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Let \(|A|=5\). (a) How many directed graphs can one construct on \(A\) ? (b) How many of the graphs in part (a) are actually undirected?

Short Answer

Expert verified
(a) There are \(5^5\) possible directed graphs on A. (b) There are \(2^{10}\) possible undirected graphs on A.

Step by step solution

01

Counting possible directed graphs

The number of possible directed graphs equals the number of possible edges that can be selected, chosen from the set of all possible edges. Since \(|A|=5\), there are 5 nodes. From every node, an edge could be directed to itself or to any other node, for a total of 5 choices per node. Therefore, the total amount of possible edges is \(5^5\).
02

Adjust for undirected graphs

Contrastingly, an undirected graph only has one edge between two nodes, no matter the direction. This implies that the total number of possible edges would be \(\frac{5*(5-1)}{2}\), equivalent to choosing 2 nodes out of 5 to serve as the end points of an edge. This results in 10 possible edges.
03

Counting possible undirected graphs

Following similar logic to step 1, for each of the 10 possible edges, we could decide to include it or not. This results in \(2^10\) possible undirected graphs.

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