/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 18 The sequence \(6,15,24,33,42, \l... [FREE SOLUTION] | 91Ó°ÊÓ

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The sequence \(6,15,24,33,42, \ldots\) is an example of an arithmetic sequence - each term is generated by adding a constant, in this case \(9,\) to the previous term. The sequence \(6,12,24,48,96, \ldots\) is an example of a geometric sequence - each term is generated by multiplying the previous term by a constant, in this case 2 . Find the missing terms assuming each pattern is an arithmetic sequence, and then find the missing terms assuming each pattern is a geometric sequence. a. \(10,\text{_}, 40,...\) b. \(2,\text{_}, 50,...\) c. \(4,\text{_}, 36,...\)

Short Answer

Expert verified
a. Arithmetic: 10, 20, 30, 40; Geometric: 10, 20, 40.b. Arithmetic: 2, 18, 34, 50 ; Geometric: 2, 16, 50.c. Arithmetic:4, 20, 12,36/ Geometric -4,8..)

Step by step solution

01

Understand the Patterns

Identify which sequence is arithmetic and which one is geometric for each pattern. Verify the pattern by checking the differences (for arithmetic) or the ratios (for geometric).
02

Arithmetic Sequence Analysis

For each pattern, determine the common difference by using the given terms. For example, in part (a) for the arithmetic sequence, if the first term is 10 and the interval between terms will make the second term 40, the difference is (40-10)/3 = 10.
03

Arithmetic Sequences Calculation

a. Given 10,_,40 and common difference 10:Let the missing term be denoted by x.10 + x + 10 + 10 = 40 implying x + 30 = 40Hence x = 30.So, the arithmetic sequence becomes: 10, 20, 30, 40.b. Given 2, _, 50:The common difference is (50-2)/3= 16.So second term: 2 + x + 16 = 50. x+ 40 =50. Hence x=14.So the arithmetic sequence becomes: 2, 18, 34, 50.c. Given 4, _, 36:The first and second terms (in 4+ x+4*8 =36) implies 4+4=8. Hence x =12.So the arithmetic sequence becomes: 4, 20, 12, 36.
04

Geometric Sequence Analysis

For geometric sequences, determine the common ratio by using the given terms. For example, in part (a) for the geometric sequence, if the first term is 10 and final (third) term is 40, the ratio 40/10 for the second term generalises by x typically.
05

Geometric Sequences Calculation

For part(a):Given: 10, _, 40. The common ratio can be calculated (40/10)^1/2 = 2.So, the geometric sequence correctly becomes: 10, 20, (20*1/2)=20. Part (b):Given: 2, _, 50. To find common ratio x/x+m= 4/3. (50/2)^(1/3) for m, x.(8)=20.geometric sequence correctly : 2, _, 50.Part (c):Given 4, given 16th (consider aligning 50/4= 1.Ratio for geometric); So 4, 8, (32)=4.So sequence; correct geometric: 4. 8 .ratios.
06

Final Sequences

Final combined forms for arithmetic-geometric sequences.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

arithmetic sequences
An arithmetic sequence is a list of numbers where each term is obtained by adding a constant value, called the common difference, to the preceding term. For example, consider the sequence 6, 15, 24, 33, 42, .... Here, the common difference is 9 because each term increases by 9. The formula for finding the n-th term of an arithmetic sequence is:

\[ a_n = a_1 + (n-1)d \]

where \(a_n\) is the n-th term, \(a_1\) is the first term, and \(d\) is the common difference. Let's break it down with an example: if we have the sequence 10, _, 40, and we need to find the missing term, we observe that the common difference is

\[ d = (40 - 10)/3 = 10. \]

Thus, the sequence becomes 10, 20, 30, 40.
geometric sequences
A geometric sequence is a list of numbers where each term is obtained by multiplying the preceding term by a constant value, called the common ratio. For example, in the sequence 6, 12, 24, 48, 96, ..., the common ratio is 2 because each term is multiplied by 2. The formula for finding the n-th term of a geometric sequence is:

\[ a_n = a_1 \times r^{(n-1)} \]

where \(a_n\) is the n-th term, \(a_1\) is the first term, and \(r\) is the common ratio. For instance, if we have the sequence 10, _, 40 and need to find the missing term, we determine that the common ratio is

\[ r = \frac{40}{10} = 2. \]

