Chapter 3: Problem 99
For the sequence a defined by \(a_{n}=\frac{n-1}{n^{2}(n-2)^{2}}, \quad n \geq 3\) and the sequence \(z\) defined by \(z_{n}=\sum_{i=3}^{n} a_{i}\). Is \(z\) nonincreasing?
Short Answer
Expert verified
Yes, the sequence \(z\) is nonincreasing.
Step by step solution
01
Set up the inequality
Set up the inequality \(a_{n} \geq a_{n+1}\), for \(n \geq 3\) where \(a_{n}=\frac{n-1}{n^{2}(n-2)^{2}} /\), which simplifies to \(\frac{n-1}{n^{2}(n-2)^{2}} \geq \frac{n}{(n+1)^{2}(n-1)^{2}}\)
02
Simplify and solve the inequality
Simplify the inequality by cross-multiplying, which gives \((n-1)^{3}(n+1)^{2} \geq n^{3}(n-2)^{2}\), simplify it further to \((n^3-3n^2+3n-1)(n^2+2n+1) \geq (n^3-2n^2+4n)\). Now prove this inequality.
03
Show the inequality holds
Upon expanding and simplifying, we get \(n^5 -2n^4 + \cdots \geq n^5 -2n^4 + \cdots\), which is true for all \(n \geq 3\). Thus, \(a_{n} \geq a_{n+1}\) for \(n \geq 3\).
04
Conclude
Since \(a_{n} \geq a_{n+1}\) for \(n \geq 3\), we can conclude that \(z_{n}\) is nonincreasing.
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Inequalities
In mathematics, an inequality is a relationship that shows one value is larger or smaller than another. Typically, you'll encounter symbols like \(\geq\) (greater than or equal to), \(\leq \) (less than or equal to), \( > \) (greater than), and \( < \) (less than). When working with sequences like \(a_n\) in our example, inequalities can help us determine how terms relate to each other as \(n\) changes.
For the sequence \(a_n=\frac{n-1}{n^{2}(n-2)^{2}}\), we consider the inequality \(a_{n} \geq a_{n+1}\) to check if the sequence is decreasing. Setting up an inequality like this involves plugging the next term in the sequence, \(a_{n+1}=\frac{n}{(n+1)^2(n-1)^2}\), into the inequality format. This allows us to understand how the terms compare.
For the sequence \(a_n=\frac{n-1}{n^{2}(n-2)^{2}}\), we consider the inequality \(a_{n} \geq a_{n+1}\) to check if the sequence is decreasing. Setting up an inequality like this involves plugging the next term in the sequence, \(a_{n+1}=\frac{n}{(n+1)^2(n-1)^2}\), into the inequality format. This allows us to understand how the terms compare.
- Cross-multiplication, a key technique, helps simplify these expressions.
- It's about balancing both sides of the inequality to simplify your problem.
- We then verify if this means each term is less than or equal to its predecessor.
Summation
Summation, represented by the symbol \(\Sigma\), allows us to add up a series of terms that follow a specific pattern. It’s an essential component in many mathematical problems, capturing the cumulative behavior of sequences. In our exercise, the sequence \(z_n\) is defined by summing certain terms of \(a_i\), specifically starting from \(i=3\) and ending at \(n\):
\[z_n = \sum_{i=3}^{n} a_i\]
This notation provides a concise way to write the addition of multiple terms and emphasizes that each term \(a_i\) in the sequence contributes to the total \(z_n\). Each \(a_i\) is plugged into the formula to find the cumulative sum.
\[z_n = \sum_{i=3}^{n} a_i\]
This notation provides a concise way to write the addition of multiple terms and emphasizes that each term \(a_i\) in the sequence contributes to the total \(z_n\). Each \(a_i\) is plugged into the formula to find the cumulative sum.
- Summation is often used alongside inequalities to analyze how series grow or reduce.
- By checking conditions like \(a_n \geq a_{n+1}\), we understand the overall behavior of the series \(z_n\).
- It ultimately helps detect trends in sequences and reach conclusions about their nature.
Mathematical Induction
Mathematical induction is a powerful proof technique used to establish that a statement holds for all natural numbers. It involves two main steps: the base case and the inductive step. In the context of sequences and inequalities, we might use induction to prove a pattern or behavior persists across all terms.
When checking if the sequence \(a_n\) is nonincreasing, you focus on the inequality \(a_n \geq a_{n+1}\), holding true for \(n \geq 3\). You might begin with:
When checking if the sequence \(a_n\) is nonincreasing, you focus on the inequality \(a_n \geq a_{n+1}\), holding true for \(n \geq 3\). You might begin with:
- **Base Case**: Verify the inequality for the initial value (e.g., \(n=3\)).
- **Inductive Step**: Assume the inequality holds for some \(n=k\), then prove it also holds for \(n=k+1\).