' slots (objects plus dividers).
Combinations with Repetition
The concept of combinations with repetition is a staple in combinatorics, offering an elegant way to solve problems regarding selections where individual items can be chosen multiple times. It's equivalent to asking how many different combinations can be formed from a set of items when each selected item can be picked again for future selections.

For example, when creating different packs of crayons from a limited palette, one might use several crayons of the same color in a pack. To find out the total different packs possible, we employ the formula \(C(n + r - 1, r - 1)\), which symbolizes the choice of 'r - 1' partitioning elements from a pool of 'n' items being organized into 'r' categories.

<h4>Remembering the Cookies</h4>Returning to our cookie distribution problem, notice how it mirrors the selection of crayons in packs. Both scenarios allow for repetition of elements (cookies or crayon colors), fitting within the framework of combinations with repetition. Importantly, the repetitive selection is what sets these problems apart from combinations without repetition, often leading to higher counts of possible distributions or combinations.
Solutions to Linear Equations in Non-negative Integers
The exploration of solutions to linear equations in non-negative integers is another fascinating application of combinatorics. When we're given an equation like \(x + y + z = 8\), where \(x\), \(y\), and \(z\) must be non-negative integers, we're essentially searching for the number of ways to split the number 8 into three parts.

This problem type is akin to distributing indistinguishable objects (units of the number 8) into distinguishable categories (the individual variables \(x\), \(y\), and \(z\)). The connection to our previous discussions is immediate: we are once more relying on combinations with repetition, given that each variable can assume any allowed value multiple times.

Using our versatile formula \(C(n + r - 1, r - 1)\), we see that the equation \(x + y + z = 8\) is not just an algebraic curiosity but a combinatorial challenge, illustrating the deep interplay between seemingly distinct fields of mathematics. The non-negative integers requirement ensures that all solutions are valid in real-world scenarios, such as distributing items, and aligns with the conditions imposed in our cookie and crayon examples.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

How many different seating arrangements are possible for King Arthur and his 9 knights around their round table?

Gridtown USA, besides having excellent donut shops, is known for its precisely laid out grid of streets and avenues. Streets run east-west, and avenues north-south, for the entire stretch of the town, never curving and never interrupted by parks or schools or the like. Suppose you live on the corner of \(3 \mathrm{rd}\) and \(3 \mathrm{rd}\) and work on the corner of 12 th and 12 th. Thus you must travel 18 blocks to get to work as quickly as possible. (a) How many different routes can you take to work, assuming you want to get there as quickly as possible? Explain. (b) Now suppose you want to stop and get a donut on the way to work, from your favorite donut shop on the corner of 10 th ave and 8 th st. How many routes to work, stopping at the donut shop, can you take (again, ensuring the shortest possible route)? Explain. (c) Disaster Strikes Gridtown: there is a pothole on 4 th ave between 5 th st and 6 th st. How many routes to work can you take avoiding that unsightly (and dangerous) stretch of road? Explain. (d) The pothole has been repaired (phew) and a new donut shop has opened on the corner of 4 th ave and 5 th st. How many routes to work drive by one or the other (or both) donut shops? Hint: the donut shops serve PIE.

Recall, by 8-bit strings, we mean strings of binary digits, of length 8 . (a) How many 8-bit strings are there total? (b) How many 8-bit strings have weight \(5 ?\) (c) How many subsets of the set \(\\{a, b, c, d, e, f, g, h\\}\) contain exactly 5 elements? (d) Explain why your answers to parts (b) and (c) are the same. Why are these questions equivalent?

Using the digits 2 through 8 , find the number of different 5 -digit numbers such that: (a) Digits can be used more than once. (b) Digits cannot be repeated, but can come in any order. (c) Digits cannot be repeated and must be written in increasing order. (d) Which of the above counting questions is a combination and which is a permutation? Explain why this makes sense.

Your wardrobe consists of 5 shirts, 3 pairs of pants, and 17 bow ties. bow ties How many different outfits can you make?

See all solutions

Recommended explanations on Math Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.