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In Problems 1-10 use the finite difference method and the indicated value of \(n\) to approximate the solution of the given boundary-value problem. \(x^{2} y^{\prime \prime}-x y^{\prime}+y=\ln x, \quad y(1)=0, y(2)=-2 ; \quad n=8\)

Short Answer

Expert verified
Approximate the solution by solving the derived linear system using finite differences.

Step by step solution

01

Understanding the Problem

We are given a boundary-value problem with a differential equation \( x^2 y'' - x y' + y = \ln x \) and boundary conditions \( y(1) = 0 \) and \( y(2) = -2 \). We need to approximate the solution using the finite difference method with \( n = 8 \).
02

Discretize the Interval

With \( n = 8 \), we divide the interval \([1, 2]\) into 8 equal parts. The step size \( h \) is given by \( h = \frac{2 - 1}{8} = 0.125 \). This gives us grid points at \( x_i = 1 + i \, h \) for \( i = 0, 1, \, ..., \, 8 \).
03

Finite Difference Approximations

We use finite difference approximations for derivatives. The second derivative \( y''(x_i) \approx \frac{y_{i+1} - 2y_i + y_{i-1}}{h^2} \) and the first derivative \( y'(x_i) \approx \frac{y_{i+1} - y_{i-1}}{2h} \).
04

Set Up the Finite Difference Equations

For each internal grid point \( i \), substitute the finite differences into the differential equation: \[ x_i^2 \frac{y_{i+1} - 2y_i + y_{i-1}}{h^2} - x_i \frac{y_{i+1} - y_{i-1}}{2h} + y_i = \ln x_i \]. This generates a system of linear equations.
05

Incorporate Boundary Conditions

Use the boundary conditions to simplify the system. For example, \( y_0 = 0 \) and \( y_8 = -2 \) are known, reducing the number of unknowns in the system of equations.
06

Solve the Linear System

Solve the system of linear equations generated to find the approximate values of \( y_i \) at each grid point. This can often be done via matrix methods such as LU decomposition, Gaussian elimination, or using computational tools.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Boundary-Value Problem
A boundary-value problem is a type of differential equation with specified values, called boundary conditions, at the endpoints of the interval of interest. In our case, the differential equation is \( x^2 y'' - x y' + y = \ln x \), which we need to solve in the interval from \(x = 1\) to \(x = 2\). The boundary conditions are \(y(1) = 0\) and \(y(2) = -2\), which means the solution must pass through these specific points.Boundary-value problems are essential in real-world applications, as they often represent physical situations where certain conditions are constrained at the boundaries, such as a beam fixed at both ends or the temperature distribution in a rod.
Differential Equation Approximation
Differential equation approximation involves finding a numerical solution to differential equations, especially when finding an exact analytical solution is complex or impossible. By using methods like the finite difference method, we can approximate the solution over discrete points in the interval. The benefit of approximation is that it converts the continuous problem into a discrete one, which is easier to solve computationally. This transformation is particularly useful in modeling physical processes where exact solutions cannot be formulated or are computationally expensive.
Grid Points
Grid points divide the interval of interest into smaller, distinct segments, allowing us to evaluate and approximate the solution to the differential equation at each point. In our example, the interval \([1, 2]\) is divided into \(n = 8\) equal parts, creating grid points.
  • The step size \(h\) is calculated as \(h = \frac{2 - 1}{8} = 0.125\).
  • The grid points \(x_i\) are determined by \(x_i = 1 + i \cdot h\) for \(i = 0, 1, ..., 8\).
These grid points are fundamental because they provide discrete locations where we apply the finite difference approximations to solve for \(y\).
Finite Difference Approximations
Finite difference approximations replace derivatives in differential equations with arithmetic operations on function values at grid points. This method simplifies solving differential equations numerically.For a first-order derivative at a point \(x_i\), we use:\[ y'(x_i) \approx \frac{y_{i+1} - y_{i-1}}{2h} \]For a second-order derivative at a point \(x_i\), we use:\[ y''(x_i) \approx \frac{y_{i+1} - 2y_i + y_{i-1}}{h^2} \]These approximations allow us to set up a system of linear equations that can be solved to approximate the solution to the boundary-value problem. Finite difference method is particularly valuable because it transforms differential equations into algebraic ones, easing both the interpretation and computation of solutions.

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Most popular questions from this chapter

Construct a table comparing the indicated values of \(y(x)\) using the Euler, improved Euler, and Runge-Kutta methods. Compute to four rounded decimal places. Use \(h=0.1\) and \(h=0.05\). $$ \begin{aligned} &y^{\prime}=x y+y^{2}, y(1)=1 ; \\ &y(1.1), y(1.2), y(1.3), y(1.4), y(1.5) \end{aligned} $$

The Runge-Kutta method for solving an initial-value problem over an interval \([a, b]\) results in a finite set of points that are supposed to approximate points on the graph of the exact solution. In order to expand this set of discrete points to an approximate solution defined at all points on the interval \([a, b]\) we can use an interpolating function. This is a function, supported by most computer algebra systems, that agrees with the given data exactly and assumes a smooth transition between data points. These interpolating functions may be polynomials or sets of polynomials joined together smoothly. In Mathematica the command \(y=\) Interpolation[data] can be used to obtain an interpolating function through the points data \(=\left\\{\left\\{x_{0}, y_{0}\right\\},\left\\{x_{1}, y_{1}\right\\}, \ldots\right.\), \(\left.\left\\{x_{n}, y_{n}\right\\}\right\\}\). The interpolating function \(y[\mathbf{x}]\) can now be treated like any other function built into the computer algebra system. (a) Find the exact solution of the initial-value problem \(y^{\prime}=-y+\) \(10 \sin 3 x, y(0)=0\) on the interval \([0,2]\). Graph this solution and find its positive roots. (b) Use the fourth-order Runge-Kutta method with \(h=0.1\) to approximate a solution of the initial-value problem in part (a). Obtain an interpolating function and graph it. Find the positive roots of the interpolating function on the interval \([0,2]\).

In Problems 1-10 use the finite difference method and the indicated value of \(n\) to approximate the solution of the given boundary-value problem. \(y^{\prime \prime}+2 y^{\prime}+y=5 x, \quad y(0)=0, y(1)=0 ; \quad n=5\)

Given the initial-value problems in Problems use the Runge-Kutta method with \(h=0.1\) to obtain a four-decimal-place approximation to the indicated value.\(y^{\prime}=x y+\sqrt{y}, y(0)=1 ; \quad y(0.5)\)

Consider the initial-value problem \(y^{\prime}=2 y, y(0)=1\). The analytic solution is \(y(x)=e^{2 x}\). (a) Approximate \(y(0.1)\) using one step and the fourth-order RungeKutta method. (b) Find a bound for the local truncation error in \(y_{1}\). (c) Compare the actual error in \(y_{1}\) with your error bound.(d) Approximate \(y(0.1)\) using two steps and the fourth-order RungeKutta method. (e) Verify that the global truncation error for the fourth-order RungeKutta method is \(O\left(h^{4}\right)\) by comparing the errors in parts (a) and (d).

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