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3\. Let \(p, q\) be primitive statements for which the implication \(p \rightarrow q\) is false. Determine the truth values for each of the following. a) \(p \wedge q\) b) \(\neg p \vee q\) c) \(q \rightarrow p\) d) \(\neg q \rightarrow \neg p\)

Short Answer

Expert verified
The truth values for the logical expressions are: a) false, b) false, c) true, d) false.

Step by step solution

01

Analyzing the given false implication

By examining the given false implication 'p -> q', we recognize that for this implication to be false, 'p' must be 'true' and 'q' must be 'false'.
02

Evaluating logical expressions

Using these identified values for 'p' and 'q', we evaluate each of the following logical expressions. a) For the first logical expression 'p ∧ q', the result is 'true ∧ false' which evaluates to 'false'. b) For the second expression '¬p ∨ q', it transforms to '¬true ∨ false' which simplifies to 'false ∨ false', and therefore, it evaluates to 'false'. c) For 'q -> p', it turns into 'false -> true', and as per the definition of implication, this evaluates to 'true'. d) For '¬q -> ¬p', we get '¬false -> ¬true' which simplifies to 'true -> false'. This evaluates to 'false' as per the implication definition when 'p' is true and 'q' is false.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Logical Implications
A logical implication is a fascinating concept in propositional logic. It is an expression formed with two logical statements, usually represented as \( p \rightarrow q \). The idea is simple: if the first part \( p \) (called the antecedent) is true, then the second part \( q \) (called the consequent) should be true for the whole implication to hold true. If \( p \) is true but \( q \) turns out to be false, the entire implication \( p \rightarrow q \) becomes false.
However, if \( p \) is false, the implication \( p \rightarrow q \) is considered true regardless of whether \( q \) is true or false.
  • True \( \rightarrow \) True results in True.
  • True \( \rightarrow \) False results in False.
  • False \( \rightarrow \) True results in True.
  • False \( \rightarrow \) False results in True.
Understanding logical implications helps in evaluating logical expressions efficiently and accurately.
Truth Values
Truth values are the building blocks of propositional logic. In this field, statements are either true or false, nothing else. These two possibilities form the classic binary system.
Consider a logical statement like \( p \) or \( q \). These are primitive propositions which could be true or false. When analyzing compound logical statements formed with operators like \( \wedge \), \( \vee \), and \( \rightarrow \), figuring out the truth values of these statements becomes essential.
Let's break it down with an example:
  • For \( p \wedge q \), the compound statement is true only when both \( p \) and \( q \) are true.
  • For \( eg p \), the truth value is the opposite of \( p \). If \( p \) is true, \( eg p \) is false.
  • In \( eg p \vee q \), the statement holds true if at least one of the expressions is true.
Mastering truth values allows for a clear understanding of whether a given logical expression is true or false.
Logical Expressions
Logical expressions are combinations of primitive logical statements using logical operators to form complex judgments. They employ operators like "and" (\( \wedge \)), "or" (\( \vee \)), "not" (\( eg \)), and "implies" (\( \rightarrow \)). These operators function like arithmetic operators, determining how we evaluate our logical statements.

A well-known logical expression from our example is \( eg p \vee q \). Here's how it works:
  • The expression \( eg p \vee q \) means "not \( p \) or \( q \)," which evaluates to true if at least one part is true.
  • Additionally, consider \( q \rightarrow p \). This reverses the roles of \( p \) and \( q \), showing how changing the arrangement of terms alters their logical relationship
  • Logical expressions like \( eg q \rightarrow eg p \) illustrate how negating each part can change the outcome of the implication.
Understanding different logical expressions and how they work helps in constructing arguments and solving complex logical problems more effectively.

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Most popular questions from this chapter

7\. For the universe of all integers, let \(p(x), q(x), r(x), s(x)\), nd \(t(x)\) be the following open statements. \(s(x) ; \quad x\) is (exactly) divisible by 4 \(t(x): \quad x\) is (exactly) divisible by 5 a) Write the following statements in symbolic form. i) At least one integer is even. ii) There exists a positive integer that is even. iii) If \(x\) is even, then \(x\) is not divisible by 5 . iv) No even integer is divisible by 5 . v) There exists an even integer divisible by \(5 .\) vi) If \(x\) is even and \(x\) is a perfect square, then \(x\) is divisible by 4 b) Determine whether each of the six statements in part (a) is true or falsc. For cach false statement, provide a counterexample. c) Express each of the following symbolic representations in words. i) \(\forall x[r(x) \rightarrow p(x)]\) ii) \(\forall x[s(x) \rightarrow q(x)]\) iii) \(\forall x[s(x) \rightarrow \neg t(x)]\) iv) \(\exists x[s(x) \wedge \neg r(x)]\) d) Provide a counterexample for each false statement in part (c)

4\. Let \(n\) be a positive integer greater than 1 . We call \(n\) prime if the only positive integers that (exactly) divide \(n\) are 1 and \(n\) itself. For example, the first seven primes are \(2,3,5,7,11\), 13 , and 17. (We shall learn more about primes in Chapter 4.) Use the method of exhaustion to show that every integer in the universe \(4,6,8, \ldots, 36,38\) can be written as the sum of two primes.

1\. Determine whether each of the following sentences is a statement. a) In 2003 George W. Bush was the president of the United States, b) \(x+3\) is a positive integer. c) Fifteen is an even number. d) If Jennifer is late for the party, then her cousin Zachary will be quite angry. e) What time is it? f) As of June 30,2003 , Christine Marie Evert had won the French Open a record seven times.

24\. Let \(n\) be an integer. Prove that \(n\) is even if and only if \(31 n+12\) is even.

12\. a) Let \(p(x, y)\) denote the open statement " \(x\) divides \(y\)," where the universe for each of the variables \(x, y\) comprises all integers. (In this context "divides" means "exactly divides" or "divides evenly.") Determine the truth value of each of the following statements; if a quantified statement is false, provide an explanation or a counterexample. i) \(p(3,7)\) ii) \(p(3,27)\) iii) \(\forall y p(1, y)\) iv) \(\forall x p(x, 0)\) v) \(\forall x p(x, x)\) vi) \(\forall y \exists x p(x, y)\) vii) \(\exists y \forall x p(x, y)\) viii) \(\forall x \forall y[(p(x, y) \wedge p(y, x)) \rightarrow(x=y)]\) b) Determine which of the eight statements in part (a) will change in truth value if the universe for each of the variables \(x, y\) were restricted to just the positive integers. c) Determine the truth value of each of the following statements. If the statement is false, provide an explanation or a counterexample. [The universe for each of \(x, y\) is as in part (b).] i) \(\forall x \exists y p(x, y)\) ii) \(\forall y \exists x p(x, y)\) iii) \(\exists x \forall y p(x, y)\) iv) \(\exists y \forall x p(x, y)\)

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