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(The Infinite Möbius Strip.) Let $$ C=\left\\{(x, y, z) \in R^{3} ; x^{2}+y^{2}=1\right\\} $$ be a cylinder and \(A: C \rightarrow C\) be the map (the antipodal map) \(A(x, y, z)=\) \((-x,-y,-z)\). Let \(M\) be the quotient of \(C\) by the equivalence relation \(p \sim A(p)\), and let \(\pi: C \rightarrow M\) be the \(\operatorname{map} \pi(p)=\\{p, A(p)\\}, p \in C .\) a. Show that \(M\) can be given a differentiable structure so that \(\pi\) is a local diffeomorphism ( \(M\) is then called the infinite Möbius strip). b. Prove that \(M\) is nonorientable. c. Introduce on \(M\) a Riemannian metric so that \(\pi\) is a local isometry. What is the curvature of such a metric?

Short Answer

Expert verified
The quotient space \(M\) is a differentiable, nonorientable manifold with curvature zero.

Step by step solution

01

Define the cylinder \(C\) and the Map \(A\)

The cylinder is defined as \[C = \left\{(x, y, z) \,\in\, \mathbb{R}^{3} \;|\; x^{2} + y^{2} = 1\right\}\]The map \(A\) (the antipodal map) is defined by \[A(x, y, z) = (-x, -y, -z)\]
02

Define the quotient space \(M\)

Define the quotient space \(M\) by the equivalence relation \(p \, \sim \, A(p)\). Let \(\pi : C \to M \) be the map given by \( \p(p) = \{ p, A(p) \}\)
03

Show that \(M\) is a differentiable manifold

To show \(M\) is a differentiable manifold, establish local charts around points. The map \(\pi : C \to M\) is locally a homeomorphism because in small neighborhoods, points are not identified. This ensures that \(\pi\) maps local coordinates on \(C\) to those on \(M\), thus demonstrating that \(M\) can be given a differentiable structure where \(\pi\) is a local diffeomorphism.
04

Prove that \(M\) is nonorientable

To prove that \(M\) is nonorientable, consider the path along the cylinder \(C\) such that an orientation in \(C\) would flip under the map \(A\). If a loop on \(M\) winds around \(C\) and ends up at an antipodal point, its orientation is reversed. Therefore, an orientation cannot be consistently maintained across the entirety of \(M\), showing it is nonorientable.
05

Introduce a Riemannian metric on \(M\)

To introduce a Riemannian metric on \(M\), let the Riemannian metrics \(g_{C}\) and \(g_{M}\) on \(C\) and \(M\) respectively be defined such that \(\pi\:C \to M \)is a local isometry. The natural metric inherited from \(\mathbb{R}^{3}\: dx^{2} + dy^{2} + dz^{2}\) works, as \(\pi\) maps smoothly between the spaces.
06

Determine the curvature of \(M\)

