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Reduce the rational expressions by dividing out common factors from the numerator and denominator. State any restrictions on the variable. (7) a. \(\frac{(x-2)(x+2)}{(x+2)(x+3)}\) (a) b. \(\frac{x^{2}+3 x+2}{(x-4)(x+2)}\) c. \(\frac{x^{2}-3 x-10}{x^{2}-5 x}\) (d) d. \(\frac{x^{2}+2 x-3}{x^{2}+5 x+6}\) c. \(\frac{x^{2}+x-6}{x^{2}+6 x+9}\)

Short Answer

Expert verified
a. \(\frac{x-2}{x+3}\), \(x \neq -2, -3\); b. \(\frac{x+1}{x-4}\), \(x \neq -2, 4\); c. \(\frac{x+2}{x}\), \(x \neq 0, 5\); d. \(\frac{x-1}{x+2}\), \(x \neq -2, -3\); e. \(\frac{x-2}{x+3}\), \(x \neq -3\).

Step by step solution

01

Identify and Cancel Common Factors - Part a

Consider the expression \( \frac{(x-2)(x+2)}{(x+2)(x+3)} \). Both the numerator and the denominator share the common factor \((x+2)\). Divide out this common factor, and the simplified expression becomes \( \frac{x-2}{x+3} \).
02

Determine Restrictions - Part a

Restrictions exist where the original denominator is equal to zero. Set each factor in the denominator, \((x+2)(x+3)\), to zero. This gives the restrictions: \(x eq -2\), \(x eq -3\).
03

Factor the Expression - Part b

Start with the expression \( \frac{x^2+3x+2}{(x-4)(x+2)} \). Factor the numerator: \(x^2+3x+2 = (x+1)(x+2)\). The expression becomes \( \frac{(x+1)(x+2)}{(x-4)(x+2)} \).
04

Cancel Common Factors - Part b

Notice that \((x+2)\) is a common factor in the numerator and denominator. Cancel \((x+2)\) from both, leaving \( \frac{x+1}{x-4} \).
05

Determine Restrictions - Part b

For restrictions, set the original denominator to zero: \((x-4)(x+2)\). Solving these gives: \(x eq 4\), \(x eq -2\).
06

Factor the Expression - Part c

Consider the expression \( \frac{x^2-3x-10}{x^2-5x} \). Factor the numerator as \((x-5)(x+2)\) and the denominator as \(x(x-5)\). The expression becomes \( \frac{(x-5)(x+2)}{x(x-5)} \).
07

Cancel Common Factors - Part c

Cancel the common factor \((x-5)\) from both numerator and denominator, giving \( \frac{x+2}{x} \).
08

Determine Restrictions - Part c

To find restrictions, solve the original denominator \(x(x-5) = 0\). This gives the restrictions: \(x eq 0\), \(x eq 5\).
09

Factor the Expression - Part d

Given the expression \( \frac{x^2+2x-3}{x^2+5x+6} \), factor the numerator as \((x-1)(x+3)\) and the denominator as \((x+2)(x+3)\). The expression is \( \frac{(x-1)(x+3)}{(x+2)(x+3)} \).
10

Cancel Common Factors - Part d

Notice that \((x+3)\) is a common factor. Cancel it to simplify the expression to \( \frac{x-1}{x+2} \).
11

Determine Restrictions - Part d

Solve for when the original denominator \((x+2)(x+3) = 0\). This gives the restrictions: \(x eq -2\), \(x eq -3\).
12

Factor the Expression - Part e

Consider the expression \( \frac{x^2+x-6}{x^2+6x+9} \). Factor the numerator as \((x-2)(x+3)\) and denominator as \((x+3)^2\). The expression becomes \( \frac{(x-2)(x+3)}{(x+3)^2} \).
13

Cancel Common Factors - Part e

Cancel the common factor \((x+3)\) from numerator and denominator, resulting in \( \frac{x-2}{x+3} \).
14

