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Solve the given differential equation subject to the indicated initial conditions. $$ \frac{d^{2} x}{d t^{2}}+\omega^{2} x=F_{0} \cos \gamma t, \quad x(0)=0, x^{\prime}(0)=0 $$

Short Answer

Expert verified
\( x(t) = \frac{-F_0}{\omega^2 - \gamma^2} (\cos(\omega t) - \cos(\gamma t)) \).

Step by step solution

01

Identify the Type of Differential Equation

The given differential equation is \( \frac{d^2 x}{dt^2} + \omega^2 x = F_0 \cos \gamma t \). This is a second order non-homogeneous linear differential equation.
02

Solve the Homogeneous Equation

The homogeneous version of the differential equation is \( \frac{d^2 x}{dt^2} + \omega^2 x = 0 \). The characteristic equation is \( r^2 + \omega^2 = 0 \), giving roots \( r = \pm i\omega \). Thus, the general solution to the homogeneous equation is \( x_h(t) = C_1 \cos(\omega t) + C_2 \sin(\omega t) \).
03

Solve the Particular Solution

To find a particular solution \( x_p(t) \) for the non-homogeneous equation, we use the method of undetermined coefficients. Assume \( x_p(t) = A \cos(\gamma t) + B \sin(\gamma t) \). Substitute \( x_p(t) \) into the differential equation and solve for \( A \) and \( B \).
04

Determine Coefficients for Particular Solution

Taking derivatives, \( x_p'(t) = -A\gamma \sin(\gamma t) + B\gamma \cos(\gamma t) \) and \( x_p''(t) = -A\gamma^2 \cos(\gamma t) - B\gamma^2 \sin(\gamma t) \). Substitute into the differential equation: \( -A \gamma^2 \cos(\gamma t) - B \gamma^2 \sin(\gamma t) + \omega^2(A \cos(\gamma t) + B \sin(\gamma t)) = F_0 \cos(\gamma t) \). Simplifying, matching coefficients yields \( A = \frac{F_0}{\omega^2 - \gamma^2} \) and \( B = 0 \). Thus, \( x_p(t) = \frac{F_0}{\omega^2 - \gamma^2} \cos(\gamma t) \).
05

Form the General Solution

Combine the homogeneous and particular solutions: \( x(t) = C_1 \cos(\omega t) + C_2 \sin(\omega t) + \frac{F_0}{\omega^2 - \gamma^2} \cos(\gamma t) \).
06

Apply Initial Conditions

Use the initial conditions \( x(0) = 0 \) and \( x'(0) = 0 \) to solve for \( C_1 \) and \( C_2 \). Substitute \( t=0 \) into the general solution: \(0 = C_1 + \frac{F_0}{\omega^2 - \gamma^2}\) implies \(C_1 = -\frac{F_0}{\omega^2 - \gamma^2}\).Differentiate \( x(t) \) and substitute \( t=0 \): \(0 = \omega C_2\), which gives \(C_2 = 0\).
07

Write the Solution

Substitute \( C_1 \) and \( C_2 \) back into the general solution: \( x(t) = -\frac{F_0}{\omega^2 - \gamma^2} \cos(\omega t) + \frac{F_0}{\omega^2 - \gamma^2} \cos(\gamma t) \). This is the specific solution of the differential equation subject to the given initial conditions.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Second Order Differential Equations
A second order differential equation contains the second derivative of a function as its highest derivative and is often encountered in many fields, such as physics and engineering. These equations provide a way to describe systems with dynamics that involve acceleration, like mass-spring systems or electrical circuits. In our exercise, the equation is \[ \frac{d^{2} x}{d t^{2}} + \omega^{2} x = F_{0} \cos \gamma t \]This represents a linear second order differential equation due to the appearance of the second derivative \( \frac{d^{2} x}{d t^{2}} \). Another important feature of this equation is that it includes a sine or cosine function as a driving force, which requires specific techniques for its solution. The nature of second order differential equations allows for a variety of solutions depending on the initial conditions and whether the equation is homogeneous or non-homogeneous.
Non-homogeneous Equations
Differential equations fall into two categories: homogeneous and non-homogeneous. A homogeneous equation does not have any terms without the function or its derivatives, such as constants or specific functions like sine or cosine. Our equation, \( \frac{d^{2} x}{d t^{2}} + \omega^{2} x = F_{0} \cos \gamma t \), is non-homogeneous because of the term \( F_{0} \cos \gamma t \). This term represents an external force acting on the system, often referred to as a driving force. Solving non-homogeneous equations typically involves:
  • Finding the general solution of the corresponding homogeneous equation.
  • Finding a particular solution that includes the non-homogeneous term.
  • Combining both solutions to write the overall solution for the equation.
The presence of the additional term \( F_{0} \cos \gamma t \) necessitates methods like the Method of Undetermined Coefficients.
Method of Undetermined Coefficients
The Method of Undetermined Coefficients is a strategic technique used for finding particular solutions of non-homogeneous linear differential equations. It works particularly well when the non-homogeneous part is a simple function like a polynomial, exponential, sine, or cosine.For our problem, we assume a particular solution of the form \( x_p(t) = A \cos(\gamma t) + B \sin(\gamma t) \) because the non-homogeneous term is \( F_0 \cos \gamma t \). To find \( A \) and \( B \), you substitute \( x_p(t) \) and its derivatives back into the original equation:\[ -A \gamma^2 \cos(\gamma t) - B \gamma^2 \sin(\gamma t) + \omega^2(A \cos(\gamma t) + B \sin(\gamma t)) = F_0 \cos(\gamma t) \]By aligning coefficients on both sides of the equation, you solve for \( A \) and \( B \). In our case:
  • \( A = \frac{F_0}{\omega^2 - \gamma^2} \)
  • \( B = 0 \)
Thus, we found our particular solution \( x_p(t) = \frac{F_0}{\omega^2 - \gamma^2} \cos(\gamma t) \). This technique harnesses simplicity by making educated guesses based on the form of the non-homogeneous term.
Initial Value Problems
Initial value problems involve solving differential equations with given initial conditions, which specify the state of the system at a particular point. These conditions are vital as they make the solution specific to a problem, allowing for the determination of constant coefficients in the general solution.In our exercise, we have the initial conditions:
  • \( x(0) = 0 \)
  • \( x'(0) = 0 \)
The goal is to solve the differential equation such that the result satisfies these initial conditions. By applying these conditions to the general solution:\[ x(t) = C_1 \cos(\omega t) + C_2 \sin(\omega t) + \frac{F_0}{\omega^2 - \gamma^2} \cos(\gamma t) \]We determine the constants \( C_1 \) and \( C_2 \). Specifically, solving with \( t = 0 \) plugs directly into the equation and provides specific values for these constants:
  • \( C_1 = -\frac{F_0}{\omega^2 - \gamma^2} \)
  • \( C_2 = 0 \)
Once the constants are determined, you finalize the solution to match the initial conditions, delivering a unique solution for the specific problem.

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