Chapter 6: Problem 19
Prove that for all finite languages \(A, B \subseteq \Sigma^{*},|A B| \leq\) \(|A \| B|\)
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Chapter 6: Problem 19
Prove that for all finite languages \(A, B \subseteq \Sigma^{*},|A B| \leq\) \(|A \| B|\)
These are the key concepts you need to understand to accurately answer the question.
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For \(\Sigma=\\{0,1\\}\) consider the languages \(A, B, C \subset \Sigma^{*}\) where \(A=\\{01,11\\}, B=\\{01,11,111\\}\), and \(C=\\{01,11\), 1111\\}. (a) How are \(A^{*}\) and \(B^{*}\) related? (b) How about \(A^{*}\) and \(C^{*} ?\)
For \(\Sigma=\\{0,1\\}\), let \(A, B \subseteq \Sigma^{*}\), where \(A\) is the language of all strings in \(\Sigma^{*}\) of even length, while \(B\) is the language of all strings in \(\Sigma^{*}\) of odd length. Give a recursive definition for each of the languages \(A, B\).
Construct a state diagram for a finite state machine with \(\mathscr{I}=0=\\{0,1\\}\) that recognizes all strings in the language \(\\{0,1\\}^{*}\\{00\\} \cup\\{0,1\\}^{*}\\{11\\}\)
For an alphabet \(\Sigma\) a string \(x\) in \(\Sigma^{*}\) is called a palindrome if \(x=x^{R}-\) that is, \(x\) is equal to its reversal. If \(A \subseteq \Sigma^{*}\) where \(A=\left\\{x \in \Sigma^{*} \mid x=x^{R}\right\\}\), how can we define the language \(A\) recursively?
Show that it is not possible to construct a finite state machine that recognizes precisely those sequences in the language \(A=\left\\{0^{r} 1^{J} \mid i, j \in \mathbf{Z}^{+}, i>j\right\\} .\) (Here the alphabet for \(A\) is \(\Sigma=\\{0,1\\} .)\)
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