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Let \(\alpha: I \rightarrow R^{3}\) be a regular parametrized curve with \(k(t) \neq 0, t \in I\). Let \(\mathbf{x}(t, v)\) be its tangent surface. Prove that, for each \(\left(t_{0}, v_{0}\right) \in I \times\) \((R-\\{0\\})\), there exists a neighborhood \(V\) of \(\left(t_{0}, v_{0}\right)\) such that \(\mathbf{x}(V)\) is isometric to an open set of the plane (thus, tangent surfaces are locally isometric to planes).

Short Answer

Expert verified
The tangent surface can be locally approximated by isometry to the plane using Gaussian coordinates and small neighborhoods around \(t_0, v_0\).

Step by step solution

01

Understand the tangent surface

The tangent surface to \(\backslashalpha(t)\) is given by the parametrization \(\backslashmathbf{x}(t, v) = \backslashalpha(t) + v \frac{\backslashmathrm{d} \backslashalpha(t)}{\backslashmathrm{d} t}\), where \(\backslashalpha(t)\) is a regular parametrized curve and \(\frac{\backslashmathrm{d} \backslashalpha(t)}{\backslashmathrm{d} t}\) is its tangent vector.
02

Compute the first fundamental form

Calculate the metric coefficients \(E, F,\) and \(G\) of the first fundamental form. Noting that \(\backslashmathbf{x}_t = \frac{\backslashmathrm{d} \backslashalpha(t)}{\backslashmathrm{d} t} + v \frac{\backslashmathrm{d}^2 \backslashalpha(t)}{\backslashmathrm{d} t^2}\) and \(\backslashmathbf{x}_v = \frac{\backslashmathrm{d} \backslashalpha(t)}{\backslashmathrm{d} t}\), we find: \(E = \backslashmathbf{x}_t \backslashcdot \backslashmathbf{x}_t, F = \backslashmathbf{x}_t \backslashcdot \backslashmathbf{x}_v, G = \backslashmathbf{x}_v \backslashcdot \backslashmathbf{x}_v\).
03

Evaluate the metric coefficients

Since \(F = \backslashmathbf{x}_t \backslashcdot \backslashmathbf{x}_v = \frac{\backslashmathrm{d} \backslashalpha(t)}{\backslashmathrm{d} t} \backslashcdot \frac{\backslashmathrm{d} \backslashalpha(t)}{\backslashmathrm{d} t} = E\) and \(\backslashmathbf{x}_v \backslashcdot \backslashmathbf{x}_v = G\) we get specific forms for \(E\) and \(G\).
04

Introduce Gaussian coordinates transformation

We use Gaussian coordinates \((u, w)\) to simplify the form. Let \(u = t\) and \(w = \backslashint k(t) \backslashmathrm{d} t + v\), this helps isolate changes in the \(t\) direction to \(k(t) \backslashmathrm{d} t\) and other terms.
05

Identify a suitable neighborhood

By picking a small enough neighborhood \((t_0, v_0)\), ensure that the changes in the metric coefficients \(E\) and \(G\) remain small and hence resemble those of a Euclidean plane.
06