Given the Riemannian metric on \(M\), we calculate its curvature. Since \(\pi\) is a local isometry, the curvature of \(M\) is the same as that of \(C\). In a cylindrical coordinate system, the Gaussian curvature of a cylinder is zero because its surface is flat in terms of intrinsic geometry. The curvature of \(M\) thus remains zero.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Differentiable Manifolds
A differentiable manifold is a space that locally resembles Euclidean space and allows for smooth transitions between overlapping regions. In the context of this exercise, the space we are working with is a cylinder, denoted as \(\text{C}\), and we want to show that it can be given a differentiable structure even after applying the equivalence relation given by the antipodal map. To do this, think of the manifold as being 'covered' by small patches, each of which looks like a piece of 3-dimensional Euclidean space. When we say that \(\text{M}\) can be given a differentiable structure and that \(\text{Ï€}\) is a local diffeomorphism, it means that for any small enough neighborhood on \(\text{C}\), the map \(\text{Ï€}\) behaves smoothly and retain structure in \(\text{M}\). Essentially, we are stitching together small, smoothly varying pieces that form our quotient space \(\text{M}\).
Nonorientable Surfaces
Nonorientable surfaces are those surfaces that lack a consistent choice of 'direction' throughout. An example is the Möbius strip, which has only one side and one boundary. In our case, the nonorientability of the space \(\text{M}\) follows from the use of the antipodal map. When you traverse a path that loops back on itself through the antipodal points on the cylinder, you return to the starting point, but with the orientation flipped. This means that if you try to maintain a consistent 'up' direction over the surface, you will eventually find yourself with an 'up' direction pointing 'down'. Hence, the surface \(\text{M}\) cannot be oriented in any globally consistent way and thus is nonorientable.
Riemannian Metrics
A Riemannian metric allows us to measure distances and angles on a manifold. It provides a way to take the dot product of vectors within the manifold. For the infinite Möbius strip, \(\text{M}\), we need a Riemannian metric that fits with the existing structure on the cylinder \(\text{C}\). The map \(\text{π: C → M}\) being a local isometry means that the Riemannian metric on \(\text{M}\) induces the same measurements as on \(\text{C}\). Thus, we can use the metric inherited from the Euclidean space \(\text{dx}^{2} + \text{dy}^{2} + \text{dz}^{2}\). This implies that at small scales, measurements on \(\text{M}\) will be identical to measurements on \(\text{C}\).
Antipodal Map
The antipodal map takes a point on the surface and maps it to its opposite. For the cylinder \(\text{C}\), defined by \(\text{x}^2 + \text{y}^2 = 1\), this means that the point \((\text{x}, \text{y}, \text{z})\) gets mapped to \((-x, -y, -z)\). This relation essentially glues points on the cylinder to their antipodal counterparts to form the new quotient space \(\text{M}\). Therefore, each element in \(\text{M}\) is not a single point, but a pair of points from \(\text{C}\). The antipodal mapping is crucial because it underlies the non-orientability and also determines how we need to adapt our measurements and structure when defining local diffeomorphisms on \(\text{M}\).
Curvature
Curvature in Riemannian geometry quantifies how much a geometric object deviates from being flat. For our manifold \(\text{M}\), which inherits the properties of \(\text{C}\), the curvature is determined by how the cylinder bends in the ambient space. Given that the cylinder is flat in terms of its intrinsic geometry, its Gaussian curvature is zero. Thus, the infinite Möbius strip \(\text{M}\), inheriting this characteristic through the local isometry via \(\text{π}\), will also have zero curvature. This means that, locally, \(\text{M}\) doesn't curve - its geometry is flat.

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Most popular questions from this chapter

Let \(S \subset R^{3}\) be a complete surface and let \(F \subset S\) be a nonempty, closed subset of \(S\) such that the complement \(S-F\) is connected. Show that \(S-F\) is a non-complete regular surface.

Let \(J(s)\) be a Jacobi field along a geodesic \(\gamma:[0, l] \rightarrow S\) such that \(\left\langle J(0), \gamma^{\prime}(0)\right\rangle=0\) and \(J^{\prime}(0)=0\). Prove that \(\left\langle J(s), \gamma^{\prime}(s)\right\rangle=0\) for all \(s \in[0, l]\).

Let \(S\) be a complete surface with \(K \geq K_{1}>0\), where \(K\) is the Gaussian curvature of \(S\) and \(K_{1}\) is a constant. Prove that every geodesic \(\gamma:[0, \infty) \rightarrow S\) has a point conjugate to \(\gamma(0)\) in the interval \(\left(0, \pi / \sqrt{K_{1}}\right]\).

Let \(S\) be the helicoid generated by the normals to the helix \((\cos t, \sin t, b t)\). Denote by \(L\) the \(z\) axis and let \(\pi: S-L \rightarrow R^{2}-\\{0,0\\}\) be the projection \(\pi(x, y, z)=(x, y)\). Show that \(\pi\) is a covering map.

