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Copy and complete this table to determine the expected value of the spinner game shown. \begin{tabular}{|l|c|c|c|c|} \hline Outcome & \(\$ 2\) & \(\$ 5\) & \(\$ 10\) & \\ \hline Probability & \(\frac{1}{3}\) & \(\frac{1}{2}\) & \(\frac{1}{6}\) & Sum \\ \hline Product & & & & \\ \hline \end{tabular}

Short Answer

Expert verified
The expected value of the spinner game is \( \frac{29}{6} \) or \( 4.8333 \).

Step by step solution

01

Identify the Components

The table consists of two rows that contain important information: outcomes and probabilities. The outcomes are monetary winnings designated as \( \\(2 \), \( \\)5 \), and \( \$10 \). The associated probabilities for each outcome are given as \( \frac{1}{3} \), \( \frac{1}{2} \), and \( \frac{1}{6} \) respectively.
02

Compute the Product for Each Outcome

To find the product, multiply each outcome by its probability. This gives:- For \( \\(2 \): \( 2 \times \frac{1}{3} = \frac{2}{3} \)- For \( \\)5 \): \( 5 \times \frac{1}{2} = \frac{5}{2} \)- For \( \$10 \): \( 10 \times \frac{1}{6} = \frac{5}{3} \)
03

Calculate the Expected Value

The expected value is the sum of the products obtained in Step 2. Add these values together to find:\[ \text{Expected Value} = \frac{2}{3} + \frac{5}{2} + \frac{5}{3} \]Convert to a common denominator (6):\[ \frac{2}{3} = \frac{4}{6}, \quad \frac{5}{2} = \frac{15}{6}, \quad \frac{5}{3} = \frac{10}{6} \]Then, add them:\[ \frac{4}{6} + \frac{15}{6} + \frac{10}{6} = \frac{29}{6} \]
04

Verify the Probability Sum

Ensure the sum of all probabilities is 1. Given probabilities are \( \frac{1}{3} + \frac{1}{2} + \frac{1}{6} \). Convert these probabilities to a common denominator (6) before adding:\[ \frac{1}{3} = \frac{2}{6}, \quad \frac{1}{2} = \frac{3}{6}, \quad \frac{1}{6} = \frac{1}{6} \]Sum these values:\[ \frac{2}{6} + \frac{3}{6} + \frac{1}{6} = \frac{6}{6} = 1 \]Since the probabilities sum to 1, they are correct.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Probability
Probability is a concept that measures the likelihood of an event occurring. It ranges from 0 to 1, where 0 means the event will not happen, and 1 means it will happen for sure.
For instance, in the spinner game, each outcome like winning \(2, \)5, or $10 has its own probability. These probabilities tell us how likely each outcome is when you spin the spinner.
The probabilities for the outcomes in the table are \(\frac{1}{3}\), \(\frac{1}{2}\), and \(\frac{1}{6}\). When combined, they must add up to 1 to show a complete set of possible outcomes. This ensures we account for every possible result of spinning the spinner.
Outcome
An outcome is the result of a random event. In our context, the "outcome" is what you get when you spin the game wheel.
Each slice of the spinner is an outcome with a specific monetary win, like $2, $5, or $10. The actual winnings depend on where the spinner arrow lands.
Knowing the possible outcomes is crucial for calculating the expected value because they determine the rewards associated with each spin.
It's important to remember that even unlikely outcomes still affect the total expected value. Probabilities accompanying each outcome predict long-term averages when the game is played many times.
Spinner Game
A spinner game involves a circular wheel divided into segments, each representing a different outcome with its own probability. It's a fun way to understand probability in a visually engaging format.
In our exercise, the spinner is labeled with monetary outcomes: $2, $5, and $10, each segment with an associated probability.
As you spin the wheel, the arrow will eventually point to one segment, determining the outcome. The randomness of each spin makes spinner games an excellent example to study mathematical expectation and probability models.
It represents real-world uncertainty and helps in learning how to calculate expected outcomes effectively over numerous attempts.
Mathematical Expectation
Mathematical expectation, often referred to as expected value, is an average value someone can expect over many trials of a random activity.
Calculating it involves multiplying each outcome by its probability and adding these products together. This gives us an idea of what we might "expect" to win or lose on average after spinning the wheel many times.
Using our exercise, we multiply each monetary value by its probability: \(2 by \(\frac{1}{3}\), \)5 by \(\frac{1}{2}\), and $10 by \(\frac{1}{6}\). Adding up these values, we find that the expected value of the game is \(\frac{29}{6}\).
Understanding mathematical expectation helps us make better decisions in situations involving chance. It can reveal whether a game is favorable or not based on expected returns.

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Most popular questions from this chapter

A chili recipe calls for seven ingredients: ground beef, onions, beans, tomatoes, peppers, chili powder, and salt. There are no directions about the order in which the ingredients should be combined. You decide to add the ingredients in a random order. a. How many different arrangements are there? b. What is the probability that onions are first? c. What is the probability that the order is exactly as listed above? d. What is the probability that the order isn't exactly as listed above? e. What is the probability that beans are third?

A thumbtack can land "point up" or "point down." a. When you drop a thumbtack on a hard surface, do you think the two outcomes will be equally likely? If not, what would you predict for \(P(\) up \()\) ? (a) b. Drop a thumbtack 100 times onto a hard surface, or drop 10 thumbtacks 10 times. Record the frequency of "point up" and "point down." What are your experimental probabilities for the two responses? c. Make a prediction for the probabilities on a softer surface like a towel. Repeat the experiment over a towel. What are your experimental probabilities?

Cheryl plays on the school basketball team. When shooting free throws, she makes \(75 \%\) of her first shots, and \(80 \%\) of her second shots provided she makes the first one. However, if she misses the first shot, she makes only half of her second shots. Each free throw is worth one point. a. Draw a tree diagram of a two-shot attempt. What is the probability that she will make both shots? (a) b. What is the expected number of points that Cheryl will make in a two-shot free throw attempt? (a) c. If Cheryl has five chances to shoot two free throws in a game, how many points can she expect to make? (a)

You are packing your suitcase for a weekend trip. Create a scenario for each expression. (For example, for \(9 \cdot 8 \cdot 7=504\), you might answer: I have 9 shirts and I pack 3 in the order I will wear them. There are 504 ways to do this.) a. \({ }_{8} P_{2}=56\) b. \(\frac{12 \cdot 11 \cdot 10 \cdot 9}{4 \cdot 3 \cdot 2 \cdot 1}=495\) c. \({ }_{6} C_{2}=15\)

Create a tree diagram with probabilities showing outcomes when drawing two marbles without replacement from a bag containing one blue and two red marbles. (You do not replace the first marble drawn from the bag before drawing the second.) (a)

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