Chapter 2: Problem 26
Prove that if \(X \subseteq Y,\) then \(Y-(Y-X)=X\) for all sets \(X\) and \(Y\).
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Chapter 2: Problem 26
Prove that if \(X \subseteq Y,\) then \(Y-(Y-X)=X\) for all sets \(X\) and \(Y\).
These are the key concepts you need to understand to accurately answer the question.
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A 3D-septomino is a three-dimensional \(2 \times 2 \times 2\) cube with one \(1 \times 1 \times 1\) corner cube removed. \(A\) deficient cube is \(a k \times k \times k\) cube with one \(1 \times 1 \times 1\) cube removed. Prove that if a \(k \times k \times k\) deficient cube can be tiled by 3D-septominoes, then 7 divides one of \(k-1, k-2, k-4\).
Prove that if \(X \subseteq Y\), then \(X \cap Z \subseteq Y \cap Z\) for all sets \(X, Y\), and \(Z\).
Show that postage of 24 cents or more can be achieved by using only 5 -cent and 7 -cent stamps.
Prove that \(X \cap Y \subseteq X\) for all sets \(X\) and \(Y\).
Using induction, verify the inequality. $$ \frac{1 \cdot 3 \cdot 5 \cdots(2 n-1)}{2 \cdot 4 \cdot 6 \cdots(2 n)} \leq \frac{1}{\sqrt{n+1}}, n=1,2, \ldots $$
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