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Find a set of smallest possible size that has both \\{1,2,3,4,5\\} and \\{2,4,6,8,10\\} as subsets.

Short Answer

Expert verified
The smallest set containing both \{1,2,3,4,5\} and \{2,4,6,8,10\} is \{1, 2, 3, 4, 5, 6, 8, 10\}.

Step by step solution

01

Identify Common Elements

First, identify the elements that are common to both sets. The sets \(\{1,2,3,4,5\}\) and \(\{2,4,6,8,10\}\) have \(2\) and \(4\) in common.
02

Combine Unique Elements

Next, list all the unique elements from both sets without repeating common elements. This gives \(1, 2, 3, 4, 5, 6, 8, 10\).
03

Create the Smallest Set

Finally, create a set that includes all the listed elements. The smallest set that contains both \(\{1,2,3,4,5\}\) and \(\{2,4,6,8,10\}\) as subsets is \(\{1, 2, 3, 4, 5, 6, 8, 10\}\).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Common Elements in Sets
Understanding common elements in sets is a fundamental aspect of set theory. When we refer to 'common elements', we are talking about items that are present in all of the sets being considered. For example, let's consider two sets, Set A: \(\{1, 2, 3, 4, 5\}\) and Set B: \(\{2, 4, 6, 8, 10\}\). To find the common elements, we look for numbers that are present in both Set A and Set B. As clearly shown in our step-by-step solution, the numbers that are shared by both sets are \(2\) and \(4\).

Identifying the common elements is important because it allows us to understand the relationship between different sets and can also be used to simplify the process of combining sets, which we will discuss in the following sections. When you're faced with a similar problem, always start by listing down those elements that both sets share, as this will form a crucial part of the final set.
Combining Unique Set Elements
Once you have identified the common elements in sets, the next step is to combine unique set elements to create a new set. This procedure ensures we include each element from the original sets without repetition, thereby maintaining the distinct nature of set elements. Continuing with our example, after extracting the common elements \(2\) and \(4\), we then list all the unique elements from Set A and Set B.

To do this efficiently, you can create a single list that includes both sets and then eliminate any duplicates. This would leave us with \(1, 2, 3, 4, 5, 6, 8, 10\). By following this process, we ensure that the resultant set is a true representation of all the elements from both sets combined, but without any redundancy. When combining sets, always remember to keep only one instance of each element, no matter how many times it's repeated across the sets.
Subset Relation
The concept of a subset is a bit like the idea of a 'contained group'. In set theory, a set X is considered a subset of another set Y if all elements of X are also elements of Y. This doesn’t mean that sets X and Y are equal, as Y may contain additional elements. An example from our step-by-step solution demonstrates this: Set A can be written as \(\{1, 2, 3, 4, 5\}\), and our final combined set is \(\{1, 2, 3, 4, 5, 6, 8, 10\}\). It's evident that all elements of Set A are included in the combined set, making it a subset.

To formally affirm this relationship, we express that A is a subset of the combined set, as is Set B. This idea is central when creating sets that are inclusive of other sets, or when we aim to find the smallest set that contains several subsets, such as in the exercise we solved. In summary, the subset concept is about ensuring one set entirely fits within another, likened to a box within a bigger box scenario, where the small box is nestled neatly inside without anything left outside.

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Most popular questions from this chapter

For a given predicate \(P(x)\), you might believe that the statements \(\forall x P(x)\) or \(\exists x P(x)\) are either true or false. How would you decide if you were correct in each case? You have four choices: you could give an example of an element \(n\) in the domain for which \(P(n)\) is true or for which \(P(n)\) if false, or you could argue that no matter what \(n\) is, \(P(n)\) is true or is false. (a) What would you need to do to prove \(\forall x P(x)\) is true? (b) What would you need to do to prove \(\forall x P(x)\) is false? (c) What would you need to do to prove \(\exists x P(x)\) is true? (d) What would you need to do to prove \(\exists x P(x)\) is false?

Consider the function \(f: \mathbb{N} \rightarrow \mathbb{N}\) that gives the number of handshakes that take place in a room of \(n\) people assuming everyone shakes hands with everyone else. Give a recursive definition for this function.

The following functions all have domain \\{1,2,3,4,5\\} and codomain \(\\{1,2,3\\} .\) For each, determine whether it is (only) injective, (only) surjective, bijective, or neither injective nor surjective. (a) \(f=\left(\begin{array}{lllll}1 & 2 & 3 & 4 & 5 \\ 1 & 2 & 1 & 2 & 1\end{array}\right)\). (b) \(f=\left(\begin{array}{lllll}1 & 2 & 3 & 4 & 5 \\ 1 & 2 & 3 & 1 & 2\end{array}\right)\). (c) \(f(x)=\left\\{\begin{array}{ll}x & \text { if } x \leq 3 \\ x-3 & \text { if } x>3\end{array}\right.\)

Translate into symbols. Use \(E(x)\) for \({ }^{\prime \prime} x\) is even \(^{\prime \prime}\) and \(O(x)\) for \({ }^{\prime \prime} x\) is odd." (a) No number is both even and odd. (b) One more than any even number is an odd number. (c) There is prime number that is even. (d) Between any two numbers there is a third number. (e) There is no number between a number and one more than that number.

Let \(A=\\{1,2, \ldots, 10\\} .\) How many subsets of \(A\) contain exactly one element (i.e., how many singleton subsets are there)? singleton set How many doubleton subsets (containing exactly two elements) are there? doubleton set.

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