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What is the coefficient of \(x^{10}\) in the expansion of \((x+1)^{13}+x^{2}(x+1)^{17} ?\)

Short Answer

Expert verified
The coefficient of \(x^{10}\) is \(286 + 19448 = 19734\).

Step by step solution

01

Examine the First Term

The binomial expansion of \((x+1)^{13}\) includes terms of the form \(\binom{13}{k}x^{13-k}1^k\). The coefficient of \(x^{10}\) occurs when \(k=3\) which gives us \(\binom{13}{3}\).
02

Calculate the Coefficient for the First Term

Using the combination formula \(\binom{n}{r}=\frac{n!}{r!(n-r)!}\), calculate \(\binom{13}{3}=\frac{13!}{3!10!} = 286\). So the coefficient for \(x^{10}\) in the first term is 286.
03

Examine the Second Term

The binomial expansion of \(x^{2}(x+1)^{17}\) includes terms of the form \(x^{2}\binom{17}{k}x^{17-k}1^k\). The coefficient of \(x^{10}\) will occur when \(k=7\) resulting in \(x^{2}\binom{17}{7}x^{10}\). Thus, we need to calculate \(\binom{17}{7}\).
04

Calculate the Coefficient for the Second Term

Calculate \(\binom{17}{7}=\frac{17!}{7!10!} = 19448\). So the coefficient for \(x^{10}\) in the second term after accounting for \(x^{2}\) is \(19448 \times 1 = 19448\).
05

Sum the Coefficients

The total coefficient for \(x^{10}\) is the sum of the coefficients from both terms. So, add the coefficient from the first term (286) to the coefficient from the second term (19448) to get the final answer.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Binomial Expansion
The binomial expansion refers to expressing a binomial expression raised to a certain power as a series of terms involving coefficients and powers of the variables. It is based on the pattern described by the binomial theorem, which provides a formula for expanding expressions of the form \( (a + b)^n \). For example, expanding \( (x+1)^{13} \) involves computing terms starting with \( x^{13} \) and ending with \( 1^{13} \) with corresponding coefficients. These coefficients can be found using combinatorial numbers, commonly referred to as binomial coefficients, which express the number of ways to choose a subset of items from a larger set, irrespective of the order.

When looking for a specific term, like the coefficient of \( x^{10} \) in an expansion, we can use the fact that the exponent of \( x \) in a term and its corresponding coefficient are connected via the binomial theorem. The index \( k \) in the binomial coefficient \( \binom{n}{k} \) corresponds to how many times \( 1 \) is multiplied in each term of the expansion, with the exponent of \( x \) being \( n - k \) in the term. It's important to grasp that these coefficients are symmetrical in a binomial expansion; the \( k \)th and \( (n-k) \)th coefficients are always equal.
Combinatorics
Combinatorics is the branch of mathematics dealing with counting, arranging, and finding patterns in sets, especially the set of all possible combinations or permutations of a collection of things. It underpins the binomial coefficients found in the expansion of \( (a+b)^n \), which signify the number of ways we can choose \( k \) elements from a set of \( n \) without regard to the order. This is often denoted as \( \binom{n}{k} \) and is pronounced 'n choose k'.

In our exercise, we use combinatorics to find the coefficients for the terms in the binomial expansion. By recognizing the combinatorial nature of the coefficients, we can calculate them directly through the formula \( \binom{n}{k} = \frac{n!}{k!(n-k)!} \) without having to expand the entire binomial expression. This not only simplifies finding the coefficient for a term in the expansion but also helps to understand the different possible combinations that contribute to a term in the binomial expansion.
Factorial Notation
Factorial notation is fundamental for calculating combinations and understanding the binomial theorem. It is represented by an exclamation point \( ! \) following a number and signifies the product of all positive integers from that number down to 1. For example, \( 5! = 5 \times 4 \times 3 \times 2 \times 1 = 120 \). Factorials grow very rapidly with increasing numbers, which plays a crucial role in combinatorics and hence in the coefficients of binomial expansion.

In the binomial coefficient \( \binom{n}{k} \) formula, factorials are used to calculate the number of distinct ways \( k \) items can be chosen from a set of \( n \) items. To get the coefficient for a specific term in our example, we used factorial notation to compute \( \binom{13}{3} \) and \( \binom{17}{7} \) for the corresponding terms in the binomial expansions. Remember that factorial notation is also practical since the factorials in the numerator and denominator can often simplify, making calculations more manageable.

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