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We say that a differentiable map \(\varphi: S_{1} \rightarrow S_{2}\) preserves angles when for every \(p \in S_{1}\) and every pair \(v_{1}, v_{2} \in T_{p}\left(S_{1}\right)\) we have $$ \cos \left(v_{1}, v_{2}\right)=\cos \left(d \varphi_{p}\left(v_{1}\right), d \varphi_{p}\left(v_{2}\right)\right) . $$ Prove that \(\varphi\) is locally conformal if and only if it preserves angles.

Short Answer

Expert verified
Locally conformal maps preserve angles, showing that angle preservation implies local conformality, and vice versa, as shown through the behavior of the differential map.

Step by step solution

01

Understand Given Conditions

We are given a differentiable map \(\textcolor{darkviolet}{\text{\varphi : S_1 \rightarrow S_2}}\textcolor{}\). The map is said to preserve angles if for any point \(\textcolor{darkviolet}{\text{p}}\textcolor{}\) in \(\textcolor{darkviolet}{\text{S_1}}\textcolor{}\) and any pair of vectors \(\textcolor{darkviolet}{\text{v_1, v_2 \text{ in } T_p(S_1)}}\textcolor{darkviolet}\), the following equation is satisfied: \(\textcolor{darkviolet}{\text{\cos\left(v_1, v_2\right) = \cos\left(d\varphi_p\left(v_1\right), d\varphi_p\left(v_2\right)\right) }}\).
02

Define Local Conformality

A map \(\textcolor{darkviolet}{\text{\varphi: S_1 \rightarrow S_2}}\textcolor{}\) is locally conformal if, for every point \(\textcolor{darkviolet}{\text{p}}\textcolor{}\) in \(\textcolor{darkviolet}{\text{S_1}}\textcolor{}\), there exists a neighborhood around \(\textcolor{darkviolet}{\text{p}}\textcolor{}\) within which \(\textcolor{darkviolet}{\text{\varphi}}\textcolor{}\) behaves like a scaled isometry, i.e., \(\textcolor{darkviolet}{\text{d\varphi_p}}\textcolor{}\) preserves angles and scales lengths by a factor.
03

Show Angle Preservation Implies Local Conformality

Given that \(\textcolor{darkviolet}{\text{\varphi}}\textcolor{}\) preserves angles, angle preservation can be expressed by the equation \(\textcolor{darkviolet}{\text{ \cos (v_1, v_2) = \tt{\cos} (d\varphi_p(v_1), d\varphi_p(v_2)) }}\). This indicates that \(\textcolor{darkviolet}{\text{d\varphi_p}}\textcolor{}\) is angle-preserving, which is one condition for conformality.
04

Prove that \(\text{\varphi}\textcolor{}\) is locally conformal

Local conformality means that \(\textcolor{darkviolet}{\text{d\varphi_p}}\textcolor{}\) at any \(\textcolor{darkviolet}{\text{p}}\textcolor{}\) can be written as \(\textcolor{darkviolet}{rQ}\textcolor{}\) where \(\textcolor{darkviolet}{\text{r}}\textcolor{}\) is a nonzero scalar and \(\textcolor{darkviolet}{\text{Q}}\textcolor{}\) is an orthogonal transformation. Angle preservation guarantees the existence of such \(\textcolor{darkviolet}{\text{Q}}\textcolor{}\) since it maps an orthonormal basis of \(\textcolor{darkviolet}{\text{T_p(S_1)}}\textcolor{}\) to another orthonormal basis with preservation of angles.
05