Let \(U \subset R^{3}\) be an open connected subset of \(R^{2}\) and let \(\mathbf{x}: U \rightarrow S\) be an isothermal parametrization (i.e., \(E=G, F=0\); cf. Sec. 4-2) of a regular surface \(S\). We identify \(R^{2}\) with the complex plane \(\mathbb{C}\) by setting \(u+i v=\zeta\), \((u, v) \in R^{2}, \zeta \in \mathbb{C}\). \(\zeta\) is called the complex parameter corresponding to \(\mathbf{x}\). Let \(\phi: \mathbf{x}(U) \rightarrow \mathbb{C}\) be the complex- valued function given by $$ \phi(\zeta)=\phi(u, v)=\frac{e-g}{2}-i f=\phi_{1}+i \phi_{2} $$ where \(e, f, g\) are the coefficients of the second fundamental form of \(S\). a. Show that the Mainardi-Codazzi equations (cf. Sec. 4-3) can be written, in the isothermal parametrization \(\mathrm{x}\), as $$ \left(\frac{e-g}{2}\right)_{a}+f_{*}=E H_{a} \quad\left(\frac{e-g}{2}\right)_{*}-f_{*}=-E H_{*} $$ and conclude that the mean curvature \(H\) of \(\mathbf{x}(U) \subset S\) is constant if and only if \(\phi\) is an analytic function of \(\zeta\) (i.e., \(\left(\phi_{1}\right)_{a}=\left(\phi_{2}\right)_{2},\left(\phi_{1}\right)_{\nu}=\) \(\left.-\left(\phi_{2}\right)_{2}\right) .\) h. Define the "complex derivative" $$ \frac{\partial}{\partial \bar{\zeta}}=\frac{1}{2}\left(\frac{a}{\partial x}-i \frac{\partial}{\partial x}\right) \text {. } $$ and prove that \(\phi(\zeta)=-2\left\langle\mathbf{x}_{\gamma}, N_{\zeta}\right\rangle\), where by \(\mathbf{x}_{c}\), for instance, we mean the vector with complex coordinates $$ \mathbf{x}_{p}=\left(\frac{\partial x}{\partial \zeta}, \frac{\partial y}{\partial \zeta}, \frac{\partial z}{\partial \zeta}\right) $$ c. Let \(f: U \subset C \rightarrow V \subset C\) be a one-to-one complex function given by \(f(u+i v)=x+i y=\eta\). Show that \((x, y)\) are isothermal parameters on \(S\) (i.e., \(\eta\) is a complex parameter on \(S\) ) if and only if \(f\) is analytic and \(f^{\prime}(\zeta) \neq 0, \zeta\) \& \(U\). Let \(\mathbf{y}=\mathbf{x} \circ f^{-1}\) be the correspond ing parametrization and define \(\phi(\eta)=-2\left\\{\mathbf{y}_{4}, N_{4}\right\\}\). Show that on \(x(U) \cap y(V) .\) $$ \phi(\zeta)=\psi(\eta)\left(\frac{3 \eta}{\partial \zeta}\right)^{2} $$ d. Let \(S^{2}\) be the unit sphere of \(R^{3}\). Use the stereographic projection (cf. Exercise 16, Sec. 2.2) from the poles \(N=(0,0,1)\) and \(S=(0,0,-1)\) to cover \(S^{2}\) by the coordinate neighborhoods of two (isothermal) complex parameters, \(\zeta\) and \(\eta\), with \(\zeta(S)=0\) and \(n(N)=0\), in such a way that in the intersection \(W\) of these coordinate neighborhoods (the sphere minus the two poles) \(\eta=\zeta^{-1}\). Assume that there exists on each coontinate neighborhood analytic functicns \(\psi(\zeta), \psi(n)\) such that \((+)\) holds in W. Use Liouville's theorem to prove that \(\varphi(\zeta)=0\) (hence, \(\psi(\eta)=0\) ). c. Let \(S \subset R^{3}\) be a regular surface with constant mean curvature homeomorphic to a sphere. Assume that there exists a conformal diffeomorphism \(\varphi: S \rightarrow S^{2}\) of \(S\) onto the unit sphere \(S^{2}\) (this is a consequence of the uniformization theorem for Riemann surfaces and will be assumed here). Let \(\bar{\zeta}\) and \(\bar{\eta}\) be the complex parameters corresponding ander \(\varphi\) to the parameters \(\zeta\) and \(\eta\) of \(S^{2}\) given in part \(\mathrm{d}\). By part a, the function \(\phi(\bar{\zeta})=((e-g) / 2)-\) if is analytic. The similar function \(\psi(\bar{p})\) is also 5.3. Complete Surfaces. Theorem of Hopf.Aioow \(93 t\) analytic, and by part c they are related by \((+)\). Use part d to show that \(\phi(\bar{\zeta})=0\) (hence, \(\psi(\bar{i})=0\) ). Conclude that \(S\) is made up of umbilical points and hence is a sphere. This proves Hopf's theorem.

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