Determine Restrictions - Part e

Find where the original denominator \((x+3)^2 = 0\). Since \(x+3 = 0\), the restriction is: \(x eq -3\).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Factoring Polynomials
Factoring polynomials is a fundamental skill when working with rational expressions. It involves breaking down a polynomial into simpler components called factors which, when multiplied, recreate the original polynomial. This process is crucial for simplifying expressions or finding the roots of equations.
For example, when factoring the polynomial \(x^2 + 3x + 2\), we look for two numbers that multiply to 2 and add to 3. The factors turn out to be \((x+1)\) and \((x+2)\). Hence, \(x^2 + 3x + 2\) can be rewritten as \((x+1)(x+2)\).
  • Finding the Greatest Common Factor (GCF) makes factoring easier by simplifying each term.
  • Using methods like grouping, the quadratic formula, or special patterns (like square of a binomial) helps in factorizing different types of polynomials.
Mastery in factoring allows you to simplify complex expressions more efficiently by first making them manageable. Through practice, identifying these patterns and factors becomes intuitive.
Simplifying Expressions
Simplifying expressions involves reducing them to their most basic form. For rational expressions, this often means canceling out common factors in the numerator and denominator. The aim is to make expressions easier to work with and understand.
Let's look at the expression \( \frac{(x-2)(x+2)}{(x+2)(x+3)} \). Here, \((x+2)\) appears in both the numerator and denominator, making it a common factor. By canceling \((x+2)\) in both places, the expression reduces to \( \frac{x-2}{x+3} \).
  • Ensure both the numerator and denominator are fully factored before canceling common factors.
  • Double-check for remaining factors that could be further simplified.
This process not only simplifies calculations but enhances understanding by focusing on the core of the expression. Always be attentive to not overlook any factor that may simplify further.
Algebraic Restrictions
Algebraic restrictions in rational expressions occur due to the nature of division, where the denominator must not be zero. If the denominator is zero, the expression becomes undefined. Therefore, it's important to determine restrictions for the variables.
To find restrictions, compute the roots of the denominator by setting it equal to zero. For instance, in the expression \( \frac{(x+1)(x+2)}{(x-4)(x+2)} \), the denominator \((x-4)(x+2)\) suggests restrictions where \(x+4=0\) and \(x+2=0\). Solving these gives restrictions: \(x eq 4\) and \(x eq -2\).
  • Be thorough in examining each factor within the denominator for restrictions.
  • Always state these restrictions explicitly as part of your solution.
Addressing these restrictions is crucial to ensure the validity of mathematical solutions, preventing potential errors in computation or interpretation.

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Most popular questions from this chapter

Edward is responsible for keeping the stockroom packed with the best-selling merchandise at the Super Store. He has collected data on sales of the new video game "Math-a-Magic." $$ \begin{array}{|l|l|l|l|l|l|l|l|l|l|l|l|} \hline \text { Week } & 1 & 2 & 3 & 4 & 5 & 6 & 7 & 8 & 9 & 10 \\ \hline \text { Games sold } & 0 & 186 & 366 & 516 & 636 & 727 & 789 & 821 & 825 & 798 \\ \hline \end{array} $$ a. Find a quadratic model in vertex form that fits the data. Let \(w\) represent the week number and let \(s\) represent the number of games sold. b. If the pattern continues, in what week will people stop buying the game? c. How many total games will have been sold when people stop buying the game? (T1) d. There are 1000 games left in the stockroom at the start of week 11 . How many more should Edward buy?

Convert each equation from vertex form to general form. Check your answers by entering both expressions into the \(\mathrm{Y}=\) screen on your calculator, then graphing. a. \(y=(x+5)^{2}+4\) b. \(y=2(x-7)^{2}-8\) c. \(y=-3(x+4)^{2}+1\) (a) d. \(y=0.5(x-3)^{2}-4.5\)

The path of a ball in flight is given by \(p(x)=-0.23(x-3.4)^{2}+4.2\), where \(x\) is the horizontal distance in meters and \(p(x)\) is the vertical height in meters. Note that in this case the graph is the path of the ball, not the graph of the ball's height over time. a. Find \(p(2)\) and give a real-world meaning for this value. b. Find the \(x\)-values for \(p(x)=2\), and describe their real-world meanings. c. How high is the ball when it is released? d. How far will the ball travel horizontally before it hits the ground?

Combine like terms in these polynomials. Check your answers by using calculator tables or graphs. a. \((x+1)+\left(2 x^{2}+3 x+1\right)\) b. \((2 x-5)+\left(3 x^{2}+2 x-4\right)\) c. \((x+1)-\left(2 x^{2}+3 x+1\right)\) (ai) d. \((2 x-5)-\left(3 x^{2}+2 x-4\right)\)

The quadratic formula gives two roots of an equation: $$ x=\frac{-b+\sqrt{b^{2}-4 a c}}{2 a} \text { and } x=\frac{-b-\sqrt{b^{2}-4 a c}}{2 a} $$ What is the average of these two roots? How does averaging the roots help you find the vertex?

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