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a) In how many ways can one totally order the partial order of positive- integer divisors of \(96 ?\) b) How many of the total orders in part (a) start with \(96>32 ?\) c) How many of the total orders in part (a) end with \(3>1 ?\) d) How many of the total orders in part (a) start with \(96>32\) and end with \(3>1 ?\) e) How many of the total orders in part (a) start with \(96>48>32>16 ?\)

Short Answer

Expert verified
The number of total orders of divisors of 96 is \(12!\). There are \(10!\) total orders that start with 96>32, \(10!\) that end with 3>1, \(8!\) that start with 96>32 and end with 3>1, and \(8!\) total orders that start with 96>48>32>16.

Step by step solution

01

Identify the divisors of 96

The first thing to do is determine the set of positive integer divisors of 96. They are 1, 2, 3, 4, 6,8, 12, 16, 24, 32, 48, and 96.
02

Calculate all possible orderings

The number of ways to totally order this set is equal to the factorial of the number of elements in this set. As there are 12 elements, the number of orderings will be \(12!\).
03

Calculate orders starting with 96>32

For the orders that start with \(96 > 32\), we're left with 10 other elements to arrange. This gives us \(10!\) orderings.
04

Calculate orders ending with 3>1

For the orders that end with \(3 > 1\), similar to the previous step, we're left with 10 elements to arrange. Again, this gives us \(10!\) orderings.
05

Calculate orders starting with 96>32 and ending with 3>1

A total ordering that both starts with \(96 > 32\) and ends with \(3 > 1\) leaves 8 other elements to be arranged. This gives us \(8!\) orderings.
06

Calculate orders starting with \(96 > 48 > 32 > 16\)

A total ordering starting with \(96 > 48 > 32 > 16\) leaves us with 8 other elements to be arranged, similar to the previous case. It results in \(8!\) total orderings.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Divisors of an Integer
Understanding divisors of an integer is critical when we deal with questions of ordering and arrangements in mathematics. A divisor, also known as a factor, is an integer which evenly divides a given number without leaving a remainder. For the number 96, as highlighted in the exercise, the set of positive integer divisors includes 1, 2, 3, 4, 6, 8, 12, 16, 24, 32, 48, and 96.

Each of these numbers has a unique relationship with 96 in that the product of the divisor and another integer is 96. For example, 3 is a divisor of 96 because 3 times 32 equals 96. This concept is fundamental in creating total orders of elements based on their dividing properties.
Factorial
The factorial, denoted by an exclamation point (!), is a function that multiplies a series of descending natural numbers. For instance, the factorial of 4, written as 4!, would be calculated as 4 x 3 x 2 x 1, which equals 24.

In combinatorial problems, like the one from our exercise, factorials are essential to understanding the total number of ways in which a set of elements can be ordered ('total orders'). The factorial of the number of elements gives us the total number of unique arrangements. For a set with 12 divisors of the integer 96, there are 12! (12 factorial) ways to arrange these divisors into a sequence, or total order.
Ordering Elements
Ordering elements is the process of arranging items according to a certain rule. In mathematics, particularly in set theory, 'partial orders' and 'total orders' are two types of relations that can be used to describe how elements are arranged in a sequence.

A 'partial order' is a binary relation over a set that describes a way to organize elements where not every pair of elements is necessarily comparable. On the other hand, a 'total order' is a kind of partial order in which every pair of elements is comparable, meaning one can always say that one element precedes another. This creates a linear or sequential arrangement, an essential concept in several mathematical disciplines.
Combinatorics
Combinatorics is a branch of mathematics dealing with the counting, arrangement, and combination of objects. It plays a crucial role in problems that require determining the number of possible configurations, such as the number of ways to order a set of divisors.

By utilizing factorial calculations, combinatorics provides the tools needed to tackle questions like those presented in the exercise. It allows us to systematically count the number of total orders and examine specific conditions, like orders starting or ending with certain elements. Combinatorics combines concepts from number theory, algebra, and geometry to solve complex counting problems and is an indispensable tool in modern-day mathematics.

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Most popular questions from this chapter

How many of the equivalence relations on \(A=\) \(\\{a, b, c, d, e, f\\}\) have (a) exactly two equivalence classes of size 3 ? (b) exactly one equivalence class of size \(3 ?\) (c) one equivalence class of size \(4 ?\) (d) at least one equivalence class with three or more elements?

Draw the Hasse diagram for the poset \((\mathscr{P}(M), \subseteq)\), where \(q=\\{1,2,3,4\\}\)

a) Draw the Hasse diagram for the set of positive integer divisors of (i) 2 ; (ii) \(4 ;\) (iii) 6 ; (iv) 8 ; (v) 12; (vi) 16; (vii) 24 ; (viii) 30 ; (ix) 32 . b) For all \(2 \leq n \leq 35\), show that the Hasse diagram for the set of positive-integer divisors of \(n\) looks like one of the nine diagrams in part (a). (Ignore the numbers at the vertices and concentrate on the structure given by the vertices and edges.) What happens for \(n=36 ?\) c) For \(n \in \mathbf{Z}^{+}, \tau(n)=\) the number of positive-integer divisors of \(n .\) (See Supplementary Exercise 32 in Chapter 5.) Let \(m, n \in \mathbf{Z}^{+}\)and \(S, T\) be the sets of all positive-integer divisors of \(m, n\), respectively. The results of parts (a) and (b) imply that if the Hasse diagrams of \(S, T\) are structurally the same, then \(\tau(m)=\tau(n)\). But is the converse true? d) Show that each Hasse diagram in part (a) is a lattice if we define \(\mathrm{glb}[x, y\\}=\operatorname{gcd}(x, y)\) and lub \([x, y]=\operatorname{lcm}(x, y)\)

Let \(A=\\{1,2,3,4,5,6,7\\} .\) How many symmetric relations on \(A\) contain exactly (a) four ordered pairs? (b) five ordered pairs? (c) seven ordered pairs? (d) eight ordered pairs?

Let \(A=\\{1,2,3,4,5,6,7\\}\), For each of the following values of \(r\), determine an equivalence relation \(\mathscr{H}\) on \(A\) with \(|\mathscr{R}|=\) \(r\), or explain why no such relation exists. (a) \(r=6 ;\) (b) \(r=7 ;\) (c) \(r=8 ;\) (d) \(r=9\); (e) \(r=11 ;\) (f) \(r=22\) (h) \(r=30\); (i) \(r=31\) (f) \(r=22 ;\) (g) \(r=23\);

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