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91Ó°ÊÓ

Suppose that a coin is flipped and a die is rolled. List the members of the sample space.

Short Answer

Expert verified
The members of the sample space are : \[ (H,1), (H,2), (H,3), (H,4), (H,5), (H,6), (T,1), (T,2), (T,3), (T,4), (T,5), (T,6) \]

Step by step solution

01

Identify outcomes for coin flip

The coin flip can result in two possible outcomes: Head (H) or Tail (T)
02

Identify outcomes for die roll

The die roll can result in six possible outcomes: 1, 2, 3, 4, 5, or 6
03

Combine outcomes

Each possible outcome of the coin flip can be combined with each possible outcome of the die roll, resulting in 12 possible outcomes. These are: (H,1), (H,2), (H,3), (H,4), (H,5), (H,6), (T,1), (T,2), (T,3), (T,4), (T,5), (T,6)

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Coin Flip
A coin flip is one of the simplest forms of probability exercises. When you flip a coin, it can land on one of two sides: head (H) or tail (T). This binary outcome makes it a classic example in probability, often used to introduce basic concepts. With a fair coin, the probability of landing on heads is the same as landing on tails, each having a probability of \( \frac{1}{2} \).

Coin flips are used in various scenarios to teach probability principles, such as independence and mutual exclusivity. In this exercise, the coin flip is combined with another event—the rolling of a die—to explore more complicated probability outcomes.
Die Roll
A standard die is a cube with six faces, numbered 1 through 6. Each face is equally likely to land facing upward when the die is rolled. This means that each outcome—whether it's rolling a 1, 2, 3, 4, 5, or 6—has a probability of \( \frac{1}{6} \).

Die rolls are used alongside coin flips to explore compound probability. They help students understand how individual probability events can combine to create more complex sample spaces. In this exercise, the sample space expands when the potential outcomes of a die roll are considered alongside a coin flip.
Combinatorial Analysis
Combinatorial analysis is the study of counting, arranging, and combining objects. It is essential in probability for determining how different outcomes can be combined.

In the context of this exercise, we use combinatorial analysis to combine the results of two separate probability events: a coin flip and a die roll. Each outcome from the coin flip can pair with any of the outcomes from the die roll. Thus, multiplying the 2 outcomes from the coin with the 6 outcomes from the die gives us \( 2 \times 6 = 12 \) total possible outcomes.
  • Outcome from coin flip: \( \{ H, T \} \)
  • Outcome from die roll: \( \{ 1, 2, 3, 4, 5, 6 \} \)
  • Total outcomes: \( 12 \)
Combinatorial analysis helps in visualizing and listing all possible combinations of outcomes. This method is crucial in constructing the sample space.
Probability Outcomes
Probability outcomes describe the possible results from a probability experiment. In this exercise, each combination of a coin flip and a die roll is a distinct outcome.

There are 12 possible outcomes based on combining the 2 outcomes of the coin with the 6 outcomes of the die. These are expressed as ordered pairs: (H,1), (H,2), (H,3), (H,4), (H,5), (H,6), (T,1), (T,2), (T,3), (T,4), (T,5), and (T,6).

Each outcome has the same likelihood of occurring, making it a fair experiment to demonstrate the concept of equal probability distribution. Understanding probability outcomes is fundamental as it forms the basis on which we calculate probabilities for more complex scenarios. Recognizing these outcomes helps in problem-solving, prediction, and making informed decisions based on mathematical likelihoods.

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Most popular questions from this chapter

Prove that for any positive integer \(n,\) there exists a positive integer which, when expressed in decimal, consists of at most \(n\) Os and 1 s and is a multiple of \(n .\) Hint: Consider the set of the \(n\) integers, \(\\{1,11,111, \ldots\\},\) using only \(1 \mathrm{~s},\) and the remainders of these numbers when divided by \(n\). Answer Exercises \(18-21\) to give an argument that shows that if \(X\) is any \((n+2)\) -element subset of \(\\{1,2, \ldots, 2 n+1\\}\) and \(m\) is the greatest element in \(X,\) there exist distinct \(i\) and \(j\) in \(X\) with \(m=i+j .\) For each element \(k \in X-\\{m\\}\), let $$ a_{k}=\left\\{\begin{array}{ll} k & \text { if } k \leq \frac{m}{2} \\ m-k & \text { if } k>\frac{m}{2}. \end{array}\right. $$

Let \(f\) be a one-to-one function from \(X=\\{1,2, \ldots, n\\}\) onto \(X\) Let \(f^{k}=f \circ f \circ \cdots \circ f\) denote the \(k\) -fold composition of \(f\) with itself. Show that there are distinct positive integers \(i\) and \(j\) such that \(f^{i}(x)=f^{j}(x)\) for all \(x \in X .\) Show that for some positive integer \(k, f^{k}(x)=x\) for all \(x \in X\).

Show that $$\sum_{k=m}^{n} C(k, m) H_{k}=C(n+1, m+1)\left(H_{n+1}-\frac{1}{m+1}\right)$$for all \(n \geq m,\) where \(H_{k},\) the \(k\) th harmonic number, is defined$$ H_{k}=\sum_{i=1}^{k} \frac{1}{i} $$

Prove that $$\sum_{k=0}^{m}(-1)^{k} C(n, k)=(-1)^{m} C(n-1, m)$$ for all \(m, 0 \leq m \leq n-1\)

Prove that among a group of six students, at least two received the same grade on the final exam. (The grades assigned were chosen from \(A, B, C, D, F .)\)

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