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91Ó°ÊÓ

Represent the expression as a binary tree and write the prefix and postfix forms of the expression. $$ (A * B+C * D)-(A / B-(D+E)) $$

Short Answer

Expert verified
The prefix expression is -+*AB*CD-/AB+DE and the postfix expression is AB*CD*+AB/D+E--.

Step by step solution

01

Expression Tree Creation

Creating binary tree for given expression. The expression should be inserted initially into the binary tree according to BODMA's rule (Brackets, Orders, Division and Multiplication, and Addition and Subtraction).
02

Prefix Expression

For the prefix expression, apply the Depth-First-Search (DFS) by visiting the root, left and right nodes. For the given expression, it becomes: -+*AB*CD-/AB+DE.
03

Postfix Expression

Postfix expression is obtained by applying the DFS rule by visiting the left node, right node, and then the root. For the given expression, it results in: AB*CD*+AB/D+E--.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Prefix Notation
Prefix notation, also known as Polish notation, is a way of writing mathematical expressions where the operator comes before the operands. It has a straightforward advantage: it eliminates the need for parentheses to denote the order of operations. This is due to the fact that the position of the operator in relation to the operands always gives an unambiguous expression.
Consider the expression \((A * B + C * D) - (A / B - (D + E))\). Representing this in prefix notation requires a systematic approach. We traverse the binary tree starting from the root node, then proceed to visit the left subtree, and finally the right subtree. This order is known as "preorder traversal".

The prefix form of the expression is -+*AB*CD-/AB+DE. Here’s a breakdown of how this representation is formed:
  • The subtraction operation (-) is the outermost operation performed last in normal arithmetic, hence it appears first.
  • Each subsequent operator appears before its operands, illustrating their relationships clearly and unambiguously.
  • This method of writing expressions ensures calculations proceed strictly in the order specified by the expression's inherent logic.
Postfix Notation
Postfix notation, sometimes referred to as Reverse Polish Notation, places the operator after the operands. This notation is beneficial because it also eliminates the need for parentheses and naturally aligns with certain computing processes, like stack-based evaluations.
For the expression \((A * B + C * D) - (A / B - (D + E))\), converting to postfix notation involves visiting the left subtree first, then the right subtree, and finally the root node of the binary tree. This is known as "postorder traversal".

The postfix expression we derive is AB*CD*+AB/D+E--. Let’s take a closer look at how this is formed:
  • Each operation is completed before moving on to the next, which closely resembles the natural order of execution in calculations.
  • Operators appear only after their operands, reflecting a completed subexpression which fits well with stack operations used in computing.
  • This notation streamlines the process for evaluators, who can compute results more efficiently without backtracking to check previously encountered symbols.
Order of Operations
The order of operations is a set of rules that dictate the sequence in which operations should be performed to accurately evaluate mathematical expressions. These rules are commonly remembered by the acronym BODMAS (Brackets, Orders, Division and Multiplication, Addition and Subtraction) in some cultures, or PEMDAS (Parentheses, Exponents, Multiplication and Division, Addition and Subtraction) in others.
Understanding these rules is crucial because they provide the foundation for breaking down complex expressions into simpler parts to ensure accurate computation. Here's a quick rundown on how to handle these operations:
  • Brackets/Parentheses: Any part of the expression enclosed in brackets should be evaluated first.
  • Orders/Exponents: Next, resolve any powers or roots.
  • Division and Multiplication: These operations have the same precedence level and are processed from left to right.
  • Addition and Subtraction: These are the last operations you perform, again going from left to right.
By applying these principles, the given expression can be broken down efficiently and represented both in prefix and postfix notations. It ensures that no steps are skipped and the original analytical hierarchy of the expression is preserved throughout the conversion process.

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Most popular questions from this chapter

Refer to the following situation. Suppose that we have stamps of various denominations and that we want to choose the minimum number of stamps to make a given amount of postage. Consider a greedy algorithm that selects stamps by choosing as many of the largest denomination as possible, then as many of the second-largest denomination as possible, and so on. Show that if the available denominations are \(1,8,\) and 10 cents, the algorithm does not always produce the fewest number of stamps to make a given amount of postage.

Refer to tournament sort. Tournament Sort. We are given a sequence \(s_{1}, \ldots, s_{2^{k}}\) to sort in nondecreasing order. We will build a binary tree with terminal vertices labeled \(s_{1}, \ldots, s_{2^{k}} .\) An example is shown. Working left to right, create a parent for each pair and label it with the maximum of the children. Continue in this way until you reach the root. At this point, the largest value, \(m\), has been found. To find the second-largest value, first pick a value vless than all the items in the sequence. Replace the terminal vertex w containing \(m\) with \(v\). Relabel the vertices by following the path from w to the root, as shown. At this point, the secondlargest value is found. Continue until the sequence is ordered. Why is the name "tournament" appropriate?

Write an algorithm based on breadth-first search that finds the minimum length of each path in an unweighted graph from a fixed vertex \(y\) to all other vertices.

Evaluate each vertex in each game tree. The values of the terminal vertices are given.

Refer to the following situation. Suppose that we have stamps of various denominations and that we want to choose the minimum number of stamps to make a given amount of postage. Consider a greedy algorithm that selects stamps by choosing as many of the largest denomination as possible, then as many of the second-largest denomination as possible, and so on. Find positive integers \(a_{1}\) and \(a_{2}\) such that \(a_{1}>2 a_{2}>1, a_{2}\) does not divide \(a_{1},\) and the algorithm, with available denominations \(1, a_{1}, a_{2},\) does not always produce the fewest number of stamps to make a given amount of postage.

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