Chapter 2: Problem 34
Prove that \(2 m^{2}+4 n^{2}-1=2(m+n)\) has no solution in positive integers.
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Chapter 2: Problem 34
Prove that \(2 m^{2}+4 n^{2}-1=2(m+n)\) has no solution in positive integers.
These are the key concepts you need to understand to accurately answer the question.
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Use mathematical induction to prove that $$ \frac{1}{2}+\frac{2}{3}+\cdots+\frac{n}{n+1}<\frac{n^{2}}{n+1} $$ for all \(n \geq 2\). This inequality gives a correct proof of the statement of the preceding exercise.
Refer to the sequence \(c_{1}, c_{2}, \ldots\) defined by the equations $$c_{1}=0, \quad c_{n}=4 c_{|n / 2|}+n \text { for all } n>1$$. Prove that \(c_{n} \leq 4(n-1)^{2}\) for all \(n \geq 1\).
Refer to the sequence \(c_{1}, c_{2}, \ldots\) defined by the equations $$c_{1}=0, \quad c_{n}=c_{\lfloor n / 2\rfloor}+n^{2} \text { for all } n>1$$ Suppose that we want to prove a statement for all \(n \geq 4\) involving \(c_{n} .\) The Inductive Step will assume the truth of the statement involving \(c_{\mid n / 2\rfloor} .\) What are the Basis Steps?
Prove or disprove: \((X-Y) \cap(Y-X)=\varnothing\) for all sets \(X\) and \(Y\).
Use induction to prove that if \(X_{1}, \ldots, X_{n}\) and \(X\) are sets, then (a) \(X \cap\left(X_{1} \cup X_{2} \cup \cdots \cup X_{n}\right)=\left(X \cap X_{1}\right) \cup\left(X \cap X_{2}\right) \cup \cdots \cup\left(X \cap X_{n}\right)\) (b) \(\overline{X_{1} \cap X_{2} \cap \cdots \cap X_{n}}=\overline{X_{1}} \cup \overline{X_{2}} \cup \cdots \cup \overline{X_{n}}\)
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