Chapter 9: Problem 4
Write an equation of a quadratic function that corresponds to each pair of \(x\)-intercepts. Assume there is no vertical stretch or shrink. a. \(2.5\) and \(-1\) (a) b. \(-4\) and \(-4\) c. \(-2\) and 2 d. \(r_{1}\) and \(r_{2}\)
Short Answer
Expert verified
(a) \(f(x) = x^2 - 1.5x - 2.5\); (b) \(f(x) = x^2 + 8x + 16\); (c) \(f(x) = x^2 - 4\); (d) \(f(x) = (x - r_1)(x - r_2)\).
Step by step solution
01
Understand the Quadratic Function
A quadratic function with given \(x\)-intercepts \((q_1, 0)\) and \((q_2, 0)\) can be expressed as \(f(x) = a(x - q_1)(x - q_2)\). If there is no vertical stretch or shrink, \(a = 1\).
02
Determine the Equation for Pair (a)
The \(x\)-intercepts given are \(2.5\) and \(-1\), meaning \(q_1 = 2.5\) and \(q_2 = -1\). Substitute these into the equation: \(f(x) = (x - 2.5)(x + 1)\).
03
Simplify the Equation for Pair (a)
Expand \((x - 2.5)(x + 1)\) to find \(f(x) = x^2 - 1.5x - 2.5\).
04
Determine the Equation for Pair (b)
For \(x\)-intercepts \(-4\) and \(-4\), \(q_1 = q_2 = -4\). The function is \(f(x) = (x + 4)^2\).
05
Simplify the Equation for Pair (b)
Expand \((x + 4)^2\) to find \(f(x) = x^2 + 8x + 16\).
06
Determine the Equation for Pair (c)
For \(x\)-intercepts \(-2\) and \(2\), substitute \(q_1 = -2\) and \(q_2 = 2\): \(f(x) = (x + 2)(x - 2)\).
07
Simplify the Equation for Pair (c)
Expand \((x + 2)(x - 2)\) to get \(f(x) = x^2 - 4\).
08
Determine the Equation for Pair (d)
For general \(x\)-intercepts \(r_1\) and \(r_2\), the function is \(f(x) = (x - r_1)(x - r_2)\).
09
Solutions
The solutions to the exercise are: (a) \(f(x) = x^2 - 1.5x - 2.5\) (b) \(f(x) = x^2 + 8x + 16\) (c) \(f(x) = x^2 - 4\) (d) \(f(x) = (x - r_1)(x - r_2)\).
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
x-intercepts
The term "x-intercepts" refers to the points where a graph crosses the x-axis. These points are special because the y-value at these intersections is zero. Understanding x-intercepts is crucial when working with quadratic functions as they provide vital information about the solutions (or roots) of the equation.
To find the x-intercepts of a quadratic function like \[ f(x) = a(x - q_1)(x - q_2) \] set the equation equal to zero: \[ 0 = a(x - q_1)(x - q_2) \]Here,
To find the x-intercepts of a quadratic function like \[ f(x) = a(x - q_1)(x - q_2) \] set the equation equal to zero: \[ 0 = a(x - q_1)(x - q_2) \]Here,
- \(q_1\) and \(q_2\) are the x-intercepts.
- These values of \(x\) make \(f(x) = 0\).
factoring quadratics
Factoring quadratics is a method used to express a quadratic polynomial as a product of its linear factors. This is incredibly helpful when seeking to find the x-intercepts (roots) of the function.
Consider a quadratic function given by:\[ f(x) = ax^2 + bx + c \]To factor this, we aim to rewrite it in terms of two binomials:\[ f(x) = a(x - q_1)(x - q_2) \]Here are key steps to factor a quadratic:
Consider a quadratic function given by:\[ f(x) = ax^2 + bx + c \]To factor this, we aim to rewrite it in terms of two binomials:\[ f(x) = a(x - q_1)(x - q_2) \]Here are key steps to factor a quadratic:
- If possible, find two numbers that multiply to \(c\) and add up to \(b\).
- Use these numbers to express \(bx\) as the sum of two terms, then factor by grouping.
- If the quadratic is in the form \((x - q_1)(x - q_2)\), this reveals the x-intercepts \(q_1\) and \(q_2\).
polynomials
A polynomial is a mathematical expression made up of variables (also called indeterminates) and coefficients, involving operations of addition, subtraction, multiplication, and non-negative integer exponents. Polynomials are foundational in algebra, and they come in many forms.
Quadratic functions are a special type of polynomial and have the general form:\[ f(x) = ax^2 + bx + c \]Here:
Quadratic functions are a special type of polynomial and have the general form:\[ f(x) = ax^2 + bx + c \]Here:
- \(a\), \(b\), and \(c\) are constants where \(a eq 0\).
- The highest power of the variable \(x\) is 2, hence the name quadratic.