/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 24 Write a word problem that illust... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

Write a word problem that illustrates \(\frac{3}{4} \cdot \frac{1}{3}\), and find the answer.

Short Answer

Expert verified
You need \( \frac{1}{4} \) cup of sugar.

Step by step solution

01

Understand the Problem Components

We need to write a word problem that involves fractions and multiplication. Specifically, we have two fractions: \( \frac{3}{4} \) and \( \frac{1}{3} \).
02

Drafting the Word Problem

A word problem involving these fractions could be about a recipe or a task being divided into smaller parts. For example: *"If a recipe needs \( \frac{3}{4} \) cup of sugar, and you want to make only one-third of the recipe, how much sugar will you need?"*
03

Set Up the Equation

In the context of the word problem, we want to multiply \( \frac{3}{4} \) by \( \frac{1}{3} \). This represents finding one-third of three-fourths of a cup of sugar.
04

Perform the Multiplication

To multiply the fractions \( \frac{3}{4} \) and \( \frac{1}{3} \), you multiply the numerators together and the denominators together: \( \frac{3 \times 1}{4 \times 3} = \frac{3}{12} \).
05

Simplify the Result

Simplify the fraction \( \frac{3}{12} \). The greatest common divisor of 3 and 12 is 3. Divide both the numerator and the denominator by 3: \( \frac{3}{12} = \frac{1}{4} \). Consequently, \( \frac{3}{4} \times \frac{1}{3} = \frac{1}{4} \).
06

Conclusion in the Context of the Problem

Thus, in the context of the word problem, if you only make one-third of the recipe, you will need \( \frac{1}{4} \) cup of sugar.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Word Problem
Word problems are a fantastic way to bring mathematics to life. When crafting a word problem, think about real-life scenarios where fractions and multiplication easily apply.
In this lesson, we created a word problem using fractions. We considered a familiar setting: a recipe.
If a complete recipe requires a set quantity, like \(\frac{3}{4}\) cups of sugar, the word problem introduces an element of scaling by fractions. For instance, if you need to make one-third of this recipe, the word problem asks you to calculate how much sugar is necessary in this reduced quantity.
This approach helps us practice fractions in relatable contexts, making complex concepts more manageable.
When writing your own word problems, try to think of scenarios that require scaling down or modifying quantities to bring multiplication of fractions into the picture.
Multiplication
Multiplication with fractions follows specific rules that make it straightforward, but it's crucial to understand these rules to avoid confusion.
When you multiply two fractions, you're essentially finding a fraction of a fraction. This requires multiplying both the numerators and the denominators of the given fractions.
For example, consider multiplying \(\frac{3}{4}\) by \(\frac{1}{3}\). Multiply the numerators: \(3 imes 1 = 3\). Then, multiply the denominators: \(4 \times 3 = 12\).
This gives you the fraction \(\frac{3}{12}\).
Multiplication in this context is about scaling down or adjusting quantities proportionally, making it a useful operation in everyday situations such as resizing recipes or dividing tasks.
Simplifying Fractions
Simplifying fractions is an essential part of solving fraction problems as it makes it easier to understand and work with the results.
Once you have multiplied fractions and reached a result, you may need to simplify the fraction. Simplifying involves reducing the fraction to its simplest form. This means there are no common factors between the numerator and denominator, other than 1.
In our example, after multiplication, we obtain \(\frac{3}{12}\). The greatest common divisor (GCD) of 3 and 12 is 3.
  • Divide the numerator (3) by the GCD: \(\frac{3}{3} = 1\).
  • Divide the denominator (12) by the GCD: \(\frac{12}{3} = 4\).
This leads to the simplified fraction \(\frac{1}{4}\).
Remembering to simplify fractions will help in keeping numbers manageable and solutions clear.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

If \(x\) represents actual temperature and \(y\) represents wind chill temperature, the equation $$ y=-29+1.4 x $$

The equations \(y=28.65-0.0411(x-1962)\) and \(y=27.5-0.0411(x-1990)\) both model the data for the winning times for the Olympic men's 10,000 -meter race. The variable \(x\) represents the year, and \(y\) represents the winning time, in minutes. a. Find the approximate winning time for the year 1972 given by each equation. What is the difference between the values? b. Find the approximate winning time for the year 2008 given by each equation. What is the difference between the values? c. Select an appropriate window and graph the two equations. d. Do you think these equations represent the same line? Explain your reasoning. (a)

For each description, invent a seven-value data set such that all the values in the set are less than 10 and meet the conditions. a. The box plot represents data with a median that is not inside the box. (a) b. The box plot represents data with an interquartile range of zero. c. The box plot represents data with one outlier on the left. d. The box plot has no right whisker.

The base of a triangle was recorded as \(18.3 \pm 0.1 \mathrm{~cm}\) and the height was recorded as \(7.4 \pm 0.1 \mathrm{~cm}\). These measurements indicate the measured value and an accuracy component. a. Use the formula \(A=0.5 b h\) and the measured values for base and height to calculate the area of the triangle. b. Use the smallest possible lengths for base and height to calculate an area. (a) c. Use the largest possible lengths for base and height to calculate an area. d. Use your answers to \(12 \mathrm{a}-\mathrm{c}\) to express the range of possible area values as a number \(\pm\) an accuracy component. \((A\)

Rewrite each expression as a repeated multiplication in three ways: using \(\times,+\), and parentheses. a. \(3^{4}\) (a) b. \(5^{6}\) c. \(\left(\frac{1}{2}\right)^{3}\)

See all solutions

Recommended explanations on Math Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.