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The equations \(y=28.65-0.0411(x-1962)\) and \(y=27.5-0.0411(x-1990)\) both model the data for the winning times for the Olympic men's 10,000 -meter race. The variable \(x\) represents the year, and \(y\) represents the winning time, in minutes. a. Find the approximate winning time for the year 1972 given by each equation. What is the difference between the values? b. Find the approximate winning time for the year 2008 given by each equation. What is the difference between the values? c. Select an appropriate window and graph the two equations. d. Do you think these equations represent the same line? Explain your reasoning. (a)

Short Answer

Expert verified
The difference in winning times for 1972 between the two equations is 0.0008 minutes.

Step by step solution

01

Substitute 1972 in the First Equation

For the first equation, substitute \(x = 1972\) into \(y = 28.65 - 0.0411(x - 1962)\). This gives \(y = 28.65 - 0.0411(1972 - 1962)\). Simplify the expression to find \(y = 28.65 - 0.0411 \times 10\). Calculate \(y\) to find the winning time.
02

Calculate Winning Time for 1972 in First Equation

Calculate \(0.0411 \times 10 = 0.411\). Therefore, \(y = 28.65 - 0.411 = 28.239\). The winning time for 1972 according to the first equation is approximately 28.239 minutes.
03

Substitute 1972 in the Second Equation

For the second equation, substitute \(x = 1972\) into \(y = 27.5 - 0.0411(x - 1990)\). This gives \(y = 27.5 - 0.0411(1972 - 1990)\). Simplify the expression to find \(y = 27.5 - 0.0411 \times (-18)\). Calculate \(y\) to find the winning time.
04

Calculate Winning Time for 1972 in Second Equation

Calculate \(0.0411 \times (-18) = -0.7398\). Therefore, \(y = 27.5 - (-0.7398) = 28.2398\). The winning time for 1972 according to the second equation is approximately 28.2398 minutes.
05

Calculate the Difference in Winning Times for 1972

Subtract the winning time from the first equation from the second: \(28.2398 - 28.239 = 0.0008\). The difference in winning times according to both equations for 1972 is 0.0008 minutes.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Linear Equations
Linear equations are mathematical expressions which form a straight line when graphed on a coordinate plane. Typically, they have the form \(y = mx + b\), where \(m\) is the slope and \(b\) is the y-intercept. The slope, \(m\), shows how much \(y\) changes for each increase in \(x\). In other words, it represents the rate of change. The y-intercept, \(b\), is the point where the line crosses the y-axis.

In the context of the Olympic race exercise, the equations \(y = 28.65 - 0.0411(x - 1962)\) and \(y = 27.5 - 0.0411(x - 1990)\) represent linear equations, with \(0.0411\) being the slope common to both.
These equations model how the Olympic winning times (\(y\)) change over the years (\(x\)).

It's important to recognize that small differences in linear equations can lead to variations in the calculated outcomes, as shown by the differences in winning times for the year 1972 in both given equations.
Olympic Race Data
The provided equations are specifically tailored to analyze Olympic race data over various years.
The goal is to estimate or predict the race times based on a linear model - a representation using a straight line on a graph, which simplifies understanding complex datasets over time.

The linear equations account for two aspects:
  • Historical trends: By observing past data, the equations allow one to see how winning times have decreased over the years.
  • Predictive modeling: They offer a means to forecast future race times, assuming past trends continue.
Understanding historical data trends is crucial for athletes, coaches, and analysts as they plan and strategize for upcoming Olympic events.

In particular, the slope \( -0.0411 \) suggests how winning times have consistently decreased each year, indicating an improvement in athletes' performances over time.
Graphing Equations
Graphing equations is an essential skill for visualizing relationships between variables. When graphing linear equations, use a Cartesian coordinate system, plotting points derived from substituting variables into the equation.

To graph the Olympic race data, convert each year's data point using the equations \(y = 28.65 - 0.0411(x - 1962)\) and \(y = 27.5 - 0.0411(x - 1990)\). Plot these points on a grid to see the trend line.

Key steps in graphing include:
  • Selecting an appropriate scale and window: Choose a range for years to ensure all relevant data points are visible.
  • Plotting each calculated data point: Manually or using graph software, determine where each \( (x, y) \) lies.
  • Drawing the line: Connect the points to see the overarching trend across plotted years.
Graphing helps in comparing both equations visually, aiding in determining whether they truly represent the same line or have slight variations - as indicated by differences in y-intercepts and thus different starting points on the graph.

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