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91Ó°ÊÓ

For each pair of propositions \(P\) and \(Q\) . State whether or not \(P \equiv Q\). $$ P=p \wedge(q \vee r), Q=(p \vee q) \wedge(p \vee r) $$

Short Answer

Expert verified
Yes, the propositions \(P\) and \(Q\) are logically equivalent.

Step by step solution

01

Understand the Distributive Law

The distributive law in logic states that for any propositions \(a\), \(b\), and \(c\), the following equivalences hold: \(a \wedge (b \vee c) \equiv (a \wedge b) \vee (a \wedge c)\) and \(a \vee (b \wedge c) \equiv (a \vee b) \wedge (a \vee c)\). These laws will be used later to simplify the propositions.
02

Applying the Distributive Law to Proposition P

Apply the distributive law to proposition \(P\), \(p \wedge (q \vee r) \equiv (p \wedge q) \vee (p \wedge r)\). This simplification gives the same form as \(Q\).
03

Compare the Simplified P with Q

After simplifying P, its new form is \((p \wedge q) \vee (p \wedge r)\) which is the same as \(Q\). Hence, \(P \equiv Q\).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Propositional Logic
In discrete mathematics, propositional logic is an important branch focusing on propositions, which are statements that are either true or false. Each proposition is a building block in logical reasoning and can be connected to other propositions using logical connectives to form more complex expressions.

Some common logical connectives include:
  • Conjunction (\( \wedge \)): Connective representing "and"
  • Disjunction (\( \vee \)): Connective representing "or"
  • Negation (\( eg \)): Connective representing "not"
By using these connectives, basic propositions can be transformed into compound ones, allowing for complex logical evaluations and simplifications. This transforms logic from simple true or false sentences into a system where reasoning can be formalized and analyzed for equivalences and validity.
Logical Equivalence
Logical equivalence in propositional logic refers to situations where two different propositions actually convey the same truth, meaning they are interchangeable in logical terms. If propositions are equivalent, they will yield the same result across all possible truth assignments.

For example, given propositions \( P \) and \( Q \), stating that \( P \equiv Q \) means that both propositions are equivalent. They both represent the same logic or concept, even if they are written differently.

To verify logical equivalence:
  • Use truth tables that enumerate all possible truth values
  • Apply logical laws and rules to transform one expression into another
In the context of the exercise, when we transform proposition \( P \) using the distributive law, we achieved its equivalence to \( Q \), confirming \( P \equiv Q \).
Distributive Law
The distributive law in logic is a critical concept for transforming and simplifying logical propositions. It mirrors the distributive property we are familiar with from arithmetic, like how multiplication distributes over addition.

In logical form, the distributive laws include:
  • \( a \wedge (b \vee c) \equiv (a \wedge b) \vee (a \wedge c) \) - This allows for distributing 'and' over 'or'
  • \( a \vee (b \wedge c) \equiv (a \vee b) \wedge (a \vee c) \) - This allows for distributing 'or' over 'and'
These laws are invaluable tools for simplifying logical expressions. In our exercise, we applied the first distributive law to transform \( P = p \wedge (q \vee r) \) to become equivalent with \( Q = (p \vee q) \wedge (p \vee r) \). This restructuring shows \( P \equiv Q \).
Logical Operators
Logical operators are symbols or words used to connect propositions in propositional logic. These operators help form compound logical propositions, allowing us to analyze complex logical relationships between individual statements.

Primary logical operators include:
  • AND (\( \wedge \)): True only if both propositions are true
  • OR (\( \vee \)): True if at least one proposition is true
  • NOT (\( eg \)): Reverses the truth value of a proposition
  • IMPLIES (\( \rightarrow \)): True unless a true proposition implies a false one
  • IF AND ONLY IF (\( \leftrightarrow \)): True only if both propositions have the same truth value
By mastering these operators, students can manipulate and develop more intricate logical statements. In logical equivalences like in our exercise, these operators are key to transforming expressions into their simplest forms while maintaining their inherent truths.

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Most popular questions from this chapter

Answer true or false. $$ \\{x\\} \in\\{x,\\{x\\}\\} $$

Refer to a coin that is flipped 10 times. Write the negation of the proposition. Some heads and some tails were obtained.

Let \(A(x, y)\) be the propositional function " \(x\) attended y's office hours" and let \(E(x)\) be the propositional function " \(x\) is enrolled in a discrete math class." Let \(\mathcal{S}\) be the set of students and let \(T\) denote the set of teachers-all at Hudson University. The domain of discourse of \(A\) is \(\mathcal{S} \times T\) and the domain of discourse of \(E\) is \(\mathcal{S}\). Write each proposition symbolically. All teachers had at least one student attend their office hours.

Provide further motivation for defining \(p \rightarrow q\) to be true when p is false. We consider changing the truth table for \(p \rightarrow q\) when \(p\) is false. For the first change, we call the resulting operator imp1 (Exercise 77 ), and, for the second change, we call the resulting operator imp2 (Exercise 78\() .\) In both cases, we see that pathologies result. Define the truth table for \(i m p 2\) by $$ \begin{array}{cc|c} \hline p & q & p \text { imp } 2 q \\ \hline \mathrm{T} & \mathrm{T} & \mathrm{T} \\ \mathrm{T} & \mathrm{F} & \mathrm{F} \\ \mathrm{F} & \mathrm{T} & \mathrm{T} \\ \mathrm{F} & \mathrm{F} & \mathrm{F} \\ \hline \end{array} $$ (a) Show that \((p \operatorname{imp} 2 q) \wedge(q \operatorname{imp} 2 p) \not \equiv p \leftrightarrow q\) (b) Show that \((1.3 .6)\) remains true if we change the third row of imp2's truth table to \(\mathrm{F} \mathrm{T} \mathrm{F}\).

Determine the truth value of each statement. The domain of discourse is \(\mathbf{R} \times \mathbf{R}\). Justify your answers. $$ \exists x \exists y\left((x < y) \rightarrow\left(x^{2} < y^{2}\right)\right) $$

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