/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 11 The population of City A is curr... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

The population of City A is currently 47,000 and is increasing at a rate of \(4.5 \%\) per year. The population of City B is currently 56,000 and is decreasing at a rate of \(1.2 \%\) per year. a. What will the populations of the two cities be in 5 years? b. When will the population of City A first exceed 150,000 ? c. If the population decrease in City B began 10 years ago, how large was the population before the decline started?

Short Answer

Expert verified
a. 58,662 for City A and 52,640 for City B in 5 years. b. 27 years for City A to exceed 150,000. c. 63,251 was City B's population 10 years ago.

Step by step solution

01

Understanding Population Growth Model

Populations that increase or decrease at a constant percentage per year can be modeled using exponential growth or decay formulas. The formula for the population after a certain number of years is given by:For City A (growth):\[ P_A = P_{A_0} \times (1 + r_A)^t \]where \( P_{A_0} \) is the initial population, \( r_A \) is the growth rate, and \( t \) is the time in years.For City B (decay):\[ P_B = P_{B_0} \times (1 - r_B)^t \]where \( P_{B_0} \) is the initial population, \( r_B \) is the decay rate, and \( t \) is the time in years.Let's use these formulas to find the future populations.
02

Population of City A in 5 Years

To find the population of City A after 5 years, use:\[ P_A = 47000 \times (1 + 0.045)^5 \]\[ = 47000 \times (1.045)^5 \]\[ \approx 47000 \times 1.246 \]\[ \approx 58662 \]Thus, the population of City A in 5 years is approximately 58,662.
03

Population of City B in 5 Years

To find the population of City B after 5 years, use:\[ P_B = 56000 \times (1 - 0.012)^5 \]\[ = 56000 \times (0.988)^5 \]\[ \approx 56000 \times 0.940 \]\[ \approx 52640 \]Hence, the population of City B in 5 years is approximately 52,640.
04

Finding When City A's Population Exceeds 150,000

To find when the population of City A will exceed 150,000, solve the equation:\[ 150000 = 47000 \times (1.045)^t \]Divide both sides by 47,000:\[ \frac{150000}{47000} = (1.045)^t \]\[ 3.191 = (1.045)^t \]Taking the logarithm of both sides:\[ \log(3.191) = t \cdot \log(1.045) \]Solve for \( t \):\[ t = \frac{\log(3.191)}{\log(1.045)} \approx 26.1 \]Thus, the population will exceed 150,000 in approximately 27 years.
05

Original Population of City B

To find the original population of City B before the decline 10 years ago, use:\[ P_{B_0} = P_B / (1 - r_B)^{10} \]We know the current population is 56,000, so:\[ P_{B_{-10}} = 56000 / (0.988)^{10} \]\[ ≈ 56000/0.886 \]\[ ≈ 63251 \]Therefore, the original population of City B was approximately 63,251.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Population Modeling
Population modeling is a powerful tool used to predict and analyze the dynamic changes in populations over time. In this context, mathematical models, especially exponential models, allow us to determine how a population will grow or decline based on certain parameters like growth or decay rates. These models are crucial in helping policymakers and researchers understand demographic changes and prepare for future needs.

For instance, in the case of City A and City B, population modeling is used to project future populations based on current trends. City A's population is increasing by a constant 4.5% per year, which suggests an exponential growth pattern. In contrast, City B's declining population at a rate of 1.2% annually is an example of exponential decay. By applying these exponential models, we can not only forecast future population sizes but also explore scenarios like the timing for City A's population to exceed a certain threshold or discovering past demographics of City B before a decline.

Understanding and utilizing population models are key in fields like urban planning, resource allocation, and even environmental studies. This kind of modeling allows for efficient strategizing and informed decision-making, making it an invaluable part of modern scientific approaches.
Exponential Functions
Exponential functions are fundamental in modeling situations where there is a constant percentage change over time. They appear in scenarios involving growth or decay, making them crucial in understanding population dynamics, as seen with Cities A and B. An exponential function generally takes the form:
  • Growth: \( P = P_0 \times (1 + r)^t \)
  • Decay: \( P = P_0 \times (1 - r)^t \)
Here, \( P_0 \) represents the initial value, \( r \) is the rate of change (growth or decay), and \( t \) is time. In population studies, these functions model situations where populations evolve at predictable rates.

City A, increasing at a rate of 4.5%, follows an exponential growth formula, resulting in its population reaching about 58,662 after 5 years. Conversely, City B, experiencing a decline at 1.2%, decreases to approximately 52,640 over the same period.

These mathematical expressions not only quantify changes but also help predict when specific milestones will be reached, such as City A surpassing 150,000 people. Exponential functions allow for the transformation of abstract growth processes into concrete numbers, providing clear insights and predictions.
Algebraic Equations
Algebraic equations are used extensively to solve real-world problems, such as calculating future populations or determining initial values before changes occur. These equations involve variables and known quantities that can model situations mathematically and allow us to derive unknown information.

Let’s take an example from the provided solution. To determine when City A's population will exceed 150,000, we set up an equation based on its exponential growth: \( 150000 = 47000 \times (1.045)^t \). By solving this algebraic equation, we isolate the variable \( t \), representing time, to find when this critical point will occur. This involves logarithmic functions to reverse the exponential function and derive the solution.

Similarly, algebraic manipulation helps uncover City B's population from a past point in time before its decline began. Using rearrangement and inverse operations, we calculate that the population was approximately 63,251 ten years ago.

This blend of algebraic equations with exponential functions enables precise predictions, making them a powerful method for tackling complex problems in population studies. These equations are essential for determining unknown quantities from known variables, ultimately facilitating strategic planning and informed decision-making.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

For Exercises \(7-14\), plot each set of points on graph paper and connect them to form a polygon. Classify each polygon using the most specific term that describes it. Use deductive reasoning to justify your answers by finding the slopes of the sides of the polygons. $$ (0,4),(2,8),(6,-2),(2,-1) $$

Draw four congruent rectangles-that is, all the same size and shape. a. Shade half the area in each rectangle. Use a different way of dividing the rectangle each time. b. Which of your methods in 13 a divide the rectangle into congruent polygons? c. Ripley divided one of her rectangles like this. Is the area divided in half? Explain.

You can rewrite some radical expressions using the fact that they contain perfect-square factors. Here's an example: \(\begin{array}{ll}\sqrt{125} & \text { Original expression. } \\ \sqrt{25 \cdot 5} & 25 \text { is a perect-square factor of } 125 . \\ \sqrt{25} \cdot \sqrt{5} & \text { Rewrite the expression as two radical expressions. } \\ 5 \sqrt{5} & \text { Find the square root of } 25 .\end{array}\) Use this method to rewrite each radical expression. a. \(\sqrt{72}\) (a) b. \(\sqrt{27}\) c. \(\sqrt{1800}\) d. \(\sqrt{147}\)

You will need a centimeter ruler for this problem. a. Measure the length and width of your textbook cover in centimeters. b. Use the Pythagorean Theorem to calculate the diagonal length using the length and width you measured in 7 a. c. Measure one of the diagonals of the cover. d. How close are the values you found in \(7 \mathrm{~b}\) and \(\mathrm{c}\) ? Should they be approximately the same?

Write the equation for each parabola in general form. Use your calculator to check that both forms give the same graph or table. a. \(y=(x+\sqrt{3})(x-\sqrt{3})\) b. \(y=(x+\sqrt{5})(x+\sqrt{5})\)

See all solutions

Recommended explanations on Math Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.