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Two \(n\)-digit integers (leading zeros allowed) are considered equivalent if one is a rearrangement of the other. (For example, 12033, 20331, and 01332 are considered equivalent five-digit integers.) a) How many five-digit integers are not cquivalent? b) If the digits 1,3, and 7 can appear at most once, how many nonequivalent five-digit integers are there?

Short Answer

Expert verified
a) 100000, b) 30240

Step by step solution

01

Finding Total Five-Digit Numbers (Part A)

Since leading zeros are allowed, any of the five places can be filled with any of the 10 digits (0-9). Hence the total number of 5 digit numbers will be \(10^5 = 100000\).
02

Finding Nonequivalent Five-Digit Numbers with Restrictions (Part B)

Here we have 10 digits (0-9) among which 1, 3, and 7 can appear only once and rest of the 7 can be repeated. So to calculate the total non-equivalent numbers, we can consider the problem as distributing 5 places amongst 10 objects (digits) with the mentioned restrictions. The first digit can be either of 1, 3, 7 (3 ways) or of the other 7 digits (7 ways) and hence have 10 ways. The second digit will then have 9 options, the third will have 8 options, fourth will have 7 options and the fifth will have 6 options. Hence the total distinct 5-digit numbers will be \(10*9*8*7*6 = 30240\).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Combinatorial Mathematics
Combinatorial mathematics is the study of counting, arranging, and structuring discrete elements within a set framework. At the heart of combinatorial mathematics sits the fundamental question of how many ways a specific event can take place under certain constraints. This branch of mathematics helps us solve problems dealing with discrete structures such as graphs, permutations, and combinations, and it often involves establishing one-to-one correspondences between two sets, such as the set of all possible rearrangements of digits to form different integers.

When dealing with problems in combinatorial mathematics, such as finding equivalent or non-equivalent integers, we have to consider each possible configuration of digits. For the example given in the exercise, combinatorial principles allow us to understand how the various rearrangements of certain digits lead to distinct or equivalent integers. This concept extends beyond numerical digits to any situation where a number of discrete choices are to be made.
Permutation and Combination
These two concepts are pillars of combinatorial mathematics and deal with the arrangement of items wherein the order may or may not matter.

Permutations

In permutations, the order is significant. For example, when identifying nonequivalent integers, a permutation of the digits is a unique arrangement and thus counts separately. When we consider five-digit integers as in the exercise, permutations of the digits generate distinct integers. This is why 12033, 20331, and 01332 are all different permutations considered separately.

Combinations

In combinations, however, the order doesn't matter. It's about selecting items from a group where the arrangement is irrelevant. While in our exercise we are more concerned with permutations because each rearrangement provides a distinct integer, it's essential always to discern whether a problem requires permutations or combinations to avoid confusion and erroneous calculations.

Both permutation and combination principles aid in solving many problems in fields such as probability, statistics, and decision-making processes.
Counting Principles
Within counting theory, various principles allow us to compute the number of possible outcomes without needing to list them all explicitly.

The Fundamental Counting Principle

states that if one event can occur in 'm' ways and another event can occur independently in 'n' ways, then the total number of ways both events can occur is m * n. Applying this principle to our exercise, if we have 10 options for the first digit and then subsequently 9 options for the second digit because one has been used, and so on, we can calculate the number of non-equivalent five-digit integers without directly enumerating them.

The Addition and Multiplication Principles

are subsets of the fundamental counting principle, used for non-overlapping and overlapping events, respectively. These principles are handy in solving more complex counting problems, such as plotting the growth of possibilities with additional restrictions, or understanding how adding or removing certain digits affect the total count of non-equivalent integers.

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Most popular questions from this chapter

While on a Saturday shopping spree Jennifer and Tiffany witnessed two men driving away from the front of a jewelry shop, just before a burglar alarm started to sound. Although everything happened rather quickly, when the two young ladies were questioned they were able to give the police the following information about the license plate (which consisted of two letters followed by four digits) on the getaway car. Tiffany was sure that the second letter on the plate was either an \(\mathrm{O}\) or a \(\mathrm{Q}\) and the last digit was either a 3 or an 8. Jennifer told the investigator that the first letter on the plate was either a \(\mathrm{C}\) or a \(G\) and that the first digit was definitely a 7 . How many different license plates will the police have to check out?

a) If \(n\) and \(r\) are positive integers with \(n \geq r\), how many solutions are there to $$ x_{1}+x_{2}+\cdots+x_{r}=n $$ where each \(x_{i}\) is a positive integer, for \(1 \leq i \leq r ?\) b) In how many ways can a positive integer \(n\) be written as a sum of \(r\) positive integer summands \((1 \leq r \leq n)\) if the order of the summands is relevant?

A committee of 12 is to be selected from 10 men and 10 women. In how many ways can the selection be carried out if (a) there are no restrictions? (b) there must be six men and six women? (c) there must be an even number of women? (d) there must be more women than men? (e) there must be at least eight men?

a) How many permutations of size 3 can one produce with the letters \(m, r, a, f\), and \(t\) ? b) List all the combinations of size 3 that result for the letters \(\mathrm{m}, \mathrm{r}, \mathrm{a}, \mathrm{f}\), and \(\mathrm{t}\).

Four numbers are selected from the following list of numbers: \(-5,-4,-3,-2,-1,1,2,3,4\). (a) In how many ways can the selections be made so that the product of the four numbers is positive and (i) the numbers are distinct? (ii) each number may be selected as many as four times? (iii) each number may be selected at most three times? (b) Answer part (a) with the product of the four numbers negative.

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