Chapter 7: Problem 59
\(f(t)=\mathscr{L}^{-1}\left\\{\frac{1}{s^{2}}-\frac{e^{-1}}{s^{2}}\right\\}\)
Short Answer
Expert verified
The solution is \( f(t) = t - u(t-1)(t-1) \).
Step by step solution
01
Identify the problem
We need to find the inverse Laplace transform of the given function: \( f(t) = \mathscr{L}^{-1}\left\{\frac{1}{s^2} - \frac{e^{-1}}{s^2}\right\} \).
02
Apply Inverse Laplace Transform to Each Term Separately
First, consider each term separately: \( \mathscr{L}^{-1}\left\{\frac{1}{s^2}\right\} \) and \( \mathscr{L}^{-1}\left\{\frac{e^{-1}}{s^2}\right\} \). The Laplace transform \( \frac{1}{s^2} \) corresponds to the function \( t \) in the time domain.
03
Apply the Shifting Theorem
For the term \( \frac{e^{-1}}{s^2} \), recognize that this indicates a time shift. Recall that \( \mathscr{L}^{-1}\left\{ e^{-as}F(s) \right\} = u(t-a)f(t-a) \). Here, \( a = 1 \) and \( F(s) = \frac{1}{s^2} \), so it's transformed into a shifted function, \( u(t-1)(t-1) \), where \( u(t-1) \) is the unit step function.
04
Combine Results
Combine the results of both inverse transforms. So, \( \mathscr{L}^{-1}\left\{ \frac{1}{s^2} \right\} = t \) and \( \mathscr{L}^{-1}\left\{ \frac{e^{-1}}{s^2} \right\} = u(t-1)(t-1) \). Thus, \( f(t) = t - u(t-1)(t-1) \).
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Laplace Transform
The Laplace Transform is a powerful mathematical tool used extensively in engineering and physics. It enables us to transform a function of time, typically denoted as \( f(t) \), into a function of a complex variable, \( s \). This transformation allows for the simplification of solving differential equations by converting them into algebraic equations. The Laplace Transform is defined as:
- \( \mathscr{L}\{f(t)\} = F(s) = \int_{0}^{\infty} e^{-st} f(t) \ dt \)
Shifting Theorem
The Shifting Theorem is an essential concept when working with Laplace Transforms, providing a mechanism to understand how modifications in the time domain correspond to changes in the \( s \)-domain. This theorem deals with time shifting and is expressed as:
- If \( F(s) = \mathscr{L}\{f(t)\} \), then \( \mathscr{L}\{f(t-a)u(t-a)\} = e^{-as}F(s) \).
Unit Step Function
The Unit Step Function, often denoted as \( u(t-a) \), is a fundamental concept in the analysis of dynamic systems and control theory. The Unit Step Function is defined as:
- \( u(t-a) = \begin{cases} 0, & \text{if } t < a \ 1, & \text{if } t \geq a \end{cases} \)