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Verify that for each integer \(n \geq 1\), $$ \left(\begin{array}{c} 2 n \\ n \end{array}\right)-\left(\begin{array}{c} 2 n \\ n-1 \end{array}\right)=\frac{1}{n+1}\left(\begin{array}{c} 2 n \\ n \end{array}\right) $$.

Short Answer

Expert verified
Verified that \(\binom{2n}{n} - \binom{2n}{n-1} = \frac{1}{n+1}\binom{2n}{n}\) is true for all integers \(n \geq 1\).

Step by step solution

01

Understand binomial coefficients

A binomial coefficient is a way to count the number of possible combinations of \(n\) items. Specifically, \( \binom{n}{k} \) is the number of ways to choose \(k\) items from a set of \(n\). The definition of a binomial coefficient is \(\binom{n}{k} = \frac{n!}{k!(n-k)!}\), where \( ! \) indicates the factorial function, which is the product of all positive integers up to \(n\).
02

Calculate the binomials

The given expression has two binomial coefficients: \(\binom{2n}{n}\) and \(\binom{2n}{n-1}\). Using the formula for binomial coefficients, these can be expanded to: \(\binom{2n}{n} = \frac{(2n)!}{n!(2n-n)!} = \frac{(2n)!}{n!n!}\), \(\binom{2n}{n-1} = \frac{(2n)!}{(n-1)!(2n-n+1)!} = \frac{(2n)!}{(n-1)!n!}\).
03

Subtract and Simplify

Subtract \(\binom{2n}{n-1}\) from \(\binom{2n}{n}\) and simplify using the formulas found in Step 2. This results in: \(\binom{2n}{n} - \binom{2n}{n-1} = \frac{(2n)!n!}{n!n!n} - \frac{(2n)!n!}{(n-1)!n!} = \frac{(2n)!}{n!(n+1)!} = \frac{1}{n+1}\binom{2n}{n}\), which affirms the initial claim.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Combinatorics and Binomial Coefficients
Combinatorics is a field of mathematics primarily concerned with counting, both as a means and an end in obtaining results, and certain properties of finite structures. It is closely related to many other areas of mathematics and has many practical applications ranging from computer science to statistics.

One of the key concepts within combinatorics is the binomial coefficient, which appears often in combinatorial problems. This coefficient, commonly expressed as \( \binom{n}{k} \), represents the distinct ways to choose \( k \) elements from a set of \( n \) items without considering the order of selection. For example, if you wish to form a committee of 3 people from a group of 10, you would use the binomial coefficient \( \binom{10}{3} \) to find the number of possible combinations.

To improve the understanding of binomial coefficients, it's essential to recognize that they are symmetric: \( \binom{n}{k} \) is the same as \( \binom{n}{n-k} \). This is because choosing \( k \) elements to include is the same as choosing \( n-k \) elements to exclude.
Factorial Function in Mathematics
The factorial function plays a central role in combinatorics and is denoted by an exclamation point \(!\). For any non-negative integer \( n \), the factorial \( n! \) is defined as the product of all positive integers less than or equal to \( n \). In other words, \( n! = n \times (n-1) \times (n-2) \times \ldots \times 2 \times 1 \). For example, \( 5! = 5 \times 4 \times 3 \times 2 \times 1 = 120 \).

There are two special cases to note: \( 0! \) is defined to be 1, and by convention, \( n! \) for negative integers is not defined. The factorial function grows very rapidly with \( n \) and is used in calculating permutations, combinations, and in many types of mathematical series. This explosive growth is also why factorials are used less in expressions for larger values of \( n \) and are often simplified or approximated in different ways.
Mathematical Induction
Mathematical induction is a powerful proof technique used extensively in mathematics, especially to prove that a statement is true for all natural numbers. It consists of two essential steps: the base case and the inductive step.

The base case verifies that the statement holds for the initial value in the sequence, often \( n=0 \) or \( n=1 \) in many cases. Once the base case is established, the inductive step is used to show that if the statement holds for an arbitrary natural number \( n \), then it must also be true for \( n+1 \).

If both steps can be completed successfully, then by induction, the statement is proven to be true for all natural numbers. This proof technique is akin to a row of dominos falling; if you tip over the first one (the base case), and show that each domino will knock over the next (the inductive step), you can be confident that all the dominos will fall (the statement holds for all natural numbers).

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Most popular questions from this chapter

If \(n\) is a positive integer and \(n>1\), prove that \(\left(\begin{array}{c}n \\\ 2\end{array}\right)+\left(\begin{array}{c}n-1 \\ 2\end{array}\right)\) is a perfect square. 7\. A committee of 12 is to be selected from 10 men and 10 women. In how many ways can the selection be carried out if (a) there are no restrictions? (b) there must be six men and six women? (c) there must be an even number of women? (d) there must be more women than men? (e) there must be at least eight men?

a) Determine the value of the integer variable counter af- ter execution of the following program segment. (Here \(i\), \(j\), and \(k\) are integer variables.) $$ \begin{array}{l}\text { Counter }:=0 \\ \text { for } i:=1 \text { to } 12 \mathrm{do} \\ \text { counter }:=\text { counter }+1 \\ \text { for } j:=5 \text { to } 10 \text { do } \\ \text { counter }:=\text { counter }+2 \\\ \text { for } k:=15 \text { downto } 8 \text { do } \\ \text { counter }:\end{array} $$ counter \(+3\) b) Which counting principle is at play in part (a)?

a) In how many ways can 17 be written as a sum of 2 's and 3 's if the order of the summands is (i) not relevant? (ii) relevant? b) Answer part (a) for 18 in place of 17 .

In the Internet each network interface of a computer is assigned one, or more, Internet addresses. The nature of these Internet addresses is dependent on network size. For the Internet Standard regarding reserved network numbers (STD 2), each address is a 32 -bit string which falls into one of the following three classes: (1) A class A address, used for the largest networks, begins with a 0 which is then followed by a seven-bit network number, and then a 24-bit local address. However, one is restricted from using the network numbers of all 0 's or all 1's and the local addresses of all 0 's or all 1's. (2) The class B address is meant for an intermediate-sized network. This address starts with the two-bit string 10, which is followed by a 14-bit network number and then a 16 -bit local address. But the local addresses of all 0 's or all 1's are not permitted. (3) Class C addresses are used for the smallest networks. These addresses consist of the three-bit string 110 , followed by a 21 -bit network number, and then an eight-bit local address. Once again the local addresses of all 0 's or all 1's are excluded. How many different addresses of each class are available on the Internet, for this Internet Standard?

Write a computer program (or develop an algorithm) to list the integer solutions for a) \(x_{1}+x_{2}+x_{3}=10, \quad 0 \leq x_{l}, \quad 1 \leq i \leq 3\) b) \(x_{1}+x_{2}+x_{3}+x_{4}=4, \quad-2 \leq x_{i}, \quad 1 \leq i \leq 4\)

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