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Let \(S=\\{1,2,3, \ldots, 29,30\\} .\) How many subsets \(A\) of \(S\) satisfy (a) \(|A|=5 ?\) (b) \(|A|=5\) and the smallest element in \(A\) is \(5 ?\) (c) \(|A|=5\) and the smallest element in \(A\) is less than \(5 ?\)

Short Answer

Expert verified
The answers are (a) \(_{30}C_{5} = \frac{30!}{5!(30-5)!}\), (b) \(_{26}C_{4} = \frac{26!}{4!(26-4)!}\), and (c) \(4 * _{26}C_{4} = 4 * \frac{26!}{4!(26-4)!}\).

Step by step solution

01

Subsets with |A| = 5

Determine the number of subsets, \(A\), from the set \(S\) such that \(|A|=5\). This is equivalent to calculating \(_{30}C_{5}\), or in simpler terms, 'from 30 items, how many ways can 5 be chosen?' This is calculated as \(\frac {30!}{5!(30-5)!}\) . Using factorial notation, '!' means to multiply all positive integers from our chosen number down to 1.
02

Subsets with smallest element 5

Calculate the number of subsets, \(A\), such that \(|A|=5\) and the smallest element in \(A\) is \(5\). For these subsets, the first number is fixed as 5, and the remaining 4 elements are chosen from 26 (30 - 4) possible numbers. Therefore, calculate \(_{26}C_{4} = \frac {26!}{4!(26-4)!}\).
03

Subsets with smallest element less than 5

Calculate the number of subsets, \(A\), where \(|A|=5\) and the smallest element in \(A\) is less than \(5\). There are 4 possibilities for the smallest number (1 to 4). Hence, the number of ways to select the smallest numbers is 4. To fill the remaining 4 spots in the subsets, we have 26 possible numbers. Therefore, the calculation is \(4 * _{26}C_{4} = 4 * \frac{26!}{4!(26-4)!}\).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Factorial Notation
Factorial notation is a mathematical convention for expressing the product of a series of descending natural numbers. To represent a number's factorial, we use the exclamation mark symbol \textbf{(!)}. For example, the factorial of 5, written as \(5!\), is calculated by multiplying 5 by every positive integer less than itself: \[5! = 5 \times 4 \times 3 \times 2 \times 1 = 120.\]

Factorials are exceedingly important in combinatorics because they are used in formulas to count the number of ways things can be arranged or combined. They provide a simple way to calculate the permutations or combinations of a given set, a fundamental concept in probability and statistics as well. A common application in combinatorial problems is when we have to find the number of possible ways to arrange or select items without repetition.

Understanding this mathematical concept is vital when solving problems involving combinations, as problem step 1 demonstrated, where factorial notation was used to calculate the number of subsets of a set.
Combinations
Combinations are selections made by taking some or all objects without considering the order of the objects. This is a key concept in combinatorics, which is a branch of mathematics focused on counting, arrangement, and grouping methods. To calculate combinations, the formula \(_nC_r = \frac{n!}{r!(n-r)!}\) is used, where \(n\) is the total number of items to choose from, \(r\) is the number of items to be chosen, and \(n!\) is the factorial of \(n\).

The distinction between combinations and permutations lies in the importance of order; combinations do not account for different orders, whereas permutations do. For example, in the textbook exercise, the number of ways to select 5 elements from a set of 30, without regard to the order, is expressed as \(_{30}C_{5}\). This approach to counting is essential when solving problems that ask for the number of ways to choose items from a larger set when the order doesn't matter—as seen in the provided steps for calculating subsets.
Set Theory
Set theory is a fundamental theory in mathematics that deals with the collection of objects or elements known as sets. This concept is the basis for all of mathematics and is particularly useful in combinatorics. In set theory, the size or cardinality of a set is denoted as \(|S|\), and it refers to the number of elements in set \(S\).

Within this framework, the notion of a subset is critical. A subset is any set where all elements are contained within a larger set. The power set of any given set \(S\) is the set of all possible subsets of \(S\), including both the empty set and \(S\) itself. When working with subsets, we often want to determine the number of specific subsets that meet certain criteria, such as having a fixed number of elements or a particular smallest element.

In the given exercise solutions, understanding set theory allowed the calculation of subsets of a particular set that satisfy various conditions like having a fixed cardinality of 5 or having a smallest element less than or equal to 5. These applications of set theory simplify the process of addressing complex combinatorial problems.

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Most popular questions from this chapter

Professor Diane gave her chemistry class a test consisting of three questions. There are 21 students in her class, and every student answered at least one question. Five students did not answer the first question, seven failed to answer the second question, and six did not answer the third question. If nine students answered all three questions, how many answered exactly one question?

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