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Express each of the following using the summation (or Sigma) notation. In parts (b), (e), \((f)\), and \((g), n\) denotes a positive integer. a) \(1+\frac{1}{2}+\frac{1}{3}+\frac{1}{4}+\frac{1}{5}+\frac{1}{6}+\cdots+\frac{1}{17}\) b) \(\frac{1}{2 !}+\frac{1}{3 !}+\frac{1}{4 !}+\cdots+\frac{1}{n !}, \quad n \geq 2\) c) \(1+4+9+16+25+36+49\) d) \(1^{3}-2^{3}+3^{3}-4^{3}+5^{3}-6^{3}+7^{3}\) e) \(\frac{1}{n}+\frac{2}{n+1}+\frac{3}{n+2}+\cdots+\frac{n+1}{2 n}\) f) \(n+\frac{n+1}{2 !}+\frac{n+2}{4 !}+\frac{n+3}{6 !}+\cdots+\frac{2 n}{(2 n) !}\) g) \(n-\left(\frac{n+1}{2 !}\right)+\left(\frac{n+2}{4 !}\right)-\left(\frac{n+3}{6 !}\right)+\cdots+(-1)^{n}\left(\frac{2 n}{(2 n) !}\right)\)

Short Answer

Expert verified
a) \(\sum_{n=1}^{17} \frac{1}{n}\) \n b) \(\sum_{n=2}^{N} \frac{1}{n!}\) \n c) \(\sum_{n=1}^{7} n^2\) \n d) \(\sum_{n=1}^{7} (-1)^{n+1} n^3\) \n e) \(\sum_{n=1}^{N} \frac{n+1}{2n}\) \n f) \(\sum_{n=0}^{2N} \frac{n+n}{2n!}\) \n g) \(\sum_{n=0}^{2N} (-1)^{n} \frac{n+n}{2n!}\)

Step by step solution

01

Analysis of (a)

For the given series \(1+\frac{1}{2}+\frac{1}{3}+\frac{1}{4}+\frac{1}{5}+\frac{1}{6}+\cdots+\frac{1}{17}\), the nth term is equal to \(\frac{1}{n}\) and it starts from 1 and ends at 17. Therefore, it can be expressed in summation notation as \(\sum_{n=1}^{17} \frac{1}{n}\)
02

Analysis of (b)

For the series \(\frac{1}{2 !}+\frac{1}{3 !}+\frac{1}{4 !}+\cdots+\frac{1}{n !}\), the nth term is equal to \(\frac{1}{n!}\) where \( n! \) denotes the factorial of n and it starts from 2 and ends at n. Therefore, it can be expressed in summation notation as \(\sum_{n=2}^{N} \frac{1}{n!}\) where N is a positive integer.
03

Analysis of (c)

For the given sequence \(1+4+9+16+25+36+49\), the nth term is equal to \(n^2\) and it starts from 1 and ends at 7. Therefore, it can be expressed in summation notation as \(\sum_{n=1}^{7} n^2\)
04

Analysis of (d)

The given sequence \(1^{3}-2^{3}+3^{3}-4^{3}+5^{3}-6^{3}+7^{3}\) oscillates between positive and negative values. The nth term is equal to \((-1)^{n+1} n^3\) and it starts from 1 and ends at 7. Therefore, it can be expressed in summation notation as \(\sum_{n=1}^{7} (-1)^{n+1} n^3\)
05

Analysis of (e)

For the series \(\frac{1}{n}+\frac{2}{n+1}+\frac{3}{n+2}+\cdots+\frac{n+1}{2 n}\), the nth term is equal to \(\frac{n+1}{2n}\) starting from 1 and ending at n. Therefore, it is expressed in summation notation as \(\sum_{n=1}^{N} \frac{n+1}{2n}\) where N is a positive integer.
06

Analysis of (f)

For the series \(n+\frac{n+1}{2 !}+\frac{n+2}{4 !}+\frac{n+3}{6 !}+\cdots+\frac{2 n}{(2 n) !}\), the nth term is equal to \(\frac{n+n}{2n!}\) where \( n! \) is the factorial of n starting from 0 and ending at 2n. Therefore, it is expressed in summation notation as \(\sum_{n=0}^{2N} \frac{n+n}{2n!}\) where N is a positive integer.
07

Analysis of (g)

