/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 17 17\. Prove the following result ... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

17\. Prove the following result in three ways (as in Theorem 2.4): If \(n\) is an odd integer, then \(n+11\) is even.

Short Answer

Expert verified
Three proofs have been provided to confirm that the sum of an odd integer \(n\) and 11 is always even. Proof 1 was based on the definition of odd and even numbers, Proof 2 utilized the properties of odd and even numbers, and Proof 3 used modular arithmetic.

Step by step solution

01

Proof 1: Definition of odd and even numbers

If \(n\) is odd, we can write it as \(n = 2k + 1\) for some integer \(k\). Then, \(n + 11 = 2k + 1 + 11 = 2k + 12 = 2(k + 6)\). Because \(k + 6\) is an integer, \(n + 11\) can be written in the form \(2m\) where \(m = k + 6\), and is therefore even by definition.
02

Proof 2: Even and odd properties

By properties of odd and even numbers, the sum of an odd number and an even number is always odd, while the sum of two odd numbers is always even. If \(n\) is odd and \(11\) is odd, the sum \(n + 11\) is therefore even.
03

Proof 3: Modular arithmetic

In modular arithmetic, if \(n\) is odd, then \(n \equiv 1 \mod 2\). Adding 11 to both sides gives \(n+11 \equiv 12 \mod 2\), which simplifies to \(n+11 \equiv 0 \mod 2\). Hence, \(n+11\) is even.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Modular Arithmetic
Modular arithmetic is a fascinating part of number theory, often likened to clock arithmetic. Here, numbers wrap around upon reaching a certain value, called the modulus. To visualize this, imagine a clock that resets to 1 after reaching 12.

If a number is divided by the modulus, the remainder is what defines it in modular arithmetic. For instance, when we say that an integer \( n \) is odd, it can be expressed using modular arithmetic as \( n \equiv 1 \mod 2 \). This tells us that when divided by 2, the remainder is 1.
  • Odd numbers leave a remainder of 1 when divided by 2.
  • Even numbers leave a remainder of 0 when divided by 2.
In the context of the exercise, when we have \( n+11 \equiv 12 \mod 2 \), it's straightforward: 12 is divided by 2 with no remainder, proving \( n+11 \equiv 0 \mod 2 \). Hence, \( n+11 \) is even.
Properties of Odd and Even Numbers
The properties of odd and even numbers are essential in understanding arithmetic operations and their results.

It's crucial to learn that:
  • Adding two odd numbers results in an even number.
  • Adding two even numbers also results in an even number.
  • Adding an odd number to an even number results in an odd number.
So, when we look at the problem, if \( n \) is odd and 11 is odd, the sum \( n + 11 \) becomes even, since the sum of two odd numbers always leads to an even number. These properties are very predictable and can be proven using simple arithmetic or algebraic expressions.
Integer Definitions
Integers are the set of whole numbers that includes positive numbers, negative numbers, and zero. One defining feature of integers is that they do not have fractional or decimal parts.

In mathematics, integers are used in a variety of ways. Odd and even integers are simple types of integers which have fascinating properties.
  • An integer is even if it can be expressed in the form \( 2m \), where \( m \) is also an integer.
  • An integer is odd if it can be written in the form \( 2k + 1 \), where \( k \) is an integer as well.
From the exercise, if we assume \( n \) to be an odd integer represented as \( 2k + 1 \), adding 11 results in an expression that can be rearranged into an even integer, \( 2(k + 6) \). Studying these definitions helps illustrate why certain additions result in odd or even numbers.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

3\. Let \(p(x)\) be the open statement \({ }^{4} x^{2}=2 x\)," where the universe comprises all integers. Determine whether each of he following statements is true or false. a) \(p(0)\) b) \(p(1)\) c) \(p(2)\) d) \(p(-2)\) e) \(\exists x p(x)\) f) \(\forall x p(x)\)

12\. Write each of the following arguments in symbolic form. Then establish the validity of the argument or give a counterexample to show that it is invalid. a) If Rochelle gets the supervisor's position and works hard, then she'll get a raise. If she gets the raise, then she'll buy a new car. She has not purchased a new car. Therefore either Rochelle did not get the supervisor's position or she did not work hard. b) If Dominic goes to the racetrack, then Helen will be mad. If Ralph plays cards all night, then Carmela will be mad. If either Helen or Carmela gets mad, then Veronica (their attorney) will be notified. Veronica has not heard from either of these two clients. Consequently, Dominic didn't make it to the racetrack and Ralph didn't play cards all night. c) If there is a chance of rain or her red headband is missing, then Lois will not mow her lawn. Whenever the temperature is over \(80^{\circ} \mathrm{F}\), there is no chance for rain. Today the temperature is \(85^{\circ} \mathrm{F}\) and Lois is wearing her red headband. Therefore (sometime today) Lois will mow her lawn.

7\. a) If \(p, q\) are primitive statements, prove that $$ (\neg p \vee q) \wedge(p \wedge(p \wedge q)) \Leftrightarrow(p \wedge q) $$ b) Write the dual of the logical equivalence in part (a).

12\. Write the following argument in symbolic form. Then either establish the validity of the argument or provide a counterexample to show that it is invalid. If it is cool this Friday, then Craig will wear his suede jacket if the pockets are mended. The forecast for Friday calls for cool weather, but the pockets have not been mended. Therefore Craig won't be wearing his suede jacket this Friday.

17\. For any statements \(p, q\), prove that a) \(\neg(p \downarrow q) \Leftrightarrow(\neg p \uparrow \neg q)\) b) \(\neg(p \uparrow q) \Leftrightarrow(\neg p \downarrow \neg q)\)

See all solutions

Recommended explanations on Math Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.