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Use the properties of exponents to rewrite each expression. Your final answer should have only positive exponents. Use calculator tables to check that your expression is equivalent to the original expression. a. \(\frac{x \cdot x \cdot x}{x}\) b. \(2 x^{-1}\) c. \(\frac{6.273 x^{8}}{5.1 x^{3}}\) d. \(3^{-x}\) e. \(3 x^{0}\) f. \(x^{2} \cdot x^{5}\) g. \(\left(3^{4}\right)^{x}\) h. \(\frac{1}{x^{-2}}\)

Short Answer

Expert verified
a. \(x^2\), b. \(\frac{2}{x}\), c. \(1.23x^5\), d. \(\frac{1}{3^x}\), e. \(3\), f. \(x^7\), g. \(3^{4x}\), h. \(x^2\).

Step by step solution

01

Simplify expression a

Given the expression \( \frac{x \cdot x \cdot x}{x} \). This simplifies by canceling one \( x \) from the numerator and the denominator, leaving \( x^2 \). Therefore, the expression is \( x^2 \).
02

Simplify expression b

Given \( 2x^{-1} \), apply the property \( a^{-n} = \frac{1}{a^n} \). This becomes \( 2 \cdot \frac{1}{x} = \frac{2}{x} \).
03

Simplify expression c

The expression \( \frac{6.273 x^8}{5.1 x^3} \) can be rewritten using the power of quotients property: \( \frac{a^m}{a^n} = a^{m-n} \). Simplifying the coefficient gives \( \frac{6.273}{5.1} = 1.23 \). The expression simplifies to \( 1.23 x^{8-3} = 1.23 x^5 \).
04

Simplify expression d

Using the property \( a^{-n} = \frac{1}{a^n} \), \( 3^{-x} \) can be rewritten as \( \frac{1}{3^x} \).
05

Simplify expression e

The expression \( 3x^0 \) uses the property that any number raised to the power of zero is 1. Thus, \( x^0 = 1 \), and the expression becomes \( 3 \cdot 1 = 3 \).
06

Simplify expression f

For \( x^2 \cdot x^5 \), using the property \( a^m \cdot a^n = a^{m+n} \), we get \( x^{2+5} = x^7 \).
07

Simplify expression g

Applying the power of a power property \( (a^m)^n = a^{m\cdot n} \) to \( (3^4)^x \), we obtain \( 3^{4x} \).
08

Simplify expression h

Given \( \frac{1}{x^{-2}} \), use the property \( a^{-n} = \frac{1}{a^n} \) directly in the denominator, which gives \( x^2 \). So the expression is \( x^2 \).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Positive Exponents
Exponents represent repeated multiplication of a base number and can either be positive or negative. Positive exponents are straightforward because they tell us how many times to multiply the base by itself. For instance, \( x^3 \) means \( x \times x \times x \).
Using positive exponents is favorable as they are easier to interpret and simplify. For example, converting expressions with negative exponents to positive ones, like changing \( x^{-1} \) to \( \frac{1}{x} \), helps in understanding the expression's value more intuitively.
By consistently using positive exponents, students can avoid confusion and maintain uniformity when simplifying or solving algebraic expressions.
Equivalent Expressions
Equivalent expressions are different algebraic expressions that represent the same value. Understanding how to create and recognize equivalent expressions is crucial in algebra, as it allows for simplification and manipulation of problems to make them more accessible.
For example, if we have \( \frac{x \cdot x \cdot x}{x} \), simplifying it to \( x^2 \) shows that despite different appearances, both expressions yield the same result when any value for \( x \) is substituted.
Checking for equivalency can often be done by simplifying the expressions fully or using a calculator to verify that two expressions give the same output for several values of the variable.
Simplifying Expressions
Simplifying expressions involves reducing them to their most basic form without changing their value. Key strategies include canceling common terms, applying the laws of exponents, and reducing fractions.
For instance, in the expression \( 2x^{-1} \), utilizing the property \( a^{-n} = \frac{1}{a^n} \), it simplifies to \( \frac{2}{x} \). This makes the expression more manageable and easier to work with.
Simplifying is essential for solving equations, comparing expressions, and performing further calculations or analyses efficiently.
Power of a Power Property
The power of a power property is one of the fundamental laws of exponents and states that \( (a^m)^n = a^{m \cdot n} \). It is used when an exponent is raised to another exponent, allowing simplification and better understanding of the expression.
Consider the expression \( (3^4)^x \). Applying the power of a power property, we multiply the exponents to get \( 3^{4x} \). This simplifies the expression significantly, transforming it into a more direct format suitable for further mathematical operations or evaluations.
Understanding and applying this property is crucial when dealing with complex expressions where powers are nested, ensuring clarity and simplicity in mathematical reasoning.

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Most popular questions from this chapter

Write each percent change as a ratio comparing the result to the original quantity. For example, a \(3 \%\) increase is \(\frac{107}{160}\). Then write it as a constant multiplier, for example, \(1+0.03\). a. \(8 \%\) increase b. \(11 \%\) decrease c. \(12.5 \%\) growth (a) d. \(6_{4}^{1} \% \operatorname{loss}\) (a) e. \(x \%\) increase f. \(y \%\) decrease

Write an equivalent expression in the form \(a \cdot b^{n}\). ( \(\hbar\) ) a. \(3 x \cdot 5 x^{3}\) b. \(x \cdot x^{5}\) c. \(2 x^{3} \cdot 2 x^{3}\) d. \(3.5(x+0.15)^{4} \cdot(x+0.15)^{2}\) e. \(\left(2 x^{3}\right)^{3}\) f. \(\left[3(x+0.05)^{3}\right]^{2}\)

APPLICATION A wireless phone service provider offers two calling plans. The first plan costs \(\$ 50\) per month and offers 500 minutes free per month; additional minutes cost \(35 \mathrm{e}\) per minute. The second plan costs only \(\$ 45\) a month and offers 600 minutes free per month; but additional minutes cost more- \(55 \mathrm{c}\) per minute. a. Define variables and write an equation for the first plan if you use it for 500 minutes or less. (a) b. Write an equation for the first plan if you use it for more than 500 minutes. (a) c. Write two equations for the second plan similar to those you wrote in \(15 \mathrm{a}\) and b. Explain what each equation represents. d. Sydney generally talks on her phone about 550 minutes per month. How much would each plan cost her? Which plan should she choose? e. Louis averages 850 minutes of phone use per month. How much would each plan cost him? Which plan should he choose? f. For how many minutes of use will the cost of the plans be the same? How can vou decide which of these two wireless plans is better for a new subscriber? (A)

Use the properties of exponents to rewrite each expression without negative exponents. a. \(\left(2 x^{3}\right)^{2}\left(3 x^{4}\right)\) b. \(\left(5 x^{4}\right)^{0}\left(2 x^{2}\right)\) c. \(3(2 x)^{3}(3 x)^{-2}\) (a) d. \(\left(\frac{2 x^{4}}{3 x}\right)^{-3}\)

Write an equation in point-slope form for a line with slope \(-1.2\) that goes through the point \((600,0)\). Find the \(y\)-intercept.

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