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APPLICATION Zoe is an intern at Yellowstone National Park. One of her jobs is to estimate the chipmunk population in the campground areas. She starts by trapping 60 chipmunks, giving them a checkup, and banding their legs. A few weeks later, Zoe traps 84 chipmunks. Of these, 22 have bands on their legs. How many chipmunks should Zoe estimate are in the campgrounds?

Short Answer

Expert verified
Approximately 229 chipmunks are estimated to be in the campgrounds.

Step by step solution

01

Understanding the Problem

Zoe trapped and banded 60 chipmunks initially. In a later trapping of 84 chipmunks, 22 were found with bands. We need to estimate the total chipmunk population.
02

Setting Up Proportions

We can use the capture-recapture method, where the ratio of banded to non-banded chipmunks in the recapture is assumed to be the same as the ratio in the total population. So, we set up the proportion: \( \frac{22}{84} = \frac{60}{N} \), where \( N \) is the total chipmunk population.
03

Solving the Proportion

Cross-multiply to solve for \( N \). We have \( 22N = 60 \times 84 \). Calculating this gives \( 22N = 5040 \).
04

Finding the Total Population

To find \( N \), divide both sides of the equation by 22: \( N = \frac{5040}{22} \). Calculating this results in \( N \approx 229 \).
05

Conclusion

Zoe should estimate that there are approximately 229 chipmunks in the campground areas.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Proportion
Proportion is a mathematical concept that involves two ratios being equal. It allows us to relate quantities in a way that when one of them changes, the other changes proportionally. In the context of the capture-recapture method used by Zoe, proportion is key in estimating the chipmunk population.
The proportion in this scenario is based on the principle that the ratio of marked to unmarked animals in a sample reflects the ratio in the entire population. Zoe initially banded 60 chipmunks and later caught a total of 84 chipmunks, 22 of which had bands. We set up a proportion based on these numbers:
\[ \frac{22}{84} = \frac{60}{N} \] Here, \( \frac{22}{84} \) is the observed ratio of marked chipmunks in the second sample, and \( \frac{60}{N} \) is the expected ratio of marked chipmunks in the entire chipmunk population, which we are trying to find. By solving this equation, we apply proportions to estimate the total number \( N \) of chipmunks.
Wildlife Population Estimation
Wildlife population estimation is crucial for conservation and ecology research. One popular technique is the capture-recapture method, which helps estimate animal populations in a specific area. This method involves capturing a number of individuals, marking them, and then releasing them back into their habitat. After some time, another capture is done to see how many of the marked individuals are recaptured.
The capture-recapture method assumes that the proportion of marked individuals in a sample matches that in the entire population, given that all individuals have an equal chance of being captured. This method is especially useful in settings where a complete count of the animal population is impractical.
This model hinges on a few assumptions, such as the marked individuals being randomly mixed within the whole population, all individuals having the same chance of being captured, and no changes in the population due to migration, births, or deaths between samplings. These assumptions ensure the reliability of the estimation.
Problem Solving
The approach to solving problems using mathematical methods often requires several steps, especially when estimating wildlife populations. In the given exercise, the solution involves understanding the scenario, setting up an appropriate mathematical model, and solving for the unknown variable.
To solve Zoe's problem of estimating the chipmunk population, it first involves recognizing the relationship between the banded chipmunks and the total population through a simple proportion. By correctly setting up the proportion, as seen in: \[ \frac{22}{84} = \frac{60}{N} \] Next, solving the proportion requires algebraic manipulation and careful calculation. In this case, multiplying both sides and using cross-multiplication to solve for \( N \) involves: \[ 22N = 60 \times 84 \] Finally, divide by 22 to isolate \( N \) which results in: \[ N \approx 229 \] Using such a methodological approach helps break down complex problems into smaller, manageable steps. This structured problem-solving method is vital in various fields beyond wildlife studies as well.

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Most popular questions from this chapter

Taya is a contestant on a television quiz show. If she answers the next question correctly, she will win \(\$ 16,000\). If she misses the question, she will receive only \(\$ 1,000\). The question is multiple choice, and Taya has no idea what the correct answer is, so she will randomly choose one of the four answers. a. What is the expected value of Taya's earnings for the next question? (a) b. If Taya can eliminate one answer and her probability of answering correctly is now one-third, what is the expected value?

The Square Deal Electronics store is having a sale. If you buy a TV, you can get a DVD player for a special price. You roll a die and pay the square of the number rolled for the DVD player (a \(\$ 50\) value). a. If you roll a 3 , how much will you pay for the DVD player? b. What is the probability that you will roll a 3 ? c. What is the expected payment for the DVD player? d. What does this number mean to the store?

Perform each operation and combine like terms. a. \(\left(x^{2}+5 x-4\right)-\left(3 x^{3}-2 x^{2}+6\right)\) b. \((x+7)\left(x^{4}-4 x\right)\) c. \(3 x+7(x+y)-4 y(x-8)\)

You are packing your suitcase for a weekend trip. Create a scenario for each expression. (For example, for \(9 \cdot 8 \cdot 7=504\), you might answer: I have 9 shirts and I pack 3 in the order I will wear them. There are 504 ways to do this.) a. \({ }_{8} P_{2}=56\) b. \(\frac{12 \cdot 11 \cdot 10 \cdot 9}{4 \cdot 3 \cdot 2 \cdot 1}=495\) c. \({ }_{6} C_{2}=15\)

If you flip a paper cup into the air, what are the possible outcomes? Do you think the outcomes are equally likely? How can you test your conjecture?

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