Demonstrate the isometry locally

Show that in this neighborhood, the first fundamental form \(ds^2 = E backslashmathrm{d} u^2 + 2F backslashmathrm{d} u backslashmathrm{d} v + G backslashmathrm{d} v^2\) approximates \(du^2 + dv^2\) visually using the Gaussian transformation.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Tangent Surface
A tangent surface provides a fascinating way to visualize the geometry of curves in 3D space. Given a regular parametric curve \(\backslashalpha(t)\), the tangent surface is defined using the parametrization: \(\backslashmathbf{x}(t, v) = \backslashalpha(t) + v \frac{\backslashmathrm{d} \backslashalpha(t)}{\backslashmathrm{d} t}\). Here, \(\backslashalpha(t)\) is the curve itself and \(\frac{\backslashmathrm{d} \backslashalpha(t)}{\backslashmathrm{d} t}\) represents the tangent vector at each point along the curve. Think of it as extending a vector from each point on \(\backslashalpha(t)\) in the direction of its tangent. By varying 'v', this extension forms a surface. This surface is important because it inherently ties the properties of the curve into a spatial structure that can reveal more about the curve's behavior in 3D space.
First Fundamental Form
The first fundamental form is a crucial concept used to describe surfaces mathematically. It's essentially a way to measure distances and angles on surfaces. For the tangent surface \(\backslashmathbf{x}(t, v)\), we need to calculate its metric coefficients: \(E, F\), and \(G\).
These are derived as follows:
  • \textrm{Calculate \(\backslashmathbf{x}_t = \frac{\backslashmathrm{d} \backslashalpha(t)}{\backslashmathrm{d} t} + v \frac{\backslashmathrm{d}^2 \backslashalpha(t)}{\backslashmathrm{d}^2 t}\)}
  • \textrm{Calculate \(\backslashmathbf{x}_v = \frac{\backslashmathrm{d} \backslashalpha(t)}{\backslashmathrm{d} t}\)}

Therefore, \(E = \backslashmathbf{x}_t \backslashcdot \backslashmathbf{x}_t\), \(F = \backslashmathbf{x}_t \backslashcdot \backslashmathbf{x}_v\) and \(G = \backslashmathbf{x}_v \backslashcdot \backslashmathbf{x}_v\).

From our computation, we observe:
\textrm{Since \(F = \backslashmathbf{x}_t \backslashcdot \backslashmathbf{x}_v = \frac{\backslashmathrm{d} \backslashalpha(t)}{\backslashmathrm{d} t} \backslashcdot \frac{\backslashmathrm{d} \backslashalpha(t)}{\backslashmathrm{d} t} = E\) and \(G = \backslashmathbf{x}_v \backslashcdot \backslashmathbf{x}_v.\)}
The first fundamental form is mathematically represented as:
\textrm{\textrm{\textrm{\textrm{\( ds\^2 = E dt\^2 + 2F dt dv + G dv\^2 \)}}.}} It provides a way to measure how the surface bends and stretches. Here, E, F, and G are coefficients that change depending on the local property of the surface.
Gaussian Coordinates
To make the computations easier and clearer, we use Gaussian coordinates transformation. This transformation helps us simplify the form of the first fundamental form. If we let \(u = t\) and \(w = \backslashint k(t) \backslashmathrm{d} t + v\), we essentially change to a coordinate system that simplifies the terms involving change in 't' direction to terms involving \(k(t) \backslashmathrm{d} t\) and other simpler terms. By doing this, we can isolate the variations in the surface and see how it transforms to be isometric to a plane locally.
To summarize:
  • We look at a small enough neighborhood around a point on this tangent surface.
  • Here, the change in our metric coefficients \(E\) and \(G\) remains small and consistent.

This allows us to show that in this local region, our surface behaves like a Euclidean plane, meaning distances and angles can be measured as if we were on a flat plane. This local isometry is a powerful result as it simplifies understanding the surface geometry and provides insight into the intrinsic properties of the curve and surface.

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Most popular questions from this chapter

Let \(V\) and \(W\) be ( \(n\)-dimensional) vector spaces with inner products \(\langle,\),\(rangle .\) Let \(G: V \rightarrow W\) be a linear map. Prove that the following conditions are equivalent: a. There exists a real constant \(\lambda \neq 0\) such that $$ \left\langle G\left(v_{1}\right), G\left(v_{2}\right)\right\rangle=\lambda^{2}\left\langle v_{1}, v_{2}\right\rangle \quad \text { for all } v_{1}, v_{2} \in V . $$ b. There exists a real constant \(\lambda>0\) such that $$ |G(v)|=\lambda|v| \quad \text { for all } v \in V $$ c. There exists an orthonormal basis \(\left\\{v_{1}, \ldots, v_{n}\right\\}\) of \(V\) such that \(\left\\{G\left(v_{1}\right), \ldots, G\left(v_{n}\right)\right\\}\) is an orthogonal basis of \(W\) and, also, the vectors \(G\left(v_{i}\right), i=1, \ldots, n\), have the same (nonzero) length. If any of these conditions is satisfied, \(G\) is called a linear conformal map (or a similitude).

