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a) How many nonnegative integer solutions are there to the pair of equations \(x_{1}+x_{2}+x_{3}+\cdots+x_{7}=37\), \(x_{1}+x_{2}+x_{3}=6 ?\) b) How many solutions in part (a) have \(x_{1}, x_{2}, x_{3}>0\) ?

Short Answer

Expert verified
Part (a): There are \(\binom{37+7-1}{7-1} - \(\binom{6+7-1}{7-1}\) nonnegative integer solutions. Part (b): There are \(\binom{34+7-1}{7-1} - \(\binom{3+7-1}{7-1}\) solutions where \(x_{1}, x_{2}, x_{3} > 0\).

Step by step solution

01

Solve Part (a)

Here we apply the 'stars and bars' theorem. The equation \(x_{1}+x_{2}+x_{3}+\cdots+x_{7}=37\) has \(\binom{37+7-1}{7-1}\) nonnegative integral solutions. But the equation \(x_{1}+x_{2}+x_{3}=6\) reduces the above number by \(\binom{6+7-1}{7-1}\). Hence, the total number of solutions for part (a) is \(\binom{37+7-1}{7-1} - \(\binom{6+7-1}{7-1}\).
02

Solve Part (b)

In order for each \(x_{i}\) (\(i=1,2,3\)) to be strictly greater than 0, we can subtract 1 from each of these variables, which does not affect the non-negativity of all variables. This leads to \(x_{1}+x_{2}+x_{3}+\cdots+x_{7}=34\) and \(x_{1}+x_{2}+x_{3}=3\). Now apply the same process from Step 1 to solve these new equations, the total number of solutions for part (b) is \(\binom{34+7-1}{7-1} - \(\binom{3+7-1}{7-1}\).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Stars and Bars theorem
The Stars and Bars theorem is a fundamental method used in combinatorics to find the number of ways to distribute indistinguishable items into distinguishable bins. Think of the items as 'stars' and the separations between different groupings of stars as 'bars.' This theorem is particularly useful when we have a problem involving the sum of variables, as it allows us to compute the number of solutions to such equations with ease.
The theorem works by transforming the problem into a partition problem. For example, if you're asked to solve the equation \(x_1 + x_2 + \cdots + x_n = k\), with nonnegative integer solutions, the task is to determine how many ways we can place 'bars' to divide 'stars' into different 'bins,' each representing a variable.

  • The number of stars \( k \) equals the total sum we want across all variables.
  • The number of bars \( (n-1) \) is one less than the number of variables.
  • The solution is given by the formula \( \binom{k+n-1}{n-1} \), where \( \binom{n}{r} \) represents a binomial coefficient.
This technique is elegantly simple and powerful for combinatorial counting problems.
Nonnegative integer solutions
When searching for the number of nonnegative integer solutions to an equation, such as \(x_1 + x_2 + \cdots + x_n = k\), it’s crucial to recognize that each variable can be any integer starting from zero and extending upwards. This contrasts with positive integer solutions where each variable must be at least 1.
To handle nonnegative solutions, the Stars and Bars method described earlier fits perfectly since it directly accommodates zero values. For example, when solving \(x_1 + x_2 + \cdots + x_n = k\):

  • You view the total sum \( k \) as being composed of \( n \) smaller parts, where any part can be zero.
  • Recall that when subtracting or shifting the values to find solutions for a modified condition (e.g., making variables positive), you'll start by reducing the variables' total sum.
  • This method maintains the elegance and simplicity needed for nonnegative integers by allowing various combinations including zero values.
It’s a versatile approach, immediately unlocking the solution space for many similar problems.
Binomial coefficient
The binomial coefficient, represented as \( \binom{n}{r} \), is a key concept in combinatorics for determining the number of ways to choose \( r \) items from \( n \) without regard to order. Often spoken as "n choose r," this concept is fundamental when calculating combinations, such as distributing items or choosing subsets.
In mathematical terms, the binomial coefficient \( \binom{n}{r} \) can be calculated using the formula:

\[ \binom{n}{r} = \frac{n!}{r!(n-r)!} \]

where \( n! \) (read as "n factorial") is the product of all positive integers up to \( n \), and similarly for \( r \) and \( (n-r) \).
Here's why binomial coefficients are so essential:
  • They allow calculation of different arrangements and groupings in combinatorial problems.
  • In Stars and Bars applications, they tell you how many ways you can distribute 'stars' with 'bars' acting as dividers.
  • They feature prominently in binomial expansions, where they give the coefficients of terms in expressions \((a+b)^n\).
This concept not only simplifies complex counting scenarios but also underpins core mathematical principles—and grips the essence of many combinatorial challenges.

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