/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 10 A bicyclist, \(1 \mathrm{mi}(528... [FREE SOLUTION] | 91Ó°ÊÓ

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A bicyclist, \(1 \mathrm{mi}(5280 \mathrm{ft})\) away, pedals toward you at a rate of \(600 \mathrm{ft} / \mathrm{min}\) for \(3 \mathrm{~min}\). The bicyclist then pedals at a rate of \(1000 \mathrm{ft} / \mathrm{min}\) for the next \(5 \mathrm{~min}\). a. Describe what you think the plot of (time, distance from you) will look like. (a) b. Graph the data using 1 min intervals for your plot. (a) c. Invent a question about the situation, and use your graph to answer the question.

Short Answer

Expert verified
The plot is a decreasing line, which crosses zero at 6 minutes, indicating the bicyclist reaches you then.

Step by step solution

01

Calculate Distance Traveled in First Interval

The bicyclist travels for 3 minutes at a speed of 600 ft/min. To find the distance covered in this interval, multiply the speed by the time: \[ \text{Distance} = 600 \text{ ft/min} \times 3 \text{ min} = 1800 \text{ ft}. \]
02

Calculate Distance Traveled in Second Interval

The bicyclist then increases speed to 1000 ft/min and pedals for 5 minutes. Calculate the distance covered in this interval: \[ \text{Distance} = 1000 \text{ ft/min} \times 5 \text{ min} = 5000 \text{ ft}. \]
03

Total Distance Traveled

Add the distances from the two intervals to find the total distance traveled: \[ \text{Total Distance} = 1800 \text{ ft} + 5000 \text{ ft} = 6800 \text{ ft}. \]
04

Determine Remaining Distance after First Interval

Initially, the bicyclist is 5280 ft away (1 mile). After traveling 1800 ft, the remaining distance is: \[ \text{Remaining Distance} = 5280 \text{ ft} - 1800 \text{ ft} = 3480 \text{ ft}. \]
05

Determine Remaining Distance after Second Interval

Subtract the distance traveled in the second interval from the remaining distance: \[ \text{Remaining Distance} = 3480 \text{ ft} - 5000 \text{ ft}. \]This results in a negative value meaning the bicyclist has surpassed you by 1520 ft: \[ 5000 \text{ ft} - 3480 \text{ ft} = 1520 \text{ ft}. \]
06

Describe the Plot Shape

The plot of time versus distance starts at 5280 ft and decreases linearly at first, then more steeply, reaching a distance of 0 and going negative; the line will cross the x-axis and dip below as the bicyclist surpasses the starting point.
07

Graphing the Data

Using 1-minute intervals from 0 to 8 minutes: - 0 min: 5280 ft - 1 min: 4680 ft - 2 min: 4080 ft - 3 min: 3480 ft - 4 min: 2480 ft - 5 min: 1480 ft - 6 min: 480 ft - 7 min: -520 ft - 8 min: -1520 ft Plot these points and connect them with lines to represent the journey.
08

Invent and Answer a Question

Question: At what time does the bicyclist reach you? Answer: From the graph, the bicyclist reaches you around 6 minutes when the distance is 0.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

distance-time graph
Distance-time graphs are a fundamental tool in illustrating how the distance between two points changes over time. These graphs help us visualize movement scenarios, where distance is plotted on the vertical axis (y-axis) and time is plotted on the horizontal axis (x-axis). This results in a clear graphical representation of an object's motion.
For our example, the bicyclist starts 5280 feet away from you and moves closer over time. On such a graph:
  • A horizontal line indicates the object is stationary, as time passes without any change in distance.
  • A line sloping downwards indicates a closing gap, which in our scenario occurs as the bicyclist approaches you.
  • If the line crosses the x-axis and goes lower, it means the bicyclist has passed the initial point of reference and is now beyond you in the opposite direction.
Understanding these visual cues on distance-time graphs is crucial for analyzing how an object's motion evolves over time, making it easier to answer questions like when two objects meet or overtake one another.
linear equations
Linear equations are equations of the first degree, meaning they involve only linear terms and can be graphed as straight lines on a coordinate plane. They are foundational for constructing distance-time graphs because they model relationships with a constant rate of change. In our scenario of the bicyclist, linear equations can express the relationship between time and distance traveled.
Let's denote the distance from you by the formula:\[D = D_0 - vt\]where:
  • \(D\) is the remaining distance from you,
  • \(D_0\) is the initial distance (5280 ft),
  • \(v\) is the speed at which the bicyclist is traveling (600 ft/min or 1000 ft/min),
  • \(t\) is the time in minutes.
By substituting the values into this equation for different segments of time, we derive linear equations that describe each part of the bicyclist's journey. These help to anticipate whether, when, and by how much the bicyclist will pass the initially observed point.
graphing techniques
Effective graphing techniques are essentials in illustrating mathematical relationships and interpreting data clearly. When constructing distance-time graphs like the one required for the bicyclist's journey, it's important to follow systematic steps to ensure accuracy.
  • **Mark the Axes**: First, label your horizontal axis as 'Time (min)' and your vertical axis as 'Distance from You (ft)'. Ensure all units are clearly marked and evenly spaced.
  • **Plotting Points**: Start with the initial measurements and plot points at specified intervals—for our example, every minute across 8 minutes.
  • **Connecting Dots**: Once plotted, connect the points with a line. The slope of these lines will visually show how the speed changes the distance over time.
    A steeper slope signifies a faster speed (as seen when the bicyclist increases speed in the example).
  • **Analysis**: Use the resulting graph to draw conclusions about the motion, such as identifying when the bicyclist reached you.
Employing proper graphing techniques not only aids in accurately depicting the data but also helps in interpreting various mathematical and real-world scenarios effectively.

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