a. Show that if a curve \(C \subset S\) is both a line of curvature and a geodesic, then \(C\) is a plane curve. b. Show that if a (nonrectilinear) geodesic is a plane curve, then it is a line of curvature. c. Give an example of a line of curvature which is a plane curve and not a geodesic.

Show that if \(\mathbf{x}\) is an orthogonal parametrization, that is, \(F=0\), then $$ K=-\frac{1}{2 \sqrt{E G}}\left\\{\left(\frac{E_{v}}{\sqrt{E G}}\right)_{v}+\left(\frac{G_{u}}{\sqrt{E G}}\right)_{u}\right\\} . $$

Let \(y\) and \(w\) be differentiable vector fields on an open set \(U \subset S .\) Let \(p \in S\) and let \(\alpha: I \rightarrow U\) be a curve such that \(\alpha(0)=p, \alpha^{\prime}(0)=y\). Denote by \(P_{\alpha, t}: T_{\alpha(0)}(S) \rightarrow T_{\alpha(t)}(S)\) the parallel transport along \(\alpha\) from \(\alpha(0)\) to \(\alpha(t), t \in I\). Prove that $$ \left(D_{y} w\right)(p)=\left.\frac{d}{d t}\left(P_{\alpha, t}^{-1}(w(\alpha(t)))\right)\right|_{t=0} $$ where the second member is the velocity vector of the curve \(P_{\alpha, t}^{-1}(w(\alpha(t)))\) in \(T_{p}(S)\) at \(t=0\). (Thus, the notion of covariant derivative can be derived from the notion of parallel transport.)

Let \(\alpha: I=[0, l] \rightarrow S\) be a simple, parametrized, regular curve. Consider a unit vector field \(v(t)\) along \(\alpha\), with \(\left\langle\alpha^{\prime}(t), v(t)\right\rangle=0\) and a mapping \(\mathbf{x}: R \times I \rightarrow S\) given by $$ \mathbf{x}(s, t)=\exp _{\alpha(t)}(s v(t)), \quad s \in R, t \in I $$ a. Show that \(\mathbf{x}\) is differentiable in a neighborhood of \(I\) in \(R \times I\) and that \(d \mathbf{x}\) is nonsingular in \((0, t), t \in I\). b. Show that there exists \(\epsilon>0\) such that \(\mathbf{x}\) is one-to-one in the rectangle \(t \in I,|s|<\epsilon\). c. Show that in the open set \(t \in(0, l),|s|<\epsilon, \mathbf{x}\) is a parametrization of \(S\), the coordinate neighborhood of which contains \(\alpha((0, l))\). The coordinates thus obtained are called geodesic coordinates (or Fermi's coordinates) of basis \(\alpha\). Show that in such a system \(F=0, E=1\). Moreover, if \(\alpha\) is a geodesic parametrized by the arc length, \(G(0, t)=\) 1 and \(G_{s}(0, t)=0\). d. Establish the following analogue of the Gauss lemma (Remark 1 after Prop. 3, Sec. 4-6). Let \(\alpha: I \rightarrow S\) be a regular parametrized curve and let \(\gamma_{t}(s), t \in I\), be a family of geodesics parametrized by arc length \(s\) and given by; \(\gamma_{t}(0)=\alpha(t),\left\\{\gamma_{t}^{\prime}(0), \alpha^{\prime}(t)\right\\}\) is a positive orthogonal basis. Then, for a fixed \(\bar{s}\), sufficiently small, the curve \(t \rightarrow \gamma_{t}(\bar{s}), t \in I\), intersects all \(\gamma_{t}\) orthogonally (such curves are called geodesic parallels).

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