/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 7 A certain "Burger Joint" adverti... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

A certain "Burger Joint" advertises that a customer can have his or her hamburger with or without any or all of the following: catsup, mustard, mayonnaise, lettuce, tomato, onion, pickle, cheese, or mushrooms. How many different kinds of hamburger orders are possible?

Short Answer

Expert verified
There are 512 different kinds of hamburger orders possible.

Step by step solution

01

Understand the concept of Subsets

A subset is a set that consists of elements from another set. In our case, every subset of toppings represents a different kind of hamburger order. For each topping, we have two choices: we either include it (on the hamburger) or exclude it (not on the hamburger). As there are 9 toppings in total to decide upon, we essentially have a two-choice decision (include or exclude) being made 9 times.
02

Calculate the Number of Subsets

The number of subsets of a set with 'n' elements is calculated as \(2^n\). This is because for each element, you have 2 options: include it or not. So, for 'n' items, you have \(2^n\) different possibilities. Since we have 9 toppings, the total number of possibilities is \(2^9\).
03

Apply the formula

Just plug the number of toppings into the formula. Here 'n' is 9, so the total number of different kinds of hamburger orders are \(2^9\)=512.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Understanding Subsets
At the heart of counting the different kinds of hamburger orders is the concept of subsets. If you think of each topping as a 'yes' or 'no' decision, each unique combination of decisions will give you a different set of toppings—each one being a subset of the full list of available toppings. Subsets are fundamental in combinatorics, the branch of mathematics that deals with counting, because they represent all the possible selections you can make.
Consider an easy example: if you only had two toppings to choose from, say lettuce and tomato, there would be four possible subsets: no toppings, just lettuce, just tomato, and both toppings. So for two toppings, there are 2 raised to the power of 2, which equals 4 subsets. This principle scales up with the number of toppings, leading us to the formula for calculating the number of subsets. For our burger joint with 9 toppings, using the formula \(2^n\), where 'n' is the number of toppings, we can calculate the number of different hamburger orders by simply raising 2 to the power of 9, which gives us 512. This exponential growth in possibilities shows how quickly options can expand even with a relatively small number of elements to choose from.
Permutations and Combinations
While subsets are about choosing 'yes' or 'no' for each element, permutations and combinations are different but related ways of arranging elements. Permutations care about the order of the elements, whereas combinations do not.
Imagine you're not just choosing whether to have cheese or lettuce on your burger but also the order in which they are placed. If you had three toppings and wanted to eat them in a particular sequence, that would require calculating permutations. For example, choosing the sequence of cheese, lettuce, and tomato would be a different permutation than tomato, lettuce, and cheese.
On the other hand, if you're only concerned about which toppings are on the burger without regard to order, you're thinking about combinations. Both permutations and combinations use factorials in their formulas, which are represented by an exclamation point and signify the product of an integer and all the integers below it. For instance, 3! equals 3 x 2 x 1, which is 6. Understanding when to use permutations or combinations depends on the problem's requirements and whether the order of elements matters.
Exponential Growth
Exponential growth is a concept that explains how certain quantities can increase at an accelerating rate, rather than a steady, linear pace. In our burger topping scenario, the number of possible hamburger combinations illustrates exponential growth perfectly.
With each additional topping option, the number of possible orders doesn't just increase by a fixed amount; it doubles. This doubling effect is what characterizes exponential growth, and it can be depicted mathematically as \(2^n\), where 'n' is the number of toppings or elements in question. It's what happens when you take a small number and raise it to a power based on the number of choices.
The idea of exponential growth is not just found in mathematics; it has real-world implications in various fields including biology, where populations can grow exponentially under ideal conditions, and technology, where we often hear about Moore's Law describing the rapid growth in computing power over time. Recognizing exponential growth patterns helps not only in solving combinatorial problems but in understanding complex systems in general.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

a) Fifteen points, no three of which are collinear, are given on a plane. How many lines do they determine? b) Twenty-five points, no four of which are coplanar, are given in space. How many triangles do they determine? How many planes? How many tetrahedra (pyramidlike solids with four triangular faces)?

In the Internet each network interface of a computer is assigned one, or more, Internet addresses. The nature of these Internet addresses is dependent on network size. For the Internet Standard regarding reserved network numbers (STD 2), each address is a 32 -bit string which falls into one of the following three classes: (1) A class A address, used for the largest networks, begins with a 0 which is then followed by a seven-bit network number, and then a 24-bit local address. However, one is restricted from using the network numbers of all 0 's or all 1's and the local addresses of all 0 's or all 1's. (2) The class B address is meant for an intermediate-sized network. This address starts with the two-bit string 10, which is followed by a 14-bit network number and then a 16 -bit local address. But the local addresses of all 0 's or all 1's are not permitted. (3) Class C addresses are used for the smallest networks. These addresses consist of the three-bit string 110 , followed by a 21 -bit network number, and then an eight-bit local address. Once again the local addresses of all 0 's or all 1's are excluded. How many different addresses of each class are available on the Internet, for this Internet Standard?

Consider the \(2^{19}\) compositions of 20 . (a) How many have each summand even? (b) How many have each summand a multiple of 4 ?

a) How many arrangements are there of all the letters in SOCIOLOGICAL? b) In how many of the arrangements in part (a) are A and G adjacent? c) In how many of the arrangements in part (a) are all the vowels adjacent?

How many different paths in the \(x y\)-plane are there from \((0,0)\) to \((7,7)\) if a path proceeds one step at a time by going either one space to the right (R) or one space upward \((U)\) ? How many such paths are there from \((2,7)\) to \((9,14)\) ? Can any general statement be made that incorporates these two results?

See all solutions

Recommended explanations on Math Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.