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91Ó°ÊÓ

One inch on a road map represents 50 miles on the ground. Two cities are \(3.6\) inches apart on a map. What is the actual distance between the cities?

Short Answer

Expert verified
The actual distance between the cities is 180 miles.

Step by step solution

01

Understand the Problem

We need to find the actual ground distance between two cities based on their distance on a map. The map scale indicates that each inch represents 50 miles.
02

Use the Map Scale

The given scale says that 1 inch on the map is 50 miles on the ground. To find the actual distance for any given map measurement, we can multiply that measurement by 50.
03

Apply the Scale to the Given Measurement

The cities are 3.6 inches apart on the map. To find the actual distance, multiply 3.6 inches by 50 miles per inch: \[3.6 \text{ inches} \times 50 \text{ miles/inch} = 180 \text{ miles}\]
04

State the Conclusion

Based on the calculations, the actual distance between the two cities is 180 miles.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Understanding Map Scale
A map scale is a crucial component in translating map distances to actual ground distances. It tells us how much real-world distance is represented by a unit of measurement on the map. For example, in our problem, 1 inch on the map equals 50 miles on the ground. This "1:50 scale" means that every inch measured between two points on the map corresponds to 50 miles between those points in reality.

Understanding map scales involves recognizing the proportionate relationship between map and ground distances. This helps when calculating real-world distances using scaled measurements. Map scales can be written in various ways like 1 inch equals 1 mile or 1:63,360 (inches to miles). Keeping this fundamental concept in mind is key to correctly interpreting and using maps in navigation and planning.

Calculating Distances Using a Map
Distance calculation involves determining the real-world distance between locations represented on a map. To do this, you use the map scale as a conversion factor. In our exercise, multiplying the map distance by the scale factor converts it into ground distance.

Here's how you can approach a problem like this:
  • Identify the map distance between two points. In our example, it was 3.6 inches.
  • Use the scale factor to convert the map distance to actual distance. Multiply the map distance by the scale factor. For 3.6 inches and a scale of 50 miles per inch, the calculation is: \[3.6 \, \text{inches} \times 50 \, \text{miles/inch} = 180 \, \text{miles}\]
This process will help you derive real distances from maps, aiding in activities such as travel planning or education.

The Importance of Unit Conversion
Unit conversion is essential when handling different measurement systems, especially in problems involving map scales. In our situation, the map uses inches and the ground measurement is in miles. It's important to correctly interpret and convert these units to ensure accuracy in your calculations.

Consider if the scale used different units, such as centimeters instead of inches. You would need to convert inches to centimeters to use that scale effectively. This often requires multiplying by a factor (like 2.54 to convert inches to centimeters).

Here’s a brief guide:
  • Check the units of the map scale and the required outcome units.
  • If necessary, convert the measurement to match the scale units before applying the conversion factor.
  • Finally, convert the calculated real-world distance to the desired unit, if needed.
Ensuring units align properly across the map scale and actual measurements will enhance precision and effectiveness in all your scale-related calculations.

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Most popular questions from this chapter

\(\mathrm{Al}\) says you can define a right trapezoid as a quadrilateral with exactly two right angles. Provide a counterexample by naming four points for the vertices of a quadrilateral that has two right angles but is not a right trapezoid. Draw a sketch of your figure.

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Consider the equation $$ \sqrt{20-x}=x $$ a. Solve the equation symbolically. b. Solve the equation using a graph or a table. c. Explain why you get two possible solutions when you solve the equation symbolically and only one solution when you look at a graph or table. Substitute both possible solutions into the original equation, and describe what happens.

A factory makes square tiles with a side length of \(\sqrt{93} \mathrm{~mm}\). a. What is the area of the top face of one tile? b. If you evaluate \(\sqrt{93}\) and round to the nearest tenth, you get \(\sqrt{93} \approx 9.6\). Use this value to find the area of one tile. How does this compare to your answer in \(18 \mathrm{a}\) ? c. Each tile is \(8 \mathrm{~mm}\) thick. Find the volume of clay needed to make one tile, using both \(\sqrt{93} \mathrm{~mm}\) and \(9.6 \mathrm{~mm}\) as values for the side length of a tile. How do your results compare? d. The factory needs to make 1000 tiles to satisfy a special order. Calculate how much clay is needed using both \(\sqrt{93} \mathrm{~mm}\) and \(9.6 \mathrm{~mm}\) as values for the side length of a tile. How do your results compare? e. Calculate the volume of clay needed for 1000 tiles if you estimate \(\sqrt{93}\) to be \(9.64\). f. What can you conclude based on your results in \(18 \mathrm{a}-\mathrm{e}\) ?

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