/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 5 Solve each equation symbolically... [FREE SOLUTION] | 91Ó°ÊÓ

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Solve each equation symbolically and check your answer. a. \((x+3)^{2}=7\) b. \((x-2)^{2}-8=13\)

Short Answer

Expert verified
a. Solutions are \(x = \sqrt{7} - 3\) and \(x = -\sqrt{7} - 3\). b. Solutions are \(x = \sqrt{21} + 2\) and \(x = -\sqrt{21} + 2\).

Step by step solution

01

Solving the Equation for Part a

For part a, the equation is \((x+3)^2 = 7\). Start by taking the square root of both sides of the equation to eliminate the square: \[ x + 3 = \pm \sqrt{7} \] This gives us two possible solutions: \[ x + 3 = \sqrt{7} \] or \[ x + 3 = -\sqrt{7} \] Now, solve for \(x\) in both cases.
02

Isolating x for Part a

Subtract 3 from both sides in the two possible equations: For \( x + 3 = \sqrt{7} \): \[ x = \sqrt{7} - 3 \] For \( x + 3 = -\sqrt{7} \): \[ x = -\sqrt{7} - 3 \] Thus, the solutions for part a are \( x = \sqrt{7} - 3 \) and \( x = -\sqrt{7} - 3 \).
03

Solving the Equation for Part b

The equation for part b is \((x-2)^2 - 8 = 13\). Start by isolating the squared term: Add 8 to both sides:\[ (x-2)^2 = 21 \] Now take the square root of both sides to solve for \(x-2\): \[ x - 2 = \pm \sqrt{21} \] Giving two possible solutions.
04

Isolating x for Part b

Add 2 to both sides of each equation:For \( x - 2 = \sqrt{21} \): \[ x = \sqrt{21} + 2 \] For \( x - 2 = -\sqrt{21} \): \[ x = -\sqrt{21} + 2 \] Thus, the solutions for part b are \( x = \sqrt{21} + 2 \) and \( x = -\sqrt{21} + 2 \).
05

Verify Solutions for Part a

To verify, substitute the solutions back into the original equation \((x+3)^2 = 7\): For \(x = \sqrt{7} - 3\): \((\sqrt{7} - 3 + 3)^2 = 7 \) simplifies to \(7\). For \(x = -\sqrt{7} - 3\): \((-\sqrt{7} - 3 + 3)^2 = 7 \) simplifies to also \(7\). Both checks work, confirming the solutions.
06

Verify Solutions for Part b

Substitute the solutions back into the original equation \((x-2)^2 - 8 = 13\): For \(x = \sqrt{21} + 2\): \(((\sqrt{21} + 2) - 2)^2 - 8 = 13 \) simplifies to \(13\). For \(x = -\sqrt{21} + 2\): \(((-\sqrt{21} + 2) - 2)^2 - 8 = 13 \) also simplifies to \(13\). Both checks confirm that the solutions are correct.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Quadratic Equations
A quadratic equation is any equation that you can write in the form \( ax^2 + bx + c = 0 \). This is called the standard form, where \( a \), \( b \), and \( c \) are constants, and \( a eq 0 \). Quadratic equations are often solved by finding values of \( x \) that make the equation true. These values are called the roots or solutions of the equation.
  • Quadratic equations can have two solutions, one solution, or no real solution. When a quadratic equation is symbolic, it might involve variables or constants that can be manipulated algebraically.
  • The solutions of a quadratic equation can be found using various methods, such as factoring, completing the square, or using the quadratic formula.
In symbolic solving, like in the example \((x+3)^2=7\), the expression is already factored in a way that allows easy application of square roots. By reshaping the equation to reveal the squared term, we make it easier to solve.
Quadratics are essential in algebra, showing up in various applications from physics to finance. Understanding their properties and solution methods provides a strong foundation for more advanced math topics!
Square Roots
The square root is a fundamental operation in mathematics, denoted by the symbol \( \sqrt{} \). Finding the square root of a number \( a \) means finding a value \( b \) such that \( b^2 = a \). In the given exercise, we used the property of square roots to solve quadratic equations.
  • To remove a square, take the square root of both sides of the equation. This operation can introduce two possible solutions due to the positive and negative roots (e.g., \( \pm \sqrt{a} \)).
  • Remember that every positive real number has two square roots: one positive (\( \sqrt{a} \)) and one negative (\( -\sqrt{a} \)).
In the context of these equations, the square root assists in breaking down the squared term, isolating \( x \) for clearer solution paths. In \((x - 2)^2 = 21\), taking the square root gave us \( x - 2 = \pm \sqrt{21} \).
This practice is common in algebra, allowing us to solve quadratics that aren't easily factored by other means. By understanding square roots, we handle a broader range of equations effectively!
Verification of Solutions
Verifying solutions is a crucial step in problem-solving as it confirms that the obtained solution satisfies the original equation. This means substituting the potential solutions back into the original equation and checking for consistency.
  • To verify, substitute each value or expression from your solutions back into the original quadratic equation.
  • Perform the mathematical operations as indicated and ensure that the left side equals the right side of the original equation.
For instance, when verifying the solution \( x = \sqrt{7} - 3 \) for the equation \((x+3)^2 = 7\), substituting \( \sqrt{7} - 3+3 \) simplifies to \( 7 \), confirming our solution is correct.
Verification is a powerful method to ensure correctness and is especially useful if you've used multiple steps or operations where error might have crept in. It solidifies your understanding and verifies that the symbolic manipulations were done correctly!

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Most popular questions from this chapter

The rate at which a bear population grows in a park is given by the equation \(P(b)=0.001 b(100-b)\). The function value \(P(b)\) represents the rate at which the population is growing in bears per year, and \(b\) represents the number of bears. a. Find \(P(10)\) and provide a real-world meaning for this value. (a) b. Solve \(P(b)=0\) and provide real-world meanings for these solutions. (I) c. For what size bear population would the population grow fastest? d. What is the maximum number of bears the park can support? e. What does it mean to say that \(P(120)<0\) ?

If you know the vertex and one other point on a parabola, you can find its quadratic equation. The vertex \((h, k)\) of this parabola is \((2,-31.5)\), and the other point is \((5,0)\). a. Substitute the values for \(h\) and \(k\) into the equation \(y=a(x-h)^{2}+k\). b. To find the value of \(a\), substitute 5 for \(x\) and 0 for \(y\). Then solve for \(a\). c. Use the \(a\)-value you found in \(5 \mathrm{~b}\) to write the equation of the graph in vertex form. d. Use what you learned in \(5 a-c\) to write the equation of the graph whose vertex is \((2,32)\) and that passes through the point \((5,14)\).

Use a symbolic method to solve each equation. Show each solution exactly as a rational or a radical expression. a. \(x^{2}=18\) b. \(x^{2}+3=52\) c. \((x-2)^{2}=25\) d. \(2(x+1)^{2}-4=10\) (?)

Solve each equation by converting to the form \(a x^{2}+b x+c=0\) if necessary, then factoring and using the zero-product property. Verify your answers using substitution. a. \(x^{2}-4 x=0\) b. \(x^{2}+2 x-3=0\) c. \(x^{2}-3 x=4\) d. \(2 x^{2}-11 x+15=0\) e. \(5 x^{2}-13 x+8=0\) f. \(3 x^{2}-8=-5 x\)

Sketch the graph of a quadratic function with a. One \(x\)-intercept. b. Two \(x\)-intercepts. c. Zero \(x\)-intercepts. d. The vertex in the first quadrant and two \(x\)-intercepts.

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