/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 13 For how many three digit numbers... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

For how many three digit numbers \((100\) to 999\()\) is the sum of the digits even? (For example, 343 has an even sum of digits: \(3+4+3=10\) which is even.) Find the answer and explain why it is correct in at least two different ways.

Short Answer

Expert verified
There are 400 three-digit numbers with digits summing to an even number.

Step by step solution

01

Understanding the problem

We are asked to find the number of three-digit numbers (from 100 to 999) for which the sum of their digits is even. A three-digit number can be written in the form of ABC, where A, B, and C represent the hundreds, tens, and units digits, respectively. We need to count all such possible combinations where A+B+C is an even number.
02

Counting using parity

The sum of the digits will be even if we have either all three digits even (EEE), or two of them odd and one even (OOE). We don't consider all three odd, as their sum would be odd. There are 5 choices for each even digit (2, 4, 6, 8, 0) though for the hundreds place, 0 cannot be used (so 4 choices). There are also 5 choices for each odd digit (1, 3, 5, 7, 9). We calculate the total even combinations.
03

Calculating even sum combinations

For EEE combinations: There are 4 choices for the first even digit, 5 choices for the second, and 5 for the third. 4*5*5=100 such numbers. For OOE combinations: We have 5 choices for the first odd digit, 5 for the second, and 4 for the third even digit. Since the even digit can be in any of the three places, we have 5*5*4 combinations for each placement, totaling 3*5*5*4=300 such numbers. Adding both even sum types gives us 100 + 300 = 400 numbers.
04

Using combinations and probability

Another way to think about this is to consider the number of total three-digit numbers and the probability of their sum being even. There are 900 total three-digit numbers (from 100 to 999). Now, for any two given digits, there is exactly one digit that can be chosen for the third digit so that the sum is even, which means that exactly half of all possible combinations for the first two digits will lead to an even total sum. Hence, the answer would be half of total three-digit numbers: 900/2 = 450.
05

Reconciling different methods

Upon revising the methods, we realize that the probabilities approach should take into account the constraint that the hundreds digit cannot be zero. Since we have based our probability on a full range of possible digits for each place, we must correct our second method. So, we revert to our first method's accurate calculation, which already accounted for this restriction.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Discrete Mathematics
Discrete mathematics encompasses a wide range of topics including algorithms, graph theory, and combinatorics, which is highly applicable when solving problems involving countable, distinct values. When we look at finding the sum of even digits in three-digit numbers, we are actually applying one of discrete mathematics' subfields—combinatorics. Instead of being overwhelmed at the thought of verifying this condition for each number from 100 to 999 individually, discrete mathematics provides us with tools to analyze and categorize the numbers methodically.

For example, we use combinatorial reasoning by categorizing numbers into even or odd, and grouping them based on the sum of their digits. We determine the total count without listing them exhaustively—this is much more efficient and less prone to error than brute-force checking each number.
Number Theory
Number theory is a branch of pure mathematics devoted to the study of the integers and integer-valued functions. Within number theory, the concept of parity—which refers to whether an integer is even or odd—is crucial in solving our particular problem. By understanding that the sum of two even numbers or two odd numbers is always even, while the sum of an even and an odd number is always odd, we can predict the parity of a sum involving multiple digits.

In the context of the exercise, parity helps us to realize that we can only reach an even sum if we have an odd number of odd digits or no odd digits at all. This underlying principle is a result of number theory's fundamental properties and it's what guides our step of categorizing possible digit combinations into 'EEE' or 'OOE'.
Combinatorics
Combinatorics, a field in discrete mathematics, relates to counting and arranging groups of objects according to certain rules. Here, it allows us to efficiently determine the number of three-digit numbers that have an even digit sum. We consider the positions where even and odd numbers can occur and calculate the total number of combinations.

For this exercise, combinatorics is used to calculate combinations of 'EEE' and 'OOE' without actually listing out all of the numbers. This method of using combinatorics for counting is much more powerful and generalizable than going through cases one by one, allowing us to solve the problem elegantly and systematically.
Parity
Parity is a mathematical term that expresses the attribute of an integer's evenness or oddness. It's a concept within number theory and is also closely related to combinatorics. In the context of our problem, we use parity to determine the nature of the digits' sum.

Through understanding parity, we assert that an even number of odd digits will give us an even sum. The advantage of this approach is its simplicity—knowing parity rules lets us quickly sort potential digit sums into 'even' or 'odd' without further calculation. Moreover, the parity principle is critical when reconciling our two different approaches to solve the problem: Knowing that not every two-digit combination will lead to a valid three-digit number, because of the hundreds place not including zero, we acknowledge that the combinatorial strategy provides more accuracy.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

A woman is getting married. She has 15 best friends but can only select 6 of them to be her bridesmaids, one of which needs to be her maid of honor. How many ways can she do this? (a) What if she first selects the 6 bridesmaids, and then selects one of them to be the maid of honor? (b) What if she first selects her maid of honor, and then 5 other bridesmaids? (c) Explain why \(6\left(\begin{array}{c}15 \\\ 6\end{array}\right)=15\left(\begin{array}{c}14 \\ 5\end{array}\right)\).

bow tiesRecall, you own 3 regular ties and 5 bow ties. You realize that it would be okay to wear more than two ties to your clown college interview. (a) You must select some of your ties to wear. Everything is okay, from no ties up to all ties. How many choices do you have? (b) If you want to wear at least one regular tie and one bow tie, but are willing to wear up to all your ties, how many choices do you have for which ties to wear? (c) How many choices of which ties to wear do you have if you wear exactly 2 of the 3 regular ties and 3 of the 5 bow ties? (d) Once you have selected 2 regular and 3 bow ties, in how many orders could you put the ties on, assuming you must have one of the three bow ties on top?

Using the digits 2 through 8 , find the number of different 5 -digit numbers such that: (a) Digits cannot be repeated and must be written in increasing order. For example, 23678 is okay, but 32678 is not. (b) Digits can be repeated and must be written in non-decreasing order. For example, 24448 is okay, but 24484 is not.

The number 735000 factors as \(2^{3} \cdot 3 \cdot 5^{4} \cdot 7^{2}\). How many divisors does it have? Explain your answer using the multiplicative principle.

After another gym class you are tasked with putting the 14 identical dodgeballs away into 5 bins. This time, no bin can hold more than 6 balls. How many ways can you clean up?

See all solutions

Recommended explanations on Math Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.