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Let \(T=(V, E)\) be a rooted tree with root \(r\). Define the relation \(\$$ on \)V\( by \)x \mathscr{R} y\(, for \)x, y \in V\(, if \)x=y\( or if \)x\( is on the path from \)r\( to \)y\(. Prove that \)\mathscr{R}$ is a partial order.

Short Answer

Expert verified
Every vertex in the set \(V\) of the rooted tree \(T\) is related to itself (reflexivity), if a vertex \(x\) is related to another vertex \(y\) then \(y\) cannot be related to \(x\) unless they are the same (antisymmetry), and if a vertex \(x\) is related to a vertex \(y\) and \(y\) is related to a vertex \(z\), then \(x\) is also related to \(z\) (transitivity). Therefore, the relation \(\mathscr{R}\) is a partial order.

Step by step solution

01

Reflexivity

For each vertex \(x\) in \(V\), by the definition of the relation \(x \mathscr{R} x\). Therefore, the relation is reflexive.
02

Antisymmetry

Suppose that \(x \mathscr{R} y\) and \(y \mathscr{R} x\) for some vertices \(x\) and \(y\) in \(V\). By the definition of the relation, we know that \(x = y\) or \(x\) is on the path from \(r\) to \(y\), and \(y = x\) or \(y\) is on the path from \(r\) to \(x\). The only way both conditions can be satisfied simultaneously is if \(x = y\). Therefore, the relation is antisymmetric.
03

Transitivity

Suppose that \(x \mathscr{R} y\) and \(y \mathscr{R} z\) for some vertices \(x\), \(y\), and \(z\) in \(V\). By the definition of the relation, we know that either \(x = y\) or \(x\) is on the path from \(r\) to \(y\); and either \(y = z\) or \(y\) is on the path from \(r\) to \(z\). In any case, it's clear that either \(x = z\) or \(x\) is on the path from \(r\) to \(z\). Therefore, \(x \mathscr{R} z\) and the relation is transitive.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Rooted Tree
A rooted tree is a special kind of tree structure in graph theory. It is a tree with a designated root node, from which all other nodes extend. This single pathway from the root makes it simple to trace and define relationships between nodes.

The root serves as the origin from which paths to other nodes are established. Every edge in the tree provides a connection between nodes, building a hierarchy or a parent-child relationship. In this hierarchy, the path from the root to any other node is unique, allowing systematic traversal.

Crucially, in a rooted tree:
  • There is exactly one root node.
  • All nodes except the root have exactly one parent.
  • Paths originated from the root dictate reachability.
These properties make rooted trees a foundational concept in exploring partial orders, as they inherently contain ordered relations between elements based on the tree's hierarchy.
Reflexivity
Reflexivity is a fundamental property of relations and means that each element is related to itself. In the context of a relation on a set, reflexivity is satisfied if, for every element \(x\) in the set, \(x \mathscr{R} x\).

In terms of our rooted tree example, any node \(x\) is always considered on its own path from the root, confirming reflexivity. Thus, in the context of partial orders, reflexivity ensures that every node naturally maintains its presence in the system of relations.
  • The relation asserts \(x \mathscr{R} x\).
  • This property helps in organizing nodes within the tree structure.
  • Reflexivity is vital for the relation to qualify as a partial order.
Through reflexivity, each element is anchored within the system, forming the basis for more complex relational properties like transitivity and antisymmetry.
Antisymmetry
Antisymmetry implies that if two elements are pairwise related, then they must be identical. Formally, a relation \(\mathscr{R}\) on a set \(V\) is antisymmetric if for all \(x, y \in V\), if \(x \mathscr{R} y\) and \(y \mathscr{R} x\), then \(x = y\).

In rooted trees, this condition reflects the uniqueness of paths. Given that any two nodes \(x\) and \(y\) form a mutual path with the root, both must describe identical position in structure to mutually satisfy \(x \mathscr{R} y\) and \(y \mathscr{R} x\).
  • Antisymmetry restricts redundant relations.
  • Ensures nodes cannot point to each other unless they are the same.
  • Supports efficient hierarchy establishment.
This is crucial for determining unique connections, contributing to the hierarchy's coherence within a rooted tree.
Transitivity
Transitivity refers to a property where a sequential relation is maintained across elements. More specifically, a relation \(\mathscr{R}\) on a set \(V\) is transitive if, for any \(x, y, z \in V\), \(x \mathscr{R} y\) and \(y \mathscr{R} z\) implies \(x \mathscr{R} z\).

In a rooted tree, this means that if node \(x\) is related to \(y\) and \(y\) is related to \(z\), then \(x\) is related to \(z\), adhering to the tree's path logic.
  • Solidifies the hierarchical integrity of paths.
  • Consolidates sequence relations effectively.
  • Ensures navigability across different levels of the tree efficiently.
Through transitivity, the tree's connectedness is allowed to flourish, promoting a seamless transition of relations across paths from the root to any node, thus embodying a complete structure for partial order exploration.

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Most popular questions from this chapter

If \(G=(V, E)\) is a loop-free undirected graph, we call \(G\) color-critical if \(\chi(G-v)<\chi(G)\) for all \(v \in V\). (We examined such graphs earlier, in Exercise 17 of Section 11.6.) Prove that a color-critical graph has no articulation points.

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A telephone communication system is set up at a company where 125 executives are employed. The system is initialized by the president, who calls her four vice presidents. Each vice president then calls four other executives, some of whom in turn call four others, and so on. (Any executive who does make a call will actually make four calls.) a) How many calls are made in reaching all 125 executives? b) How many executives, aside from the president, are required to make calls?

Construct an optimal prefix code for the symbols \(a, b, c, \ldots, l, j\) that occur (in a given sample) with respective frequencies \(78,16,30,35,125,31,20,50,80,3 .\)

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