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For each equation identify the order of operations. Then work backward through the order of operations to find \(x\). a. \(\frac{x-3}{2}=6\) b. \(3 x+7=22\) (ai) c. \(\frac{x}{6}-20=-19\)

Short Answer

Expert verified
(a) \(x = 15\); (b) \(x = 5\); (c) \(x = 6\).

Step by step solution

01

Understand the Order of Operations

For all equations, the order of operations is PEMDAS (Parentheses, Exponents, Multiplication and Division (left to right), Addition and Subtraction (left to right)). We need to undo these when solving for \(x\), working backward.
02

Equation a: Start with Division

The given equation is \(\frac{x-3}{2}=6\). The operations involved are: subtraction \((x - 3)\) followed by division \(\left(\frac{\ }{2}\right)\). We will first undo the division by multiplying both sides by 2.
03

Equation a: Clearing Division

Multiply both sides of the equation by 2 to get \(x - 3 = 12\). This reverses the division operation.
04

Equation a: Address Subtraction

Add 3 to both sides of the equation: \(x = 12 + 3\). This undoes the subtraction.
05

Equation a: Solution

The simplified equation is \(x = 15\).
06

Equation b: Start with Addition

The given equation is \(3x + 7 = 22\). The operations involved are multiplication by 3 and addition of 7. We will first undo the addition by subtracting 7 from both sides.
07

Equation b: Clearing Addition

Subtract 7 from both sides: \(3x = 15\). This clears the addition.
08

Equation b: Address Multiplication

Divide both sides by 3 to solve for \(x\): \(x = 5\). This undoes the multiplication.
09

Equation b: Solution

The simplified equation is \(x = 5\).
10

Equation c: Start with Subtraction

The given equation is \(\frac{x}{6} - 20 = -19\). The operations involved are division by 6 and subtraction of 20. We will first undo the subtraction by adding 20 to both sides.
11

Equation c: Clearing Subtraction

Add 20 to both sides: \(\frac{x}{6} = 1\). This undoes the subtraction.
12

Equation c: Address Division

Multiply both sides by 6 to solve for \(x\): \(x = 6\). This undoes the division.
13

Equation c: Solution

The simplified equation is \(x = 6\).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Solving Equations
Solving equations involves finding the value of an unknown variable, usually represented by \(x\), that makes the equation true. This process often requires performing operations to both sides of the equation in order to isolate and solve for the variable.

When approaching equations, it's essential to recognize the operations involved and to work systematically to reverse them. Equations may include operations such as addition, subtraction, multiplication, and division.

To solve an equation effectively, follow these general steps:
  • Identify the operations being used in the equation.
  • Determine which operation to reverse first, usually by navigating from the outermost operation toward the variable.
  • Execute the reverse operation equally on both sides of the equation to keep it balanced.
  • Continue this process until the variable is isolated.
By diligently applying these steps, equations can be solved accurately, and the correct values for the variable can be determined.
Reverse Operations
Reverse operations are critical in solving equations because they help us undo the operations that have been applied to the variable. Think of it like peeling back layers of an onion. Each layer represents an operation performed on the variable.

In mathematical terms, reverse operations include:
  • Subtracting the same number to undo addition.
  • Adding the same number to undo subtraction.
  • Dividing by the same number to undo multiplication.
  • Multiplying by the same number to undo division.
It’s important to apply the reverse operation to both sides of the equation, ensuring that the equation remains balanced.

By understanding and applying reverse operations, you can effectively navigate through equations and reach the solution with elegance and precision.
PEMDAS
PEMDAS is an acronym that stands for Parentheses, Exponents, Multiplication and Division (left to right), Addition and Subtraction (left to right). This order of operations is a fundamental rule for evaluating all mathematical expressions. It's crucial when you're deciding the sequence of operations to apply in both solving equations and simplifying expressions.

During equation solving, the reverse order of PEMDAS might be more relevant, as you frequently need to undo operations to isolate the variable. Suppose you have multiple operations in an equation. In that case, you work backward through PEMDAS, often starting with subtraction before multiplication or division, which often occurs near the variable.

Understanding PEMDAS helps ensure calculations are performed correctly, maintaining the structural integrity of mathematical expressions.
Algebraic Manipulation
Algebraic manipulation involves rearranging and simplifying equations to move towards a solution. It is crucial when trying to isolate the variable to one side of the equation. This process might involve a combination of performing operations and strategically using reverse operations.

Here’s how algebraic manipulation often works in equations:
  • Collect like terms to simplify both sides.
  • Use distributive properties or factorization if applicable.
  • Apply reverse operations carefully to maintain the balance of the equation.
  • Continue these adjustments until the variable is isolated on one side.
These steps enable you to simplify complex expressions and solve equations efficiently, granting insight into how variables interact within an equation. By mastering algebraic manipulation, students gain a versatile tool for tackling a broad range of mathematical problems.

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Most popular questions from this chapter

Evaluate each expression without a calculator. Then check your result with your calculator. a. \(-4+(-8)\) b. \((-4)(-8)\) c. \(-2(3+9)\) d. \(5+(-6)(-5)\) e. \((-3)(-5)+(-2)\) f. \(\frac{-15}{3}+8\) g. \(\frac{23-3(4-9)}{-2}\) (d) h. \(\frac{-4[7+(-8)]}{8}-6.5\) i. \(\frac{6(2 \cdot 4-5)-2}{-4}\)

In a resort area during the summer months, only one out of eight people is a year-round resident. The others are there on vacation. If the year-round population of the area is 3000 , how many people are there in the summer?

Find a rate for each situation. Then use the rate to answer the question. a. Kerstin drove \(350 \mathrm{mi}\) last week and used \(12.5 \mathrm{gal}\) of gas. How many gallons of gas will he use if he drives \(520 \mathrm{mi}\) this week? b. Angelo drove \(225 \mathrm{mi}\) last week and used \(10.7\) gal of gas. How far can he drive this week using 9 gal of gas?

APPLICATION Portia drove her new car 308 miles on \(10.8\) gallons of gasoline. a. What is the car's rate of gasoline consumption in miles per gallon? b. If this is the typical mileage for Portia's car, how much gas will it take for a 750 -mile vacation trip? c. If gas costs \(\$ 2.35\) per gallon, how much will Portia spend on gas on her vacation? d. The manufacturer advertised that the car would get 30 to 35 miles per gallon. How does Portia's mileage compare to the advertised estimates?

Insert operation signs, parentheses, or both into each string of numbers to create an expression equal to the answer given. Keep the numbers in the same order as they are written. Write an explanation of your answer, including information on the order in which you performed the operations. a. \(3257=18\) b. \(8567=13\)

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