/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 4 Show that in a system of normal ... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

Show that in a system of normal coordinates centered in \(p\), all the Christoffel symbols are zero at \(p\).

Short Answer

Expert verified
In normal coordinates centered at \(p\), the Christoffel symbols \(\Gamma^k_{ij}(p) = 0\).

Step by step solution

01

Understanding Normal Coordinates

Normal coordinates are a coordinate system where geodesics through a point can be represented as straight lines. At a point \(p\), the metric tensor is the identity matrix, and its first derivatives vanish.
02

Define Christoffel Symbols

The Christoffel symbols \(\Gamma^k_{ij}\) in terms of the metric tensor \(g_{ij}\) are given by: \[\Gamma^k_{ij} = \frac{1}{2} g^{kl} \left( \frac{\partial g_{li}}{\partial x^j} + \frac{\partial g_{lj}}{\partial x^i} - \frac{\partial g_{ij}}{\partial x^l} \right)\]
03

Evaluate Metric at Point p

In normal coordinates centered at point \(p\), by definition, the metric tensor \(g_{ij}(p) = \delta_{ij}\) and \(\frac{\partial g_{ij}}{\partial x^k}(p) = 0\).
04

Substitute into Christoffel Symbols

Using the conditions from Step 3, substitute \(g_{ij} = \delta_{ij}\) and \(\frac{\partial g_{ij}}{\partial x^k} = 0\) into the Christoffel symbol equation. \[\Gamma^k_{ij}(p) = \frac{1}{2} g^{kl} \left( \frac{\partial g_{li}}{\partial x^j}(p) + \frac{\partial g_{lj}}{\partial x^i}(p) - \frac{\partial g_{ij}}{\partial x^l}(p) \right) = 0\]
05

Conclusion

Since all the partial derivatives of the metric tensor at \(p\) are zero, the Christoffel symbols \(\Gamma^k_{ij}(p)\) are also zero. This confirms that in a system of normal coordinates centered at \(p\), all Christoffel symbols vanish at \(p\).

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

The Metric Tensor
The metric tensor is a fundamental concept in differential geometry. It provides a way to measure distances and angles between vectors in a manifold. Mathematically, the metric tensor, usually denoted as \( g_{ij} \), is a symmetric rank-2 tensor that varies smoothly from point to point on a manifold. In simpler terms, it defines the geometry of the space.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

Let \(S \subset R^{3}\) be a regular, compact, connected, orientable surface which is not homeomorphic to a sphere. Prove that there are points on \(S\) where the Gaussian curvature is positive, negative, and zero.

Prove that an orientable compact surface \(S \subset R^{3}\) has a differentiable vector field without singular points if and only if \(S\) is homeomorphic to a torus.

Consider the torus of revolution generated by rotating the circle $$ (x-a)^{2}+z^{2}=r^{2}, y=0, $$ about the \(z\) axis \((a>r>0)\). The parallels generated by the points \((a+r, 0),(a-r, 0),(a, r)\) are called the maximum parallel, the minimum parallel, and the upper parallel, respectively. Check which of these parallels is a. A geodesic. b. An asymptotic curve. c. A line of curvature.

a. Show that if a curve \(C \subset S\) is both a line of curvature and a geodesic, then \(C\) is a plane curve. b. Show that if a (nonrectilinear) geodesic is a plane curve, then it is a line of curvature. c. Give an example of a line of curvature which is a plane curve and not a geodesic.

Surfaces of Liouville are those surfaces for which it is possible to obtain a system of local coordinates \(\mathbf{x}(u, v)\) such that the coefficients of the first fundamental form are written in the form $$ E=G=U+V, \quad F=0 $$ where \(U=U(u)\) is a function of \(u\) alone and \(V=V(v)\) is a function of \(v\) alone. Observe that the surfaces of Liouville generalize the surfaces of revolution and prove that (cf. Example 5) a. The geodesics of a surface of Liouville may be obtained by integration in the form $$ \int \frac{d u}{\sqrt{U-c}}=\pm \int \frac{d v}{\sqrt{V+c}}+c_{1} $$ where \(c\) and \(c_{1}\) are constants that depend on the initial conditions. b. If \(\theta, 0 \leq \theta \leq \pi / 2\), is the angle which a geodesic makes with the curve \(v=\) const., then $$ U \sin ^{2} \theta-V \cos ^{2} \theta=\mathrm{const} $$ (Notice that this is the analogue of Clairaut's relation for the surfaces of Liouville.)

See all solutions

Recommended explanations on Math Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.