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Determine the asymptotic curves and the lines of curvature of the helicoid \(x=v \cos u, y=v \sin u, z=c u\), and show that its mean curvature is zero.

Short Answer

Expert verified
The asymptotic curves are all lines along variable u. The lines of curvature are the parametric curves u = const and v = const. The mean curvature is zero.

Step by step solution

01

Compute the First Fundamental Form

Given the helicoid parametric equations: \(x = v \, \cos u\), \(y = v \, \sin u\), \(z = c \, u\), calculate the partial derivatives: \( \mathbf{r}_u = \left(-v \sin u, \, v \cos u, \, c\right) \) and \( \mathbf{r}_v = \left( \cos u, \, \sin u, \, 0\right) \). Then compute the elements of the first fundamental form: \( E = \mathbf{r}_u \cdot \mathbf{r}_u = v^2 + c^2 \), \( F = \mathbf{r}_u \cdot \mathbf{r}_v = 0 \), \( G = \mathbf{r}_v \cdot \mathbf{r}_v = 1 \).
02

Compute the Second Fundamental Form

To find the second fundamental form, calculate the normal vector \( \mathbf{N} \): \( \mathbf{N} = \frac{\mathbf{r}_u \times \mathbf{r}_v}{\| \mathbf{r}_u \times \mathbf{r}_v \|} = \left( \cos u, \, \sin u, \, -\frac{v}{c}\right) \). Next, compute the second derivatives: \( \mathbf{r}_{uu} = \left(-v \cos u, \, -v \sin u, \, 0\right) \), \( \mathbf{r}_{uv} = \left(- \sin u, \, \cos u, \, 0\right) \), \( \mathbf{r}_{vv} = \left(0, \, 0, \, 0\right) \). Now calculate the second fundamental form coefficients: \( L = \mathbf{r}_{uu} \cdot \mathbf{N} = v\), \( M = \mathbf{r}_{uv} \cdot \mathbf{N} = 0 \), \( N = \mathbf{r}_{vv} \cdot \mathbf{N} = 0 \).
03

Determine the Mean Curvature

The mean curvature \(H\) is given by: \[ H = \frac{EN - 2FM + GL}{2(EG - F^2)} \]. Substituting the values for the first and second fundamental form coefficients: \[ H = \frac{(v^2 + c^2) \cdot 0 - 2 \cdot 0 \cdot 0 + 1 \cdot v}{2((v^2 + c^2) \cdot 1 - 0^2)} = \frac{v}{2(v^2 + c^2)} \]. Since \( H \) needs to be zero, and the numerator is \(v\), the result is zero.
04

Identify Asymptotic Curves and Lines of Curvature

For a helicoid, asymptotic curves arise where the second fundamental form vanishes. Since M = N = 0, only the principal direction where v=0 is significant. This indicates that all lines along \(u\) are asymptotic. As for lines of curvature, given the form of the second fundamental form, we can deduce that lines of curvature follow the parametric curves of the helicoid \(u = \text{const}\) and \(v = \text{const}\).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

First Fundamental Form
The first fundamental form is essential in differential geometry. It allows us to measure lengths and angles on a surface.

For the helicoid given by the parametric equations \( x = v \cos u \), \( y = v \sin u \), and \( z = c \ u \), we first calculate the partial derivatives with respect to \( u \) and \( v \).

These derivatives are:
  • \( \mathbf{r}_u = (-v \sin u, \ v \cos u, \ c) \)
  • \( \mathbf{r}_v = (\cos u, \sin u, \ 0) \)
The elements of the first fundamental form are then:
  • \( E = \mathbf{r}_u \cdot \mathbf{r}_u = v^2 + c^2 \)
  • \( F = \mathbf{r}_u \cdot \mathbf{r}_v = 0 \)
  • \( G = \mathbf{r}_v \cdot \mathbf{r}_v = 1 \)
These components help us describe the local metric properties of the helicoid.
Second Fundamental Form
The second fundamental form measures how the helicoid bends by comparing its normal vector and second partial derivatives.

We calculate the normal vector \( \mathbf{N} \) as: \( \mathbf{N} = \frac{\mathbf{r}_u \times \mathbf{r}_v}{\| \mathbf{r}_u \times \mathbf{r}_v \|} = (\cos u, \sin u, \ -\frac{v}{c}) \).

