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Use the properties of exponents to rewrite each expression with only positive exponents. a. \(4 x^{3} \cdot\left(3 x^{5}\right)^{3}\) b. \(\frac{60 x^{4} y^{4}}{15 x^{3} y}\) c. \(3^{2} \cdot 2^{3}\) d. \(\frac{\left(8 x^{3}\right)^{2}}{\left(4 x^{2}\right)^{3}}\) (d) e. \(x^{-3} y^{4}\) f. \((2 x)^{-3}\) g. \(2 x^{-3}\) h. \(\frac{2 x^{-1}}{\left(3 y^{2}\right)^{-3}}\)

Short Answer

Expert verified
a. 108x^{18} b. 4xy^{3} c. 36 d. 1 e. \frac{y^{4}}{x^{3}} f. \frac{1}{8x^{3}} g. \frac{2}{x^{3}} h. \frac{54y^{6}}{x}

Step by step solution

01

Expand Powers (Part a)

First, we need to expand the expression \(4x^3 \cdot (3x^5)^3\). Using the power of a power property \((a^m)^n = a^{m \cdot n}\), we get \((3x^5)^3 = 3^3 \cdot x^{5 \cdot 3} = 27x^{15}\). Now, multiply by \(4x^3\):\[4x^3 \cdot 27x^{15} = 108x^{18}.\]
02

Simplify the Fraction (Part b)

Deal with the fraction \(\frac{60x^4y^4}{15x^3y}\). First simplify the coefficients. \(\frac{60}{15} = 4\). For the variables, use \(x^a / x^b = x^{a-b}\) to get \(x^{4-3} = x^1\) and \(y^{4-1} = y^3\). Thus, \(\frac{60x^4y^4}{15x^3y} = 4xy^3\).
03

Calculate the Product (Part c)

Combine the numbers using the property \(a^m \cdot b^m = (ab)^m\). Thus, \((3^2 \cdot 2^3)\) can be seen as \((3 \cdot 2)^{2}\), which equals \(6^2 = 36\).
04

Simplify Complex Fraction (Part d)

For \( \frac{(8x^3)^2}{(4x^2)^3} \), calculate each term first: \((8x^3)^2 = 64x^6\) and \((4x^2)^3 = 64x^6\). They simplify to \(\frac{64x^6}{64x^6} = 1\).
05

Positive Exponent (Part e)

Change the negative exponent \(x^{-3}y^4\) to positive by using \(x^{-a} = \frac{1}{x^a}\): \(\frac{y^4}{x^3}\).
06

Raise to Positive Power (Part f)

For \((2x)^{-3}\), apply the negative power property \((a^{-n} = \frac{1}{a^n})\). This becomes \(\frac{1}{(2x)^3}\). Calculate \((2x)^3 = 8x^3\), resulting in \(\frac{1}{8x^3}\).
07

Rewriting Any Negative Term (Part g)

Transform \(2x^{-3}\) to \(2 \cdot \frac{1}{x^3}\), resulting in \(\frac{2}{x^3}\).
08

Solve the Fraction (Part h)

Convert \(\frac{2x^{-1}}{(3y^2)^{-3}}\) using the negative powers. \(x^{-1} = \frac{1}{x}\) and \((3y^2)^{-3} = \frac{1}{(3y^2)^3} = \frac{1}{27y^6}\). Thus, \(\frac{2/x}{1/(27y^6)} = 2 \cdot 27y^6 \cdot \frac{1}{x} = \frac{54y^6}{x}\).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Positive Exponents
Understanding positive exponents is crucial when rewriting expressions so that they have only positive powers. An exponent tells you how many times a number, known as the base, is multiplied by itself. For example, in the term \( x^3 \), the base is \( x \) and the exponent is 3, signifying that \( x \) is multiplied by itself 3 times: \( x \times x \times x \). When you encounter a negative exponent, it means the reciprocal of the base raised to the positive of that exponent. For instance, \( x^{-3} \) is the same as \( \frac{1}{x^3} \).

Using properties of exponents, we can turn negative exponents into positive ones to simplify calculations and make expressions more manageable. This is achieved through the property \( a^{-n} = \frac{1}{a^n} \). This principle allows us to avoid dealing with negative powers directly and simplifies the rewriting process. Practicing these conversions can greatly ease the processes in algebraic manipulations.
Simplifying Expressions
Simplifying expressions is about making a mathematical expression as easy to work with as possible. This usually involves combining like terms and reducing any fractions to their simplest form. When dealing with exponents, you often use specific rules to combine or reduce terms.

A key rule when simplifying expressions with exponents is \( x^a \cdot x^b = x^{a+b} \). This means when you multiply two exponents with the same base, you add their powers. Take, for example, \( x^3 \cdot x^2 \), which simplifies to \( x^{3+2} = x^5 \).

When dividing expressions, the rule \( \frac{x^a}{x^b} = x^{a-b} \) is useful. If you have \( \frac{x^5}{x^2} \), it simplifies to \( x^{5-2} = x^3 \). These rules help keep expressions neat and streamlined. By mastering these, simplifying any complex expression becomes straightforward.
Algebraic Operations
Algebraic operations involve applying arithmetic operations like addition, subtraction, multiplication, and division to algebraic expressions. In expressions with exponents, understanding these operations is key for efficient manipulation.

Let's first focus on multiplication. When multiplying terms with exponents, such as \( 3^2 \cdot 2^3 \), each base is handled separately unless the same bases are involved. Here, \( 3^2 \) can be calculated to 9 and \( 2^3 \) to 8, resulting in \( 9 \cdot 8 = 72 \). However, when you multiply like bases, find the product by adding the exponents.

In division, much like simplifying expressions, you subtract the exponents for like bases. For example, in \( \frac{a^5}{a^2} \), you subtract, resulting in \( a^{5-2} = a^3 \). This ensures expressions are not just simplified but also correctly structured power-wise, enabling further algebraic operations to be executed correctly.

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Most popular questions from this chapter

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