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Create a set of data that fits each description. (International Game Fish Association, Everything 2001, p. 41) a. The mean age of a family is 19 years, and the median age is 12 years. There are five people in the family. (Thi) b. Six students in the Mathematics Club compared their family sizes. The mode was five people, and the median was four people. c. The points scored by the varsity football team in the last seven games have a mean of 20 , a median of 21 , and a mode of 27 points.

Short Answer

Expert verified
a: Ages are 5, 8, 12, 30, 40. b: Sizes are 2, 3, 4, 4, 5, 5. c: Scores are 10, 15, 21, 21, 27, 27, 37.

Step by step solution

01

Determining the Mean and Median for Five People

For part a, we need a set of ages where the mean is 19 and the median is 12 with 5 people in the family. The median means the third number in an ordered set of five numbers must be 12. Let the ages be \(a, b, 12, d, e\). The mean formula is \(\frac{a+b+12+d+e}{5} = 19\). Solving, we have \(a+b+12+d+e = 95\) and thus, \(a + b + d + e = 83\). To keep 12 as the median, a possible set is \(5, 8, 12, 30, 40\). These numbers fit the requirement: \(\frac{5 + 8 + 12 + 30 + 40}{5} = 19\).
02

Arranging Family Sizes for Mode and Median

For part b, we need a set of family sizes for six students where the most frequent size (mode) is 5, and the median is 4. If the ordered sizes are \(a, b, 4, 4, 5, 5\), this gives a median of 4 and a mode of 5. A possible data set is \(2, 3, 4, 4, 5, 5\). Thus, the set fulfills the conditions.
03

Identifying Scores with Given Statistics

For part c, the objective is to find a 7-game score set with a mean of 20, median 21, and mode 27. Let the ordered scores be \(a, b, c, 21, e, f, g\). The mean is \(\frac{a+b+c+21+e+f+g}{7} = 20\), leading to \(a+b+c+21+e+f+g=140\). Select that the mode is 27, appearing more than once. A set could be \(10, 15, 21, 21, 27, 27, 37\). Here the mean is \(\frac{10 + 15 + 21 + 21 + 27 + 27 + 37}{7} = 20\), and the median and mode conditions hold as well.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Mean and Median
When we talk about data sets, the mean and median are two central measures of tendency which help summarize the data. The mean, often called the average, is obtained by dividing the sum of all numbers by the total count of numbers. For example, in part a, we have a family with ages that need to total 95 to achieve a mean of 19 with five people:
  • Mean Formula: \( \text{Mean} = \frac{\text{Sum of all values}}{\text{Number of values}} \)
The median is the number in the middle of a data set when it is organized sequentially. If we have an odd number of observations, like in the family age example with five people, the median is simply the third number. This provides a different view of the data, often giving a better idea of what is typical in a skewed distribution.
In the exercise, for instance, the ages are organized so that 12 is the median, forming this sequence: 5, 8, 12, 30, 40.
Mode
The mode is another measure of central tendency, but unlike the mean and median, it highlights the most frequently occurring value in a data set. It represents popularity or repeats in data. Part b of our exercise involves determining a data set where five is the most commonly occurring number. This means that five appears more times than any other family size:
  • A possible sequence is 2, 3, 4, 4, 5, 5, making 5 the mode.
When considering what the mode of a data set should be, ensure that it appears at least twice, as no mode exists for a data set where no number repeats. In some data sets, there could be more than one mode, or none at all, if all numbers are unique. Modes are particularly useful in categorical data where we want the most typical outcome.
Problem Solving
One crucial aspect of data analysis is problem solving, which involves using given statistical descriptions to create or understand data sets. Part a of the exercise demonstrates this by finding a sequence of ages fitting both mean and median requirements. This requires:
  • Understanding what each statistical term means and how they apply to the data.
  • Experimenting with different combinations to satisfy conditions.
Similarly, in part b and part c, we align sequences to satisfy the mode and median requirements. Thus, problem solving in statistical data involves creativity and systematic testing, often requiring trial and error. This approach not only enhances comprehension of statistical concepts but also bolsters logical thinking and analytical skills.
Statistical Concepts
Statistical concepts form the backbone of understanding and interpreting data in meaningful ways. These include mean, median, and mode, along with other measures like range, variance, and standard deviation:
  • The mean provides a "central" value, but can be skewed by outliers.
  • The median offers an idea of the "middle" of a data set, resistant to extremes.
  • The mode shows most common occurrences, applicable in qualitative data.
Applying these concepts to real-world problems, like those in the exercise, emphasizes their utility. For instance, understanding the difference between mean and median can illuminate income discrepancies in economic data.
Mastering these statistical tools empowers individuals to make informed decisions and derive insights, highlighting the importance of accurate data representation in various fields such as economics, healthcare, and sports.

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Most popular questions from this chapter

Create a data set that fits the information. (Th) a. Ten students were asked the number of times they had flown in an airplane. The range of data values was 7 . The minimum was 0 and the mode was 2 . b. Eight students each measured the length of their right foot. The range of data values was \(8.2 \mathrm{~cm}\), and the maximum value was \(30.4 \mathrm{~cm}\). There was no mode.

As a general rule, if the distance of a data point from the nearest end of the box is more than \(1.5\) times the length of the box (or IQR), then it qualifies as an outlier. a. The five-number summary for the number of points scored by the 1997-98 Chicago Bulls players is \(167,288,416,841,2357\). What is \(1.5\) times the interquartile range? b. What is the value of the first quartile minus \(1.5\) times the interquartile range? c. What is the value of the third quartile plus \(1.5\) times the interquartile range? d. The values you found in \(10 \mathrm{~b}\) and \(\mathrm{c}\) are the limits of outlier values. Identify any 1997-98 Chicago Bulls players who are outliers.

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