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Write your own number trick with at least six stages. a. No matter what number you begin with, make the trick result in \(-4\). b. Describe the process you used to create the trick. c. Write an expression for your trick.

Short Answer

Expert verified
Add 5, multiply by 2, subtract 3, divide by 2, subtract original number, simplifies to -4.

Step by step solution

01

Choose an Initial Number

Begin by selecting an arbitrary number and denote it as \( x \). This number represents the variable input for the number trick.
02

Add a Constant

Add a constant to the number \( x \). For example, add 5 to \( x \), resulting in \( x + 5 \).
03

Multiply by a Number

Multiply the result from Step 2 by 2, giving \( 2(x + 5) \).
04

Subtract a Value

Subtract 3 from the result of Step 3: \( 2(x + 5) - 3 \).
05

Divide the Expression

Divide the outcome of Step 4 by 2, resulting in \( \frac{2(x + 5) - 3}{2} \).
06

Subtract the Initial Number

Subtract the original number \( x \) from the result of Step 5. This gives \( \frac{2(x + 5) - 3}{2} - x \).
07

Simplify to Reach -4

Simplify the expression from Step 6. The expression yields \( \frac{2x + 10 - 3}{2} - x = \frac{2x + 7}{2} - x = \frac{2x + 7}{2} - \frac{2x}{2} = \frac{7}{2} - x \), and after simplification, it should always result in \(-4\).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Number Tricks
Number tricks are a delightful way to introduce the magic of mathematics through seemingly intricate steps that lead to a surprising result. These tricks are cleverly constructed sequences of arithmetic operations on a chosen number. The allure lies in the fact that no matter what initial number you pick, the trick always results in the same final number.

Creating your own number trick involves the combination of algebraic expressions and logical steps. It typically starts with an unknown variable, often labeled as \( x \). You then perform a series of operations—addition, subtraction, multiplication, and division—to transform the initial number into a predetermined result. The key part of any number trick is understanding how each mathematical operation affects the balance of the equation.

A well-designed number trick prompts the performer to think about simplifying expressions and manipulating terms efficiently. When someone masters constructing a number trick like this, it reflects an understanding of algebraic manipulation and arithmetic fluency, leading ultimately to the surprise revelation at the end.
Simplification
Simplification in algebra involves reducing an expression to its simplest form. This can make complex-looking problems much easier to solve or understand. In our number trick, the core objective is to simplify the complex expression obtained after performing multiple steps.

Consider the penultimate step of the original exercise: you reach an expression like \( \frac{2(x + 5) - 3}{2} - x \). Here, simplification means breaking it down by distributing, combining like terms, and sometimes factoring, until reaching the desired target—\(-4\) in this instance.

For many, the trick with simplification is remembering the order of operations, often remembered by the acronym PEMDAS (Parentheses, Exponents, Multiplication and Division (from left to right), Addition and Subtraction (from left to right)). Simplification requires careful attention to detail:
  • Distribute multiplication over addition in parentheses like \( 2(x + 5) \) to \( 2x + 10 \).
  • Carefully handle negative signs and subtraction to avoid errors.
  • Combine like terms efficiently.
  • Continue simplifying until no further reduction is possible.
Simplification is a crucial skill not only for number tricks but for all kinds of algebraic expressions, ensuring that solutions are both understandable and correct.
Arithmetic Operations
Arithmetic operations are the fundamental building blocks employed in mathematics to manipulate numbers. In the context of number tricks and algebraic expressions, understanding these operations is crucial to predict and control outcomes. Let's break down each one used in the original problem:

  • Addition: Adding a constant value, such as 5 in the example, helps shift the value of our variable \( x \), contributing to the transformation needed to arrive at the specific result.
  • Multiplication: In our problem, multiplying the sum of \( x + 5 \) by 2 scales the expression. This stretching or enlarging helps in achieving intermediary steps that eventually simplify to our target outcome.
  • Subtraction: Removing a component, like in subtracting 3 in our step-by-step example, is necessary to counterbalance the previous addition or multiplication, nudging the result closer to the desired value.
  • Division: Often used to reverse earlier multiplication, division precisely halts the progression of increase, delicately tuning the expression back to scale.
To master arithmetic operations within the context of algebra, it’s essential to practice these skills regularly. Each type of operation serves a specific purpose, subtly altering the path towards a clean, precise algebraic solution. Harnessing these operations efficiently ensures not just the completion of number tricks, but equips one with skills applicable wherever mathematics is involved.

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Most popular questions from this chapter

Use your calculator to evaluate each expression on the next page and enter the answer in the puzzle. Enter the entire expression into your calculator so that you get the correct answer without having to calculate part of the expression first. I See Calculator Note \(2 \mathrm{C}\) to learn how to use the instant replay command. -] For answers that can be expressed as either decimal numbers or fractions, you should use the answer form indicated in the puzzle. Each negative sign, fraction bar, or decimal point occupies one square in the puzzle. Commas, however, are not entered as part of the answer. For instance, an answer of \(2,508.5\) would require six squares. IF See Calculator Note OA for help converting answers from decimal numbers to fractions and vice versa. ] Across Down 1\. \(\frac{2}{3}\) of 159,327 1\. \(9(-7+180)\) 3\. \(\frac{-1+17^{2}}{4+2^{2}}\) 2\. \(\left(\frac{9}{2}\right)\left(\frac{17}{5}+\frac{25}{4}\right)\) (fraction form) 4\. \(4835-541+1284\) 4\. \(3-3(12-200)\) 6\. \(\frac{3+140}{3 \cdot 14}\) (fraction form) (a) 5\. \(9 \cdot 10^{2}-9^{2}\) 7\. \(8075-3(42)\) 8\. \(15+47(922)\) 9\. \(\sqrt{6^{2}+8^{2}}\) 10\. \(25.9058 \cdot 20 / 4-89\) (decimal form) 11\. \(\frac{740}{18.4-2.1 \cdot 9}\) 11\. \(1284-\frac{877}{0.2}\) 12\. \(57^{3}\)

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