/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 15 An electronic system is made up ... [FREE SOLUTION] | 91Ó°ÊÓ

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An electronic system is made up of two components connected in parallel. Consequently, the system fails only when both of the components fail. The probability the first component fails is \(0.05\) and, when this happens, the probability the second component fails is \(0.02\). What is the probability the electronic system fails?

Short Answer

Expert verified
The probability the electronic system fails is \(0.001\).

Step by step solution

01

identify probabilities

There are two probabilities given: the probability the first component, \(P(A)\), fails is \(0.05\), and if it occures, that the second component, \(P(B|A)\), fails is \(0.02\).
02

use the multiplication rule for dependent events

The multiplication rule for independent events is \(P(A and B) = P(A) * P(B|A)\), so plug in known values:\(P(A and B) = 0.05 * 0.02 .\)
03

calculate

So, the probability the electronic system fails:\(P(A and B) = 0.05 * 0.02 = 0.001\).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Probability Theory
Probability theory is a branch of mathematics that deals with the likelihood of events occurring. It's a fundamental tool in understanding how systems behave and in making decisions based on uncertain outcomes. In probability theory, the probability of an event is a number between 0 and 1, where 0 indicates impossibility and 1 indicates certainty.

When looking at real-world applications, such as the functioning of an electronic system, we utilize probability theory to predict system reliability and to mitigate risks associated with component failures. By calculating the probability of a system failure, engineers are able to design more reliable systems and maintain them effectively. In the given exercise, we apply probability theory to understand the likelihood of both components in a parallel electronic system failing, which provides insight into the overall reliability of the system.
Dependent Events
In probability, events can either be independent or dependent. Dependent events are those in which the outcome or occurrence of the first event affects the outcome of the second event. An example of this is drawing cards from a deck without replacement; the cards that have already been drawn affect the probabilities of drawing other cards on subsequent turns.

In the context of system failures, if the failure of the first component affects the probability of the second component failing, these are considered dependent events. In our exercise, the failure of the first component changes the likelihood of the second component failing, which is why we need to consider the probability of the second failure given that the first has already occurred, denoted as P(B|A). Understanding how these events interact is vital for assessing the system's reliability.
Multiplication Rule
The multiplication rule is a principle in probability that provides a way to find the probability of two events occurring together. The rule differs for independent and dependent events. For independent events, the probability of both events occurring is the product of their individual probabilities. However, for dependent events, we must adjust this calculation to account for the relationship between the events.

In this exercise, we focus on the multiplication rule for dependent events, which is expressed as P(A and B) = P(A) * P(B|A). Here, P(A and B) represents the probability that both events A and B occur together, and P(B|A) is the probability that event B occurs given that event A has already occurred. This adjusted formula is essential in calculating the probability of the electronic system's failure, given its component dependencies.

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Most popular questions from this chapter

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A shipment of 120 graphics cards contains 10 that are defective. Serena selects five of these cards, without replacement, and inspects them to see which, if any, are defective. If the random variable \(X\) counts the number of defective graphics cards in Serena's selection, determine (a) \(\operatorname{Pr}(X=x), x=0,1,2, \ldots, 5 ;\) (b) \(\operatorname{Pr}(X=4)\); (c) \(\operatorname{Pr}(X \geq 4)\); and (d) \(\operatorname{Pr}(X=1 \mid X \leq 2)\).

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