Necessity of Local Conformality for Preserving Angles

If \(\textcolor{darkviolet}{\text{\varphi}}\textcolor{}\) is locally conformal, it implies that \(\textcolor{darkviolet}{\text{d\varphi_p}}\textcolor{}\) is an isometry up to scale, hence preserving angles. Therefore, an angle-preserving map is a local diffeomorphism and satisfies the conditions for local conformality.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Differentiable Map
A differentiable map, also known as a differentiable function, is a function between two smooth manifolds that preserves the smooth structure. This means that at every point in the domain, there is a neighborhood where the function can be closely approximated by a differentiable function between Euclidean spaces. In simpler terms, if you pick any point in one space, the function will behave smoothly around that point, allowing you to take derivatives. The important thing here is that differentiability ensures the map is smooth and has a well-defined tangent relationship. This property is crucial when discussing concepts like angle preservation and local conformality, as it allows us to use differential calculus to understand how the map transforms vectors and angles.
Local Conformality
Local conformality refers to the property where a map behaves like a scaled isometry in a small neighborhood around any point. This means that angles are preserved and distances are scaled uniformly by a certain factor. Think of it as zooming in on a map function at a particular point: although the global shape might differ, locally, angles remain consistent and every small line segment's length is multiplied by the same factor. In mathematical terms, a map \( \varphi: S_1 \rightarrow S_2 \) is locally conformal at point \( \text{p} \) if there exists a neighborhood around \( \text{p} \) within which the differential \( \text{d\textbackslash varphi\textbackslash _p} \) can be expressed as \( \text{rQ}\f\), where \( \text{r} \) is a nonzero scalar and \( \text{Q} \) is an orthogonal transformation. This fundamental property guarantees that very small shapes and angles are preserved and only scaled.
Orthogonal Transformation
An orthogonal transformation is a transformation that preserves angles and distances. In the context of linear algebra and geometry, it refers to a linear map that preserves the dot product of vectors. What this means is that if you have two vectors and you transform them using an orthogonal transformation, the angle between the two vectors will remain the same.
Mathematically, a matrix \( \text{Q} \in O(n) \) is said to be orthogonal if \( \text{Q^\text{\textbackslash T}Q} = \text{I} \), where \( \text{I} \) is the identity matrix. Here, \( \text{Q^\text{\textbackslash T}} \) is the transpose of \( \text{Q} \), implying that the columns (and rows) of \( \text{Q} \) are orthonormal vectors.
In the context of angle preservation, when a map's differential \( \text{\textbackslash varphi} \text{d\textbackslash varphi\textbackslash\textunderscore p} \) can be expressed as \( \text{rQ}, \) the transformation \( \text{Q} \) ensures that angles are preserved, illustrating how orthogonal transformations play a crucial role in maintaining geometric properties during transformations.

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Most popular questions from this chapter

Let \(\varphi: R^{2} \rightarrow R^{2}\) be given by \(\varphi(x, y)=(u(x, y), v(x, y))\), where \(u\) and \(v\) are differentiable functions that satisfy the Cauchy-Riemann equations $$ u_{x}=v_{y}, \quad u_{y}=-v_{x} $$ Show that \(\varphi\) is a local conformal map from \(R^{2}-Q\) into \(R^{2}\), where \(Q=\left\\{(x, y) \in R^{2} ; u_{x}^{2}+u_{y}^{2}=0\right\\}\).

If \(p\) is a point of a regular surface \(S\), prove that $$ K(p)=\lim _{r \rightarrow 0} \frac{12}{\pi} \frac{\pi r^{2}-A}{r^{4}} $$ where \(K(p)\) is the Gaussian curvature of \(S\) at \(p, r\) is the radius of a geodesic circle \(S_{r}(p)\) centered in \(p\), and \(A\) is the area of the region bounded by \(S_{r}(p)\).

A diffeomorphism \(\varphi: S_{1} \rightarrow S_{2}\) is said to be a geodesic mapping if for every geodesic \(C \subset S_{1}\) of \(S_{1}\), the regular curve \(\varphi(C) \subset S_{2}\) is a geodesic of \(S_{2}\). If \(U\) is a neighborhood of \(p \in S_{1}\), then \(\varphi: U \rightarrow S_{2}\) is said to be a local geodesic mapping in \(p\) if there exists a neighborhood \(V\) of \(\varphi(p)\) in \(S_{2}\) such that \(\varphi: U \rightarrow V\) is a geodesic mapping. a. Show that if \(\varphi: S_{1} \rightarrow S_{2}\) is both a geodesic and a conformal mapping, then \(\varphi\) is a similarity; that is, $$ \langle v, w\rangle_{p}=\lambda\left\langle d \varphi_{p}(v), d \varphi_{p}(w)\right\rangle_{\varphi(p)}, \quad p \in S_{1}, v, w \in T_{p}\left(S_{1}\right), $$ where \(\lambda\) is constant. b. Let \(S^{2}=\left\\{(x, y, z) \in R^{3} ; x^{2}+y^{2}+z^{2}=1\right\\}\) be the unit sphere, \(S^{-}=\) \(\left\\{(x, y, z) \in S^{2} ; z<0\right\\}\) be its lower hemisphere, and \(P\) be the plane \(z=-1\). Prove that the map (central projection) \(\varphi: S^{-} \rightarrow P\) which takes a point \(p \in S^{-}\)to the intersection of \(P\) with the line that connects \(p\) to the center of \(S^{2}\) is a geodesic mapping. c. Show that a surface of constant curvature admits a local geodesic mapping into the plane for every \(p \in S\).

Let \(S \subset R^{3}\) be a regular compact surface with \(K>0 .\) Let \(\Gamma \subset S\) be a simple closed geodesic in \(S\), and let \(A\) and \(B\) be the regions of \(S\) which have \(\boldsymbol{\Gamma}\) as a common boundary. Let \(N: S \rightarrow S^{2}\) be the Gauss map of \(S\). Prove that \(N(A)\) and \(N(B)\) have the same area.

Prove that a curve \(C \subset S\) is both an asymptotic curve and a geodesic if and only if \(C\) is a (segment of a) straight line.

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