Thus, the sequence is 10, 20, 40.
common difference
The common difference is a crucial element in arithmetic sequences. It is the number added to each term to get the next term. To find the common difference, we subtract the first term from the second term. The common difference (\(d\)) can be positive, negative, or zero, which influences the nature of the sequence:
  • If \(d\) is positive, the sequence increases.
  • If \(d\) is negative, the sequence decreases.
  • If \(d\) is zero, all terms in the sequence are the same.
Let's revisit the sequence 2, _, 50. From the exercise solution, the common difference is \[ d = \frac{50 - 2}{3} = 16. \] Thus, our arithmetic sequence will be 2, 18, 34, 50.
common ratio
The common ratio is fundamental in geometric sequences. It is the factor by which we multiply each term to obtain the following term. To find the common ratio (\(r\)), we divide the second term by the first term. Similar to the common difference, the sign and value of the common ratio determine the sequence's behavior:
  • If \(r\) is greater than 1, the sequence grows.
  • If \(r\) is between 0 and 1, the sequence shrinks.
  • If \(r\) is negative, the sequence alternates sign.
For instance, in the sequence 2, _, 50, we find the common ratio is \[ r = \frac{50}{2} = 25. \] Therefore, the geometric sequence is 2, 8, 50.
sequence analysis
Sequence analysis involves identifying whether a sequence is arithmetic or geometric and then determining the common difference or common ratio. This helps in predicting future terms of the sequence. Steps for sequence analysis include:
  • Identify the type of sequence: Check the difference or ratio between terms.
  • Calculate the common value: Subtract (for arithmetic) or divide (for geometric) terms.
  • Predict future terms: Use the identified pattern to find missing terms.
Let’s analyze the sequence 4, _, 36. If it’s an arithmetic sequence, given the first and last terms, we find the common difference as: \[ d = \frac{36 - 4}{3} = 32. \] Therefore, the arithmetic sequence is 4, 20, 36. Similarly, for a geometric sequence, the common ratio is: \[ r = \frac{36}{4} = 9. \] Thus, the sequence is 4, 8, 16, 36.

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Most popular questions from this chapter

In Exercises \(13-16\), use a proportion to solve the problem. Altor and Zenor are ambassadors from Titan, the largest moon of Saturn. The sum of the lengths of any Titan's antennae is a direct measure of that Titan's age. Altor has antennae with lengths \(8 \mathrm{cm}\) \(10 \mathrm{cm}, 13 \mathrm{cm}, 16 \mathrm{cm}, 14 \mathrm{cm},\) and \(12 \mathrm{cm}\) Zenor is 130 years old, and her seven antennae have an average length of \(17 \mathrm{cm}\) How old is Altor? (IMAGE CAN'T COPY)

In Exercises \(4-12,\) solve the proportion. \(\frac{10}{10+z}=\frac{35}{56}\)

The ratio of the surface areas of two cubes is \(\frac{49}{81} .\) What is the ratio of their volumes?

Consider the pattern \(10, x, 40, \ldots\) a. If the pattern is an arithmetic sequence, the value of \(x\) is called the arithmetic mean of 10 and \(40 .\) Use your algebra skills to explain how to calculate the arithmetic mean of any two numbers. b. If the pattern is a geometric sequence, the positive value of \(x\) is called the geometric mean of 10 and \(40 .\) Use your algebra skills to explain how to calculate the geometric mean of any two positive numbers. c. For any two positive numbers, the ratio of the smaller number to their geometric mean is equal to the ratio of the geometric mean to the larger number. Find the formula for the geometric mean of \(a\) and \(b\) by solving the proportion \(\frac{a}{c}=\frac{c}{b}\) for \(c\) Are there any values for which this formula isn't true? d. Use this formula to find the geometric mean of 2 and \(50,\) and of 4 and 36

Draw an obtuse triangle. a. Use a compass and straightedge to construct two altitudes. b. Use a ruler to measure both altitudes and their corresponding bases. c. Calculate the area using both altitude-base pairs. Compare your results.

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