The given series \(n-\left(\frac{n+1}{2 !}\right)+\left(\frac{n+2}{4 !}\right)-\left(\frac{n+3}{6 !}\right)+\cdots+(-1)^{n}\left(\frac{2 n}{(2 n) !}\right)\) oscillates between positive and negative values. The nth term is equal to \((-1)^{n} \frac{n+n}{2n!}\) where \( n! \) is the factorial of n starting from 0 and ending at 2n. Therefore, it is expressed in summation notation as \(\sum_{n=0}^{2N} (-1)^{n} \frac{n+n}{2n!}\) where N is a positive integer.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Factorials
A factorial is a mathematical concept primarily used for counting permutations and combinations. When you see a factorial, it is expressed with an exclamation mark, like this: \( n! \). The factorial of a positive integer \( n \) is the product of all positive integers less than or equal to \( n \). For example, \( 5! = 5 \times 4 \times 3 \times 2 \times 1 = 120 \).
Factorials grow very rapidly, thus they are useful for representing large quantities. In the context of sequences or series, factorials are often used in formulas to express terms, such as in the series \( \frac{1}{n!} \) where each term involves the factorial of \( n \).
  • The key function of factorials in sequences: they provide an easy way to calculate combinations, probabilities, and, as seen here, terms in a series.
Sequences and Series
A sequence is simply a list of numbers in a specific order. For example, the sequence \( 1, 4, 9, 16, 25 \) follows a pattern where each term is a perfect square: \( 1^2, 2^2, 3^2, 4^2, \) and so on.
Conversely, a series is the sum of the terms of a sequence. When you add all the terms of a sequence together, you've got a series. For example, adding \( 1 + 4 + 9 + 16 + 25 \) to get a total is creating a series from the sequence.
In mathematical notation, the summation sign \( \Sigma \) denotes both sequences and their sums as series, indicating where to start and end the addition. Summation notation simplifies the expression of the sum of a series, e.g., \( \sum_{n=1}^{5} n^2 \) represents the sum of the squares from 1 to 5.
  • The summation notation allows mathematicians to describe sequences and series concisely.
  • Recognizing patterns within sequences is crucial for converting them into series using summation notation.
Mathematical Notation
Mathematical notation is like a language that uses symbols and numbers to convey concepts and ideas efficiently. One such important symbol is the Greek letter Sigma (\( \Sigma \)), used to represent summation.
This powerful symbol indicates the sum of multiple terms following a particular rule. For example, \( \sum_{n=1}^{N} a_n \) tells us to sum terms from \( a_1 \) to \( a_N \). In the given exercises, we translate lengthy, cumbersome expressions into neat summation forms making them easier to work with and interpret.
  • Mathematical notation helps simplify complex mathematical expressions into manageable and understandable forms.
  • The use of sigma notation especially aids in working with large sequences by clearly defining the start, end, and form of each term in the sequence.
Keep practicing with these notations to become comfortable with expressing and manipulating sequences and series.

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Most popular questions from this chapter

a) Provide a combinatorial argument to show that if \(n\) and \(k\) are positive integers with \(n=3 k\), then \(n ! /(3 !)^{k}\) is an integer. b) Generalize the result of part (a).

Determine the number of six-digit integers (no leading zeros) in which (a) no digit may be repeated; (b) digits may be repeated. Answer parts (a) and (b) with the extra condition that the six-digit integer is (i) even; (ii) divisible by 5 ; (iii) divisible by \(4 .\)

The expansion \(\sum_{-3}^{7} \sum_{i=1}^{4} i j\) is an example of a double sum (or double summation). Here we find that \(\sum_{j=3}^{7} \sum_{i=1}^{4} i j=\sum_{i=3}^{7}\left(\sum_{i=1}^{4} i j\right)=\sum_{j=3}^{7}(j+2 j+3 j+4 j)=\sum_{j=3}^{7} 10 j\), after we expand the inner sum(mation) for the variable \(i\). Continuing, we then expand the outer sum(mation) for the variable \(j\) and find that \(\sum_{j=3}^{7} 10 j=10 \sum_{j=3}^{7} j=10(3+4+5+6+7)=\) 250. Hence \(\sum_{j=3}^{7} \sum_{i=1}^{4} i j=250\). Determine the value of each of the following double sums. a) \(\sum_{i=1}^{4} \sum_{j=3}^{7} i j\) b) \(\sum_{i=0}^{4} \sum_{j=1}^{4}(i+j+1)\) c) \(\sum_{j=1}^{4} \sum_{i=0}^{3} i\)

a) Write a computer program (or develop an algorithm) that lists all selections of size 2 from the objects \(1,2,3,4,5,6 .\) b) Repeat part (a) for selections of size \(3 .\)

Determine the sum of all the coefficients in the expansions of a) \((x+y)^{3}\) b) \((x+y)^{10}\) c) \((x+y+z)^{10}\) d) \((w+x+y+z)^{5}\) e) \((2 s-3 t+5 u+6 v-11 w+3 x+2 y)^{10}\).

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