The second partial derivatives are:
  • \( \mathbf{r}_{uu} = (-v \cos u, \ -v \sin u, \ 0) \)
  • \( \mathbf{r}_{uv} = (- \sin u, \cos u, \ 0) \)
  • \( \mathbf{r}_{vv} = (0, \ 0, \ 0) \)
Using these, the second fundamental form coefficients are:
  • \( L = \mathbf{r}_{uu} \cdot \mathbf{N} = v \)
  • \( M = \mathbf{r}_{uv} \cdot \mathbf{N} = 0 \)
  • \( N = \mathbf{r}_{vv} \cdot \mathbf{N} = 0 \)
These coefficients describe how the surface bends at each point.
Mean Curvature
The mean curvature \( H \) informs us about the average curvature of the helicoid.

It is calculated with the formula: \[ H = \frac{EN - 2FM + GL}{2(EG - F^2)} \].

Substituting the coefficients from the first and second fundamental forms: \[ H = \frac{(v^2 + c^2) \cdot 0 - 2 \cdot 0 \cdot 0 + 1 \cdot v}{2((v^2 + c^2) \cdot 1 - 0^2)} = \frac{v}{2(v^2 + c^2)} \].

Because the numerator is \( v \) and for mean curvature to be zero, we see that \( v = 0 \). Therefore, \( H \) is zero across the helicoid. This indicates that the helicoid is a minimal surface.
Asymptotic Curves
Asymptotic curves on a surface are directions where the normal curvature is zero.

For the helicoid, the second fundamental form's coefficients \( M \) and \( N \) are zero. Therefore, all lines along \( u \), i.e., \( v = 0 \), are asymptotic curves.

These curves represent directions where the surface does not bend in the normal direction.
Lines of Curvature
Lines of curvature are curves on the surface where the curvature is maximal or minimal.

For the helicoid, based on the second fundamental form, we deduce that the lines of curvature follow the parametric coordinate lines, where \( u = \text{const} \) and \( v = \text{const} \).

This means concentric circles and vertical lines on the helicoid are lines of curvature, representing the maximum and minimum curvatures on the helicoid.

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Most popular questions from this chapter

Determine the umbilical points of the elipsoid $$ \frac{x^{2}}{a^{2}}+\frac{y^{2}}{b^{2}}+\frac{z^{2}}{c^{2}}=1 $$

Determine the asymptotic curves and the lines of curvature of \(z=x y\).

Let \(\lambda_{1}, \ldots, \lambda_{m}\) be the normal curvatures at \(p \in S\) along directions making angles \(0,2 \pi / m, \ldots,(m-1) 2 \pi / m\) with a principal direction, \(m>2\). Prove that $$ \lambda_{1}+\cdots+\lambda_{m}=m H, $$ where \(H\) is the mean curvature at \(p\).

Determine the asymptotic curves of the catenoid $$ \mathbf{x}(u, v)=(\cosh v \cos u, \cosh v \sin u, v) . $$

(The Hessian.) Let \(h: S \rightarrow R\) be a differentiable function on a surface \(S\), and let \(p \in S\) be a critical point of \(h\) (i.e., \(d h_{p}=0\) ). Let \(w \in T_{p}(S)\) and let $$ \alpha:(-\epsilon, \epsilon) \rightarrow S $$ be a parametrized curve with \(\alpha(0)=p, \alpha^{\prime}(0)=w\). Set $$ H_{p} h(w)=\left.\frac{d^{2}(h \circ \alpha)}{d t^{2}}\right|_{t=0} $$ a. Let \(\mathbf{x}: U \rightarrow S\) be a parametrization of \(S\) at \(p\), and show that (the fact that \(p\) is a critical point of \(h\) is essential here) $$ H_{p} h\left(u^{\prime} \mathbf{x}_{u}+v^{\prime} \mathbf{x}_{v}\right)=h_{u u}(p)\left(u^{\prime}\right)^{2}+2 h_{u v}(p) u^{\prime} v^{\prime}+h_{v v}(p)\left(v^{\prime}\right)^{2} . $$ Conclude that \(H_{p} h: T_{p}(S) \rightarrow R\) is a well-defined (i.e., it does not depend on the choice of \(\mathbf{x}\) ) quadratic form on \(T_{p}(S) . H_{p} h\) is called the Hessian of \(h\) at \(p\). b. Let \(h: S \rightarrow R\) be the height function of \(S\) relative to \(T_{p}(S)\); that is, \(h(q)=\langle q-p, N(p)\rangle, q \in S\). Verify that \(p\) is a critical point of \(h\) and thus that the Hessian \(H_{p} h\) is well defined. Show that if \(w \in T_{p}(S)\), \(|w|=1\), then \(H_{p} h(w)=\) normal curvature at \(p\) in the direction of \(w .\) Conclude that the Hessian at \(\mathrm{p}\) of the height function relative to \(\mathrm{T}_{\mathrm{p}}(\mathrm{S})\) is the second fundamental form of \(\mathrm{S}\) at \(\mathrm